本文整理汇总了TypeScript中d3-array.merge函数的典型用法代码示例。如果您正苦于以下问题：TypeScript merge函数的具体用法？TypeScript merge怎么用？TypeScript merge使用的例子？那么, 这里精选的函数代码示例或许可以为您提供帮助。
在下文中一共展示了merge函数的2个代码示例，这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞，您的评价将有助于系统推荐出更棒的TypeScript代码示例。
示例1: MixedObject
];
const testArray2 = [
new MixedObject(40, new Date(2016, 3, 1)),
new MixedObject(50, new Date(2016, 9, 30)),
];
let testArrays: MixedObject[][] = [testArray1, testArray2];
const readonlyTestArray1 = testArray1 as ReadonlyArray<MixedObject>;
const readonlyTestArray2 = testArray2 as ReadonlyArray<MixedObject>;
const readonlyTestArrays = [testArray1, testArray2] as ReadonlyArray<ReadonlyArray<MixedObject>>;
let mergedArray: MixedObject[];
mergedArray = d3Array.merge(testArrays); // inferred type
mergedArray = d3Array.merge<MixedObject>(testArrays); // explicit type
// $ExpectError
mergedArray = d3Array.merge<MixedObject>([[10, 40, 30], [15, 30]]); // fails, type mismatch
// $ExpectError
mergedArray = d3Array.merge([testArray1, [15, 30]]); // fails, type mismatch
mergedArray = d3Array.merge(readonlyTestArrays); // inferred type
mergedArray = d3Array.merge<MixedObject>(readonlyTestArrays); // explicit type
// cross() ---------------------------------------------------------------------
let crossed: Array<[string, number]>;
const chars = ['x', 'y'];
const nums = [1, 2];示例2: MixedObject
[
new MixedObject(10, new Date(2016, 6, 1)),
new MixedObject(20, new Date(2016, 7, 30)),
new MixedObject(30, new Date(2015, 3, 15)),
new MixedObject(40, new Date(2014, 3, 15)),
new MixedObject(50, new Date(2017, 4, 15))
],
[
new MixedObject(40, new Date(2016, 3, 1)),
new MixedObject(50, new Date(2016, 9, 30)),
]
];
let mergedArray: MixedObject[];
mergedArray = d3Array.merge(testArrays); // inferred type
mergedArray = d3Array.merge<MixedObject>(testArrays); // explicit type
// mergedArray = d3Array.merge<MixedObject>([[10, 40, 30], [15, 30]]); // fails, type mismatch
// cross() ---------------------------------------------------------------------
let crossed: Array<[string, number]>;
crossed = d3Array.cross(['x', 'y'], [1, 2]);
crossed = d3Array.cross<string, number>(['x', 'y'], [1, 2]);
let strArray: string[] = d3Array.cross<number, number, string>([2, 3], [5, 6], (a, b) => (a + b) + 'px');
strArray = d3Array.cross([2, 3], [5, 6], (a, b) => {
let aa: number = a;
let bb: number = b;
return (aa + bb) + 'px';