本文整理汇总了TypeScript中@nteract/types.makeDummyContentRecord函数的典型用法代码示例。如果您正苦于以下问题：TypeScript makeDummyContentRecord函数的具体用法？TypeScript makeDummyContentRecord怎么用？TypeScript makeDummyContentRecord使用的例子？那么, 这里精选的函数代码示例或许可以为您提供帮助。
在下文中一共展示了makeDummyContentRecord函数的2个代码示例，这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞，您的评价将有助于系统推荐出更棒的TypeScript代码示例。
示例1: createContentRef
(entry: any) => {
return [
createContentRef(),
makeDummyContentRecord({
mimetype: entry.mimetype,
// TODO: We can store the type of this content,
// it just doesn't have a model
// entry.type
assumedType: entry.type,
lastSaved: entry.last_modified,
filepath: entry.path
})
];
}示例2: switch
const byRef = (
state: Map<ContentRef, ContentRecord>,
action: Action
): Map<ContentRef, ContentRecord> => {
switch (action.type) {
case actionTypes.CHANGE_CONTENT_NAME:
const changeContentNameAction = action as actionTypes.ChangeContentName;
const { contentRef, filepath } = changeContentNameAction.payload;
return state.setIn([contentRef, "filepath"], filepath);
case actionTypes.CHANGE_CONTENT_NAME_FAILED:
return state;
case actionTypes.FETCH_CONTENT:
// TODO: we might be able to get around this by looking at the
// communication state first and not requesting this information until
// the communication state shows that it should exist.
const fetchContentAction = action as actionTypes.FetchContent;
return state.set(
fetchContentAction.payload.contentRef,
makeDummyContentRecord({
filepath: fetchContentAction.payload.filepath || "",
loading: true
// TODO: we can set kernelRef when the content record uses it.
})
);
case actionTypes.LAUNCH_KERNEL_SUCCESSFUL:
// TODO: is this reasonable? We launched the kernel on behalf of this
// content... so it makes sense to swap it, right?
const launchKernelAction = action as actionTypes.NewKernelAction;
return state.setIn(
[launchKernelAction.payload.contentRef, "model", "kernelRef"],
launchKernelAction.payload.kernelRef
);
case actionTypes.FETCH_CONTENT_FULFILLED:
const fetchContentFulfilledAction = action as actionTypes.FetchContentFulfilled;
switch (fetchContentFulfilledAction.payload.model.type) {
case "file":
return state.set(
fetchContentFulfilledAction.payload.contentRef,
makeFileContentRecord({
mimetype: fetchContentFulfilledAction.payload.model.mimetype,
created: fetchContentFulfilledAction.payload.model.created,
lastSaved:
fetchContentFulfilledAction.payload.model.last_modified,
filepath: fetchContentFulfilledAction.payload.filepath,
model: makeFileModelRecord({
text: fetchContentFulfilledAction.payload.model.content
}),
loading: false,
saving: false,
error: null
})
);
case "directory": {
// For each entry in the directory listing, create a new contentRef
// and a "filler" contents object
// Optional: run through all the current contents to see if they're
// a file we already have (?)
// Create a map of <ContentRef, ContentRecord> that we merge into the
// content refs state
const dummyRecords = Map<ContentRef, ContentRecord>(
fetchContentFulfilledAction.payload.model.content.map(
(entry: any) => {
return [
createContentRef(),
makeDummyContentRecord({
mimetype: entry.mimetype,
// TODO: We can store the type of this content,
// it just doesn't have a model
// entry.type
assumedType: entry.type,
lastSaved: entry.last_modified,
filepath: entry.path
})
];
}
)
);
const items = List<ContentRef>(dummyRecords.keys());
const sorted: List<string> = items.sort((aRef, bRef) => {
const a:
| RecordOf<DummyContentRecordProps>
| undefined = dummyRecords.get(aRef) as RecordOf<
DummyContentRecordProps
>;
const b:
| RecordOf<DummyContentRecordProps>
| undefined = dummyRecords.get(bRef) as RecordOf<
DummyContentRecordProps
>;
if (a.assumedType === b.assumedType) {
return a.filepath.localeCompare(b.filepath);
}
return a.assumedType.localeCompare(b.assumedType);
});
return (
//.........这里部分代码省略.........