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TypeScript search.service.SearchService类代码示例

本文整理汇总了TypeScript中core/search/search.service.SearchService的典型用法代码示例。如果您正苦于以下问题:TypeScript service.SearchService类的具体用法?TypeScript service.SearchService怎么用?TypeScript service.SearchService使用的例子?那么, 这里精选的类代码示例或许可以为您提供帮助。


在下文中一共展示了service.SearchService类的4个代码示例,这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞,您的评价将有助于系统推荐出更棒的TypeScript代码示例。

示例1: loadSecurityGroupsByApplicationName

  public loadSecurityGroupsByApplicationName(applicationName: string): IPromise<ISecurityGroup[]> {
    return SearchService.search<ISecurityGroupSearchResult>({
      q: applicationName,
      type: 'securityGroups',
      pageSize: 1000,
    }).then((searchResults: ISearchResults<ISecurityGroupSearchResult>) => {
      let result: ISecurityGroup[] = [];
      if (!searchResults || !searchResults.results) {
        this.$log.warn('WARNING: Gate firewall endpoint appears to be down.');
      } else {
        result = filter(searchResults.results, { application: applicationName });
      }

      return result;
    });
  }
开发者ID:mizzy,项目名称:deck,代码行数:16,代码来源:securityGroupReader.service.ts

示例2: listHealthChecks

 public listHealthChecks (type?: string): ng.IPromise<IGceHealthCheck[]> {
   if (type) {
     return this.listHealthChecks().then(healthChecks => healthChecks.filter(healthCheck => healthCheck.healthCheckType === type));
   } else {
     return this.searchService
       .search({q: '', type: 'healthChecks'}, this.infrastructureCaches.get('healthChecks'))
       .then((searchResults: ISearchResults<IHealthCheckSearchResults>) => {
         if (searchResults && searchResults.results) {
           const healthChecks = searchResults.results.filter(result => result.provider === 'gce')
             .map(result => {
               const healthCheck = JSON.parse(result.healthCheck) as IGceHealthCheck;
               healthCheck.account = result.account;
               return healthCheck;
             });
           return uniqWith(healthChecks, (checkA: IGceHealthCheck, checkB: IGceHealthCheck) => {
             return checkA.name === checkB.name && checkA.healthCheckType === checkB.healthCheckType &&
                 checkA.account === checkB.account;
           });
         } else {
           return [];
         }
       })
       .catch(() => []);
   }
 }
开发者ID:brujoand,项目名称:deck,代码行数:25,代码来源:healthCheck.read.service.ts

示例3: listCertificates

 public listCertificates(): IPromise<IGceCertificate[]> {
   return this.searchService
     .search<IGceCertificate>({q: '', type: 'sslCertificates'}, this.infrastructureCaches.get('certificates'))
     .then((searchResults: ISearchResults<IGceCertificate>) => {
       if (searchResults && searchResults.results) {
         return searchResults.results.filter(certificate => certificate.provider === 'gce');
       } else {
         return [];
       }
     })
     .catch(() => []);
 }
开发者ID:brujoand,项目名称:deck,代码行数:12,代码来源:certificate.reader.ts

示例4: listAddresses

 public listAddresses(region?: string): IPromise<IGceAddress[]> {
   if (region) {
     return this.listAddresses(null /* region */).then(addresses => addresses.filter(address => address.region === region));
   } else {
     return this.searchService
       .search<IAddressSearchResults>({q: '', type: 'addresses'}, this.infrastructureCaches.get('addresses'))
       .then((searchResults: ISearchResults<IAddressSearchResults>) => {
         if (searchResults && searchResults.results) {
           return searchResults.results
             .filter(result => result.provider === 'gce')
             .map(result => {
               const address = JSON.parse(result.address) as IGceAddress;
               address.account = result.account;
               address.region = result.region;
               return address;
             });
         } else {
           return [];
         }
       })
       .catch(() => []);
   }
 }
开发者ID:brujoand,项目名称:deck,代码行数:23,代码来源:address.reader.ts


注:本文中的core/search/search.service.SearchService类示例由纯净天空整理自Github/MSDocs等开源代码及文档管理平台,相关代码片段筛选自各路编程大神贡献的开源项目,源码版权归原作者所有,传播和使用请参考对应项目的License;未经允许,请勿转载。