本文整理汇总了TypeScript中vs/base/common/extpath.isRootOrDriveLetter函数的典型用法代码示例。如果您正苦于以下问题：TypeScript isRootOrDriveLetter函数的具体用法？TypeScript isRootOrDriveLetter怎么用？TypeScript isRootOrDriveLetter使用的例子？那么恭喜您, 这里精选的函数代码示例或许可以为您提供帮助。
在下文中一共展示了isRootOrDriveLetter函数的3个代码示例，这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞，您的评价将有助于系统推荐出更棒的TypeScript代码示例。
示例1: test
test('isRoot', () => {
if (platform.isWindows) {
assert.ok(extpath.isRootOrDriveLetter('c:'));
assert.ok(extpath.isRootOrDriveLetter('D:'));
assert.ok(extpath.isRootOrDriveLetter('D:/'));
assert.ok(extpath.isRootOrDriveLetter('D:\\'));
assert.ok(!extpath.isRootOrDriveLetter('D:\\path'));
assert.ok(!extpath.isRootOrDriveLetter('D:/path'));
} else {
assert.ok(extpath.isRootOrDriveLetter('/'));
assert.ok(!extpath.isRootOrDriveLetter('/path'));
}
});示例2: rimraf
export async function rimraf(path: string, mode = RimRafMode.UNLINK): Promise<void> {
if (isRootOrDriveLetter(path)) {
throw new Error('rimraf - will refuse to recursively delete root');
}
// delete: via unlink
if (mode === RimRafMode.UNLINK) {
return rimrafUnlink(path);
}
// delete: via move
return rimrafMove(path);
}示例3: rimrafSync
export function rimrafSync(path: string): void {
if (isRootOrDriveLetter(path)) {
throw new Error('rimraf - will refuse to recursively delete root');
}
try {
const stat = fs.lstatSync(path);
// Folder delete (recursive) - NOT for symbolic links though!
if (stat.isDirectory() && !stat.isSymbolicLink()) {
// Children
const children = readdirSync(path);
children.map(child => rimrafSync(join(path, child)));
// Folder
fs.rmdirSync(path);
}
// Single file delete
else {
// chmod as needed to allow for unlink
const mode = stat.mode;
if (!(mode & 128)) { // 128 === 0200
fs.chmodSync(path, mode | 128);
}
return fs.unlinkSync(path);
}
} catch (error) {
if (error.code !== 'ENOENT') {
throw error;
}
}
}