本文整理汇总了TypeScript中mithril/stream.combine函数的典型用法代码示例。如果您正苦于以下问题：TypeScript combine函数的具体用法？TypeScript combine怎么用？TypeScript combine使用的例子？那么, 这里精选的函数代码示例或许可以为您提供帮助。
在下文中一共展示了combine函数的3个代码示例，这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞，您的评价将有助于系统推荐出更棒的TypeScript代码示例。
示例1: stream
}
{
const s: Stream<number | undefined> = stream(1);
s(undefined);
console.assert(s() === undefined);
}
{
const s = stream(stream(1));
console.assert(s()() === 1);
}
{
const s = stream();
const doubled = stream.combine(s => s() * 2, [s]);
s(2);
console.assert(doubled() === 4);
}
{
const s = stream(2);
const doubled = stream.combine(s => s() * 2, [s]);
console.assert(doubled() === 4);
}
{
const s1 = stream();
const s2 = stream();
const added = stream.combine((s1, s2) => s1() + s2(), [s1, s2]);
s1(2);示例2: stream
halted.map(() => {
// never runs
});
}
////////////////////////////////////////////////////////////////////////////////
// http://mithril.js.org/stream.html#combining-streams
////////////////////////////////////////////////////////////////////////////////
{
const a = stream(5);
const b = stream(7);
const added = stream.combine((a: stream.Stream<number>, b: stream.Stream<number>) => {
return a() + b();
}, [a, b]);
console.log(added()); // logs 12
}
////////////////////////////////////////////////////////////////////////////////
// http://mithril.js.org/stream.html#ended-state
////////////////////////////////////////////////////////////////////////////////
{
const value = stream<number>();
const doubled = value.map(value => value * 2);
value.end(true); // set to ended state
示例3: stream
}
{
const s: Stream<number | undefined> = stream(1)
s(undefined)
console.assert(s() === undefined)
}
{
const s = stream(stream(1))
console.assert(s()() === 1)
}
{
const s = stream()
const doubled = stream.combine(function(s) {return s() * 2}, [s])
s(2)
console.assert(doubled() === 4)
}
{
const s = stream(2)
const doubled = stream.combine(function(s) {return s() * 2}, [s])
console.assert(doubled() === 4)
}
{
const s1 = stream()
const s2 = stream()
const added = stream.combine(function(s1, s2) {return s1() + s2()}, [s1, s2])
s1(2)