本文整理汇总了TypeScript中@angular-devkit/core.isObservable函数的典型用法代码示例。如果您正苦于以下问题：TypeScript isObservable函数的具体用法？TypeScript isObservable怎么用？TypeScript isObservable使用的例子？那么, 这里精选的函数代码示例或许可以为您提供帮助。
在下文中一共展示了isObservable函数的5个代码示例，这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞，您的评价将有助于系统推荐出更棒的TypeScript代码示例。
示例1: rule
return input.pipe(mergeMap(inputTree => {
const result = rule(inputTree, context) as object;
if (result === undefined) {
return observableOf(inputTree);
} else if (TreeSymbol in result) {
return observableOf(result as Tree);
} else if (typeof result == 'function') {
// This is considered a Rule, chain the rule and return its output.
return callRule(result, input, context);
} else if (isObservable(result)) {
const obs = result as Observable<Tree>;
// Only return the last Tree, and make sure it's a Tree.
return obs.pipe(
last(),
tap(inner => {
if (!(TreeSymbol in inner)) {
throw new InvalidRuleResultException(inner);
}
}),
);
} else if (result === undefined) {
return observableOf(inputTree);
} else {
return throwError(new InvalidRuleResultException(result));
}
}));示例2: rule
return input.pipe(mergeMap(inputTree => {
const result = rule(inputTree, context) as object;
if (result === undefined) {
return observableOf(inputTree);
} else if (TreeSymbol in result) {
return observableOf(result as Tree);
} else if (isObservable(result)) {
const obs = result as Observable<Tree>;
// Only return the last Tree, and make sure it's a Tree.
return obs.pipe(
last(),
tap(inner => {
if (!(TreeSymbol in inner)) {
throw new InvalidRuleResultException(inner);
}
}),
);
} else if (result === undefined) {
return observableOf(inputTree);
} else {
return throwError(new InvalidRuleResultException(result));
}
}));示例3: rule
return input.pipe(mergeMap(inputTree => {
const result = rule(inputTree, context);
if (!result) {
return observableOf(inputTree);
} else if (typeof result == 'function') {
// This is considered a Rule, chain the rule and return its output.
return callRule(result, observableOf(inputTree), context);
} else if (isObservable(result)) {
// Only return the last Tree, and make sure it's a Tree.
return result.pipe(
defaultIfEmpty(),
last(),
tap(inner => {
if (!inner || !(TreeSymbol in inner)) {
throw new InvalidRuleResultException(inner);
}
}),
);
} else if (TreeSymbol in result) {
return observableOf(result);
} else {
return throwError(new InvalidRuleResultException(result));
}
}));示例4: callSource
export function callSource(source: Source, context: SchematicContext): Observable<Tree> {
const result = source(context);
if (isObservable(result)) {
// Only return the last Tree, and make sure it's a Tree.
return result.pipe(
defaultIfEmpty(),
last(),
tap(inner => {
if (!inner || !(TreeSymbol in inner)) {
throw new InvalidSourceResultException(inner);
}
}),
);
} else if (result && TreeSymbol in result) {
return observableOf(result);
} else {
return throwError(new InvalidSourceResultException(result));
}
}示例5: callSource
export function callSource(source: Source, context: SchematicContext): Observable<Tree> {
const result = source(context) as object;
if (result === undefined) {
return throwError(new InvalidSourceResultException(result));
} else if (TreeSymbol in result) {
return observableOf(result as Tree);
} else if (isObservable(result)) {
// Only return the last Tree, and make sure it's a Tree.
return (result as Observable<Tree>).pipe(
last(),
tap(inner => {
if (!(TreeSymbol in inner)) {
throw new InvalidSourceResultException(inner);
}
}),
);
} else {
return throwError(new InvalidSourceResultException(result));
}
}