本文整理汇总了TypeScript中property-resolver.PropertyResolver.decomposePropertyRoute方法的典型用法代码示例。如果您正苦于以下问题：TypeScript PropertyResolver.decomposePropertyRoute方法的具体用法？TypeScript PropertyResolver.decomposePropertyRoute怎么用？TypeScript PropertyResolver.decomposePropertyRoute使用的例子？那么, 这里精选的方法代码示例或许可以为您提供帮助。您也可以进一步了解该方法所在类property-resolver.PropertyResolver的用法示例。
在下文中一共展示了PropertyResolver.decomposePropertyRoute方法的1个代码示例，这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞，您的评价将有助于系统推荐出更棒的TypeScript代码示例。
示例1: it
it('should correctly resolve a property route to a rule', function () {
var rulesetBuilder = new RulesetBuilder();
var nestedRuleset = rulesetBuilder.create()
.forProperty("bar")
.addRule("required", true)
.addRule("maxLength", 10)
.build();
var ruleset = rulesetBuilder.create()
.forProperty("foo")
.addRuleset(nestedRuleset)
.build();
var propertyRoute = "foo.bar";
var ruleResolver = new RuleResolver();
var locatedRules = ruleResolver.resolvePropertyRules(propertyResolver.decomposePropertyRoute(propertyRoute), ruleset);
expect(locatedRules).not.to.be.null;
expect(locatedRules.length).to.equal(2);
expect(locatedRules[0].ruleName).to.equal("required");
expect(locatedRules[0].ruleOptions).to.be.true;
expect(locatedRules[1].ruleName).to.equal("maxLength");
expect(locatedRules[1].ruleOptions).to.equal(10);
});