本文整理汇总了TypeScript中d3-array.bisectLeft函数的典型用法代码示例。如果您正苦于以下问题：TypeScript bisectLeft函数的具体用法？TypeScript bisectLeft怎么用？TypeScript bisectLeft使用的例子？那么, 这里精选的函数代码示例或许可以为您提供帮助。
在下文中一共展示了bisectLeft函数的2个代码示例，这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞，您的评价将有助于系统推荐出更棒的TypeScript代码示例。
示例1: Date
numOrUndefined = d3Array.scan(mixedObjectOrUndefinedArray, (a, b) => {
const aElem: MixedObject | undefined = a;
const bElem: MixedObject | undefined = b;
return a && b ? a.num - b.num : NaN;
});
numOrUndefined = d3Array.scan(readonlyMixedObjectOrUndefinedArray, (a, b) => {
const aElem: MixedObject | undefined = a;
const bElem: MixedObject | undefined = b;
return a && b ? a.num - b.num : NaN;
});
// bisectLeft() ----------------------------------------------------------------
num = d3Array.bisectLeft(numbersArray, 4);
num = d3Array.bisectLeft(numbersArray, 4, 1);
num = d3Array.bisectLeft(numbersArray, 4, 1, 4);
num = d3Array.bisectLeft(stringyNumbersArray, '21');
num = d3Array.bisectLeft(stringyNumbersArray, '21', 1);
num = d3Array.bisectLeft(stringyNumbersArray, '21', 1, 4);
num = d3Array.bisectLeft(dateArray, new Date(2011, 2, 1));
num = d3Array.bisectLeft(dateArray, new Date(2011, 2, 1), 1);
num = d3Array.bisectLeft(dateArray, new Date(2011, 2, 1), 1, 2);
num = d3Array.bisectLeft(typedArray, 4);
num = d3Array.bisectLeft(typedArray, 4, 1);
num = d3Array.bisectLeft(typedArray, 4, 1, 4);
示例2: Date
numOrUndefined = d3Array.scan(mixedObjectArray, (a, b) => {
const aElem: MixedObject = a;
const bElem: MixedObject = b;
return a.num - b.num;
});
numOrUndefined = d3Array.scan(mixedObjectOrUndefinedArray, (a, b) => {
const aElem: MixedObject | undefined = a;
const bElem: MixedObject | undefined = b;
return a && b ? a.num - b.num : NaN;
});
// bisectLeft() ----------------------------------------------------------------
num = d3Array.bisectLeft([0, 2, 3, 4, 7, 8], 4);
num = d3Array.bisectLeft([0, 2, 3, 4, 7, 8], 4, 1);
num = d3Array.bisectLeft([0, 2, 3, 4, 7, 8], 4, 1, 4);
num = d3Array.bisectLeft(['0', '2', '3', '4', '7', '8'], '21');
num = d3Array.bisectLeft(['0', '2', '3', '4', '7', '8'], '21', 1);
num = d3Array.bisectLeft(['0', '2', '3', '4', '7', '8'], '21', 1, 4);
num = d3Array.bisectLeft([new Date(2010, 1, 1), new Date(2011, 1, 1), new Date(2012, 1, 1), new Date(2013, 1, 1)], new Date(2011, 2, 1));
num = d3Array.bisectLeft([new Date(2010, 1, 1), new Date(2011, 1, 1), new Date(2012, 1, 1), new Date(2013, 1, 1)], new Date(2011, 2, 1), 1);
num = d3Array.bisectLeft([new Date(2010, 1, 1), new Date(2011, 1, 1), new Date(2012, 1, 1), new Date(2013, 1, 1)], new Date(2011, 2, 1), 1, 2);
// bisectRight() ---------------------------------------------------------------
num = d3Array.bisectRight([0, 2, 3, 4, 7, 8], 4);
num = d3Array.bisectRight([0, 2, 3, 4, 7, 8], 4, 1);