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TypeScript quickFix.getCodeActions函数代码示例

本文整理汇总了TypeScript中vs/editor/contrib/quickFix/quickFix.getCodeActions函数的典型用法代码示例。如果您正苦于以下问题:TypeScript getCodeActions函数的具体用法?TypeScript getCodeActions怎么用?TypeScript getCodeActions使用的例子?那么, 这里精选的函数代码示例或许可以为您提供帮助。


在下文中一共展示了getCodeActions函数的4个代码示例,这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞,您的评价将有助于系统推荐出更棒的TypeScript代码示例。

示例1: test

	test('getCodeActions should filter by scope', async function () {
		const provider = new class implements CodeActionProvider {
			provideCodeActions(): CodeAction[] {
				return [
					{ title: 'a', kind: 'a' },
					{ title: 'b', kind: 'b' },
					{ title: 'a.b', kind: 'a.b' }
				];
			}
		};

		disposables.push(CodeActionProviderRegistry.register('fooLang', provider));

		{
			const actions = await getCodeActions(model, new Range(1, 1, 2, 1), new CodeActionKind('a'));
			assert.equal(actions.length, 2);
			assert.strictEqual(actions[0].title, 'a');
			assert.strictEqual(actions[1].title, 'a.b');
		}

		{
			const actions = await getCodeActions(model, new Range(1, 1, 2, 1), new CodeActionKind('a.b'));
			assert.equal(actions.length, 1);
			assert.strictEqual(actions[0].title, 'a.b');
		}

		{
			const actions = await getCodeActions(model, new Range(1, 1, 2, 1), new CodeActionKind('a.b.c'));
			assert.equal(actions.length, 0);
		}
	});
开发者ID:JarnoNijboer,项目名称:vscode,代码行数:31,代码来源:quickFix.test.ts

示例2: test

	test('CodeActions are sorted by type, #38623', async function () {

		const provider = new class implements CodeActionProvider {
			provideCodeActions() {
				return [
					testData.command.abc,
					testData.diagnostics.bcd,
					testData.spelling.bcd,
					testData.tsLint.bcd,
					testData.tsLint.abc,
					testData.diagnostics.abc
				];
			}
		};

		disposables.push(CodeActionProviderRegistry.register('fooLang', provider));

		const expected = [
			// CodeActions with a diagnostics array are shown first ordered by diagnostics.message
			testData.diagnostics.abc,
			testData.diagnostics.bcd,

			// CodeActions without diagnostics are shown in the given order without any further sorting
			testData.command.abc,
			testData.spelling.bcd, // empty diagnostics array
			testData.tsLint.bcd,
			testData.tsLint.abc
		];

		const actions = await getCodeActions(model, new Range(1, 1, 2, 1));
		assert.equal(actions.length, 6);
		assert.deepEqual(actions, expected);
	});
开发者ID:servicesgpr,项目名称:vscode,代码行数:33,代码来源:quickFix.test.ts

示例3: test

	test('basics', async function () {

		const provider = new class implements CodeActionProvider {
			provideCodeActions() {
				return [{
					title: 'Testing1',
					diagnostics: [{
						startLineNumber: 1,
						startColumn: 1,
						endLineNumber: 2,
						endColumn: 1,
						severity: Severity.Error,
						message: 'some error'
					}]
				}, {
					title: 'Testing2'
				}];
			}
		};

		disposables.push(CodeActionProviderRegistry.register('fooLang', provider));

		const actions = await getCodeActions(model, new Range(1, 1, 2, 1));
		assert.equal(actions.length, 2);
	});
开发者ID:AlexxNica,项目名称:sqlopsstudio,代码行数:25,代码来源:quickFix.test.ts

示例4: test

	test('getCodeActions should not return source code action by default', async function () {
		const provider = new class implements CodeActionProvider {
			provideCodeActions(): CodeAction[] {
				return [
					{ title: 'a', kind: CodeActionKind.Source.value },
					{ title: 'b', kind: 'b' }
				];
			}
		};

		disposables.push(CodeActionProviderRegistry.register('fooLang', provider));

		{
			const actions = await getCodeActions(model, new Range(1, 1, 2, 1), {});
			assert.equal(actions.length, 1);
			assert.strictEqual(actions[0].title, 'b');
		}

		{
			const actions = await getCodeActions(model, new Range(1, 1, 2, 1), { kind: CodeActionKind.Source, includeSourceActions: true });
			assert.equal(actions.length, 1);
			assert.strictEqual(actions[0].title, 'a');
		}
	});
开发者ID:costincaraivan,项目名称:vscode,代码行数:24,代码来源:quickFix.test.ts


注:本文中的vs/editor/contrib/quickFix/quickFix.getCodeActions函数示例由纯净天空整理自Github/MSDocs等开源代码及文档管理平台,相关代码片段筛选自各路编程大神贡献的开源项目,源码版权归原作者所有,传播和使用请参考对应项目的License;未经允许,请勿转载。