本文整理汇总了TypeScript中Immutable.List.isEmpty方法的典型用法代码示例。如果您正苦于以下问题：TypeScript List.isEmpty方法的具体用法？TypeScript List.isEmpty怎么用？TypeScript List.isEmpty使用的例子？那么, 这里精选的方法代码示例或许可以为您提供帮助。您也可以进一步了解该方法所在类Immutable.List的用法示例。
在下文中一共展示了List.isEmpty方法的3个代码示例，这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞，您的评价将有助于系统推荐出更棒的TypeScript代码示例。
示例1: getStageNameList
function getStageNameList(stageList: List<StageConfig | RawStageConfig>) {
if (stageList.isEmpty()) {
return 'empty'
} else {
return stageList.map(s => s.name).join(',')
}
}示例2: removeCounter
function removeCounter(state: List<number>, action: RemoveCounterAction): List<number> {
if(state.isEmpty()) {
throw "no counters"
}
if(action.index >= state.size) {
throw "index out of bounds"
}
if(action.index < 0) {
throw "index out of bounds"
}
return state.remove(action.index)
}示例3: Some
.reduce((accumulator: List<[string, List<GitHubCommit>]>, currentCommit: GitHubCommit, currentIndex: number): List<[string, List<GitHubCommit>]> => {
const isNotEmpty: boolean = ! accumulator.isEmpty();
const previousGroup = accumulator.last();
const maybePreviousAuthorName: Option<string> = isNotEmpty ? headOption(previousGroup) : None;
return maybePreviousAuthorName
.flatMap(previousAuthorName => {
if (previousAuthorName === currentCommit.authorName) {
const currentCommitsByAuthor = previousGroup[1];
const index = accumulator.indexOf(previousGroup);
return new Some(accumulator.set(index, [ previousAuthorName, currentCommitsByAuthor.push(currentCommit) ]))
} else {
return None;
}
})
.getOrElse(() => accumulator.push([ currentCommit.authorName, List([ currentCommit ]) ]))
}, List<[string, List<GitHubCommit>]>())