本文整理汇总了TypeScript中src/monet.IO函数的典型用法代码示例。如果您正苦于以下问题：TypeScript IO函数的具体用法？TypeScript IO怎么用？TypeScript IO使用的例子？那么, 这里精选的函数代码示例或许可以为您提供帮助。
在下文中一共展示了IO函数的5个代码示例，这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞，您的评价将有助于系统推荐出更棒的TypeScript代码示例。
示例1: log2
function log2(message: Maybe<string>): IO<void> {
return message.fold(IO(() => {
console.warn('Nothing to log.')
}))(msg => IO(() => {
console.log(msg);
}));
}示例2: IO
}), msg => IO(() => {
console.log(msg);
}));示例3: IO
const oneChar: IO<string> = IO.pure(() => IO(() => '1')).join<string>();示例4: IO
return message.cata(err => IO(() => {
console.error(err);
}), msg => IO(() => {示例5: List
.takeLeft(List.of(true, Nil))
.takeRight(List.unit(['a', 'b', 'c']))
.map(List.fromArray);
const y: List<List<string>> = x.join<string>()
.flatMap(s => List.pure(`Value: ${s}`).cons(s))
.tails();
const z: List<string> = y.flatten<string>()
.reverse().snoc('EhhâŚ')
.concat(List<string>())
.append(List('WOW!'));
const a: number = z.tails().foldLeft(0)((acc, t) => acc + t.size());
const b: List<Maybe<number>> = x.foldRight(z)((l, acc) => acc.append(l))
.ap(List(Number, List(e => parseInt(e, 10))))
.headMaybe().map(h => List(h)).orJust(List(0))
.tails().map(t => t.filter(n => !isNaN(n)))
.map(t => t.size() > 0 ? Some(t.head()) : None<number>());
const c: List<number> = b.flattenMaybe<number>().chain(n => y.bind(ls => ls).map(s => Number(s) + n));
const maybeList: Maybe<List<string>> = List(Some('A')).sequenceMaybe<string>();
const eitherList: Either<string, List<string>> = List(Right('A')).sequenceEither<string, string>();
const successOfList: Validation<List<string>, List<string>> = List(Success('A')).sequenceValidation<string, string>();
const ioOfList: IO<List<string>> = List(IO(() =>'A')).sequenceIO<string>();
const readerOfList: Reader<string, List<string>> = List(Reader(x => x + 'A')).sequenceReader<string, string>();
const maybeList2: Maybe<List<string>> = List(Some('A')).sequence<string>(Maybe);
const eitherList2: Either<string, List<string>> = List(Right('A')).sequence<string, string>(Either);
const successOfList2: Validation<List<string>, List<string>> = List(Success('A')).sequence<string, string>(Validation);
const ioOfList2: IO<List<string>> = List(IO(() =>'A')).sequence<string>(IO);
const readerOfList2: Reader<string, List<string>> = List(Reader(x => x + 'A')).sequence<string, string>(Reader);