本文整理汇总了TypeScript中rxjs/operator/withLatestFrom.withLatestFrom.call方法的典型用法代码示例。如果您正苦于以下问题:TypeScript withLatestFrom.call方法的具体用法?TypeScript withLatestFrom.call怎么用?TypeScript withLatestFrom.call使用的例子?那么恭喜您, 这里精选的方法代码示例或许可以为您提供帮助。您也可以进一步了解该方法所在类rxjs/operator/withLatestFrom.withLatestFrom
的用法示例。
在下文中一共展示了withLatestFrom.call方法的4个代码示例,这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞,您的评价将有助于系统推荐出更棒的TypeScript代码示例。
示例1: listenForStoreChanges
export function listenForStoreChanges(router: Router, store: Store<any>) {
const storeAndRouter$ = withLatestFrom.call(selectRouter(store), getLatestUrl(router));
const mismatch$ = filter.call(storeAndRouter$, ([ rs, url ]) => rs.path !== url);
const newPath$ = map.call(mismatch$, ([ rs ]) => rs.path);
newPath$.subscribe(url => router.navigateByUrl(url));
}
示例2: constructor
constructor(actions$: Dispatcher, state$: State<S>) {
super(1);
withLatestFrom
.call(actions$, state$)
.subscribe(([ action, state ]) => {
super.next({ action, state });
});
}
示例3: connectRouterActions
export function connectRouterActions(router: Router, store: Store<any>) {
const routerAndStore$ = withLatestFrom.call(getLatestUrl(router), selectRouter(store));
const mismatchUrl$ = filter.call(routerAndStore$, ([ url, rs ]) => (rs && rs.path !== url || !rs));
const updateLocation$ = map.call(mismatchUrl$, ([ path ]) => {
return { type: routerActions.UPDATE_LOCATION, payload: { path }};
});
updateLocation$.subscribe(store);
}
示例4: constructor
constructor(_initialState: T, action$: Dispatcher, reducer$: Reducer) {
super(_initialState);
const actionInQueue$ = observeOn.call(action$, queue);
const actionAndReducer$ = withLatestFrom.call(actionInQueue$, reducer$);
const state$ = scan.call(actionAndReducer$, (state, [ action, reducer ]) => {
return reducer(state, action);
}, _initialState);
state$.subscribe(value => this.next(value));
}