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TypeScript js.BigNumber.lessThan方法代码示例

本文整理汇总了TypeScript中bignumber.js.BigNumber.lessThan方法的典型用法代码示例。如果您正苦于以下问题:TypeScript js.BigNumber.lessThan方法的具体用法?TypeScript js.BigNumber.lessThan怎么用?TypeScript js.BigNumber.lessThan使用的例子?那么恭喜您, 这里精选的方法代码示例或许可以为您提供帮助。您也可以进一步了解该方法所在bignumber.js.BigNumber的用法示例。


在下文中一共展示了js.BigNumber.lessThan方法的4个代码示例,这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞,您的评价将有助于系统推荐出更棒的TypeScript代码示例。

示例1: cssClass

 cssClass(): string {
   if (this.amount.greaterThan(0.0)) {
     return 'positive';
   } else if (this.amount.lessThan(0.0)) {
     return 'negative';
   } else {
     return 'zero';
   }
 }
开发者ID:gaborfeher,项目名称:grantmaster,代码行数:9,代码来源:FormattedAmount.ts

示例2: addSpentAmounts

 addSpentAmounts(local: BigNumber, foreign: BigNumber) {
   let that: ProjectCategory = this.merge({
     spentLocal: this.spentLocal.plus(local),
     spentForeign: this.spentForeign.plus(foreign)
   });
   let overshoot = this.limitForeign.lessThan(that.spentForeign);
   return that.merge({
     overshoot: overshoot
   });
 }
开发者ID:gaborfeher,项目名称:grantmaster,代码行数:10,代码来源:ProjectCategory.ts

示例3: addLastExpenseInternal

  addLastExpenseInternal(expense: Expense): Project {
    let that: Project = this;

    let fulfilledAmount = new BigNumber(0);
    let iteration = 0;
    while (fulfilledAmount.lessThan(expense.localAmount)) {
      iteration += 1;
      let pos = findFirstNonEmptyIncome(that.incomes);
      let income = that.incomes.get(pos);
      let neededValue = expense.localAmount.minus(fulfilledAmount);
      let valueToTake = neededValue;
      let availableValue = income.localAmount.minus(income.spentLocalAmount);
      if (pos < that.incomes.size - 1) {
        // If this is not the last possible income, then cap fulfillment amount
        // to this income.
        valueToTake = Utils.bigMin(neededValue, availableValue);
      } else if (availableValue.lessThan(neededValue)) {
        expense = expense.set('overshoot', true);
      }
      that = that.merge({
        incomes: that.incomes.set(pos, income.spendInLocalCurrency(valueToTake))
      });
      expense = expense.merge({
        foreignAmount:
          expense.foreignAmount.plus(valueToTake.dividedBy(income.exchangeRate)),
        multiPart: iteration > 1
      });
      fulfilledAmount = fulfilledAmount.plus(valueToTake);
    }

    let exchangeRate = expense.localAmount.dividedBy(expense.foreignAmount);
    return that.merge({
      expenses: that.expenses.push(
        expense.set('exchangeRate', exchangeRate)
      )
    });
  }
开发者ID:gaborfeher,项目名称:grantmaster,代码行数:37,代码来源:Project.ts

示例4: bigMin

 export function bigMin(a: BigNumber, b: BigNumber): BigNumber {
   return a.lessThan(b) ? a : b;
 }
开发者ID:gaborfeher,项目名称:grantmaster,代码行数:3,代码来源:Utils.ts


注:本文中的bignumber.js.BigNumber.lessThan方法示例由纯净天空整理自Github/MSDocs等开源代码及文档管理平台,相关代码片段筛选自各路编程大神贡献的开源项目,源码版权归原作者所有,传播和使用请参考对应项目的License;未经允许,请勿转载。