本文整理汇总了TypeScript中d3-array.bisect函数的典型用法代码示例。如果您正苦于以下问题：TypeScript bisect函数的具体用法？TypeScript bisect怎么用？TypeScript bisect使用的例子？那么恭喜您, 这里精选的函数代码示例或许可以为您提供帮助。
在下文中一共展示了bisect函数的2个代码示例，这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞，您的评价将有助于系统推荐出更棒的TypeScript代码示例。
示例1: Date
num = d3Array.bisectRight(readonlyNumbersArray, 4);
num = d3Array.bisectRight(readonlyNumbersArray, 4, 1);
num = d3Array.bisectRight(readonlyNumbersArray, 4, 1, 4);
num = d3Array.bisectRight(readonlyStringyNumbersArray, '21');
num = d3Array.bisectRight(readonlyStringyNumbersArray, '21', 1);
num = d3Array.bisectRight(readonlyStringyNumbersArray, '21', 1, 4);
num = d3Array.bisectRight(readonlyDateArray, new Date(2011, 2, 1));
num = d3Array.bisectRight(readonlyDateArray, new Date(2011, 2, 1), 1);
num = d3Array.bisectRight(readonlyDateArray, new Date(2011, 2, 1), 1, 2);
// bisect() --------------------------------------------------------------------
num = d3Array.bisect(numbersArray, 4);
num = d3Array.bisect(numbersArray, 4, 1);
num = d3Array.bisect(numbersArray, 4, 1, 4);
num = d3Array.bisect(stringyNumbersArray, '21');
num = d3Array.bisect(stringyNumbersArray, '21', 1);
num = d3Array.bisect(stringyNumbersArray, '21', 1, 4);
num = d3Array.bisect(dateArray, new Date(2011, 2, 1));
num = d3Array.bisect(dateArray, new Date(2011, 2, 1), 1);
num = d3Array.bisect(dateArray, new Date(2011, 2, 1), 1, 2);
num = d3Array.bisect(typedArray, 4);
num = d3Array.bisect(typedArray, 4, 1);
num = d3Array.bisect(typedArray, 4, 1, 4);
示例2: Date
num = d3Array.bisectRight([0, 2, 3, 4, 7, 8], 4);
num = d3Array.bisectRight([0, 2, 3, 4, 7, 8], 4, 1);
num = d3Array.bisectRight([0, 2, 3, 4, 7, 8], 4, 1, 4);
num = d3Array.bisectRight(['0', '2', '3', '4', '7', '8'], '21');
num = d3Array.bisectRight(['0', '2', '3', '4', '7', '8'], '21', 1);
num = d3Array.bisectRight(['0', '2', '3', '4', '7', '8'], '21', 1, 4);
num = d3Array.bisectRight([new Date(2010, 1, 1), new Date(2011, 1, 1), new Date(2012, 1, 1), new Date(2013, 1, 1)], new Date(2011, 2, 1));
num = d3Array.bisectRight([new Date(2010, 1, 1), new Date(2011, 1, 1), new Date(2012, 1, 1), new Date(2013, 1, 1)], new Date(2011, 2, 1), 1);
num = d3Array.bisectRight([new Date(2010, 1, 1), new Date(2011, 1, 1), new Date(2012, 1, 1), new Date(2013, 1, 1)], new Date(2011, 2, 1), 1, 2);
// bisect() --------------------------------------------------------------------
num = d3Array.bisect([0, 2, 3, 4, 7, 8], 4);
num = d3Array.bisect([0, 2, 3, 4, 7, 8], 4, 1);
num = d3Array.bisect([0, 2, 3, 4, 7, 8], 4, 1, 4);
num = d3Array.bisect(['0', '2', '3', '4', '7', '8'], '21');
num = d3Array.bisect(['0', '2', '3', '4', '7', '8'], '21', 1);
num = d3Array.bisect(['0', '2', '3', '4', '7', '8'], '21', 1, 4);
num = d3Array.bisect([new Date(2010, 1, 1), new Date(2011, 1, 1), new Date(2012, 1, 1), new Date(2013, 1, 1)], new Date(2011, 2, 1));
num = d3Array.bisect([new Date(2010, 1, 1), new Date(2011, 1, 1), new Date(2012, 1, 1), new Date(2013, 1, 1)], new Date(2011, 2, 1), 1);
num = d3Array.bisect([new Date(2010, 1, 1), new Date(2011, 1, 1), new Date(2012, 1, 1), new Date(2013, 1, 1)], new Date(2011, 2, 1), 1, 2);
// bisector() ------------------------------------------------------------------
mixedObjectArray.sort((a, b) => a.date.valueOf() - b.date.valueOf());