本文整理汇总了Python中string.pyc方法的典型用法代码示例。如果您正苦于以下问题：Python string.pyc方法的具体用法？Python string.pyc怎么用？Python string.pyc使用的例子？那么, 这里精选的方法代码示例或许可以为您提供帮助。您也可以进一步了解该方法所在类string的用法示例。
在下文中一共展示了string.pyc方法的3个代码示例，这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞，您的评价将有助于系统推荐出更棒的Python代码示例。
示例1: _get_codename
# 需要导入模块: import string [as 别名]
# 或者: from string import pyc [as 别名]
def _get_codename(self, pathname, basename):
"""Return (filename, archivename) for the path.
Given a module name path, return the correct file path and
archive name, compiling if necessary. For example, given
/python/lib/string, return (/python/lib/string.pyc, string).
"""
file_py = pathname + ".py"
file_pyc = pathname + ".pyc"
file_pyo = pathname + ".pyo"
if os.path.isfile(file_pyo) and \
os.stat(file_pyo).st_mtime >= os.stat(file_py).st_mtime:
fname = file_pyo # Use .pyo file
elif not os.path.isfile(file_pyc) or \
os.stat(file_pyc).st_mtime < os.stat(file_py).st_mtime:
import py_compile
if self.debug:
print "Compiling", file_py
try:
py_compile.compile(file_py, file_pyc, None, True)
except py_compile.PyCompileError,err:
print err.msg
fname = file_pyc 示例2: _get_codename
# 需要导入模块: import string [as 别名]
# 或者: from string import pyc [as 别名]
def _get_codename(self, pathname, basename):
"""Return (filename, archivename) for the path.
Given a module name path, return the correct file path and
archive name, compiling if necessary. For example, given
/python/lib/string, return (/python/lib/string.pyc, string).
"""
file_py = pathname + ".py"
file_pyc = pathname + ".pyc"
file_pyo = pathname + ".pyo"
if os.path.isfile(file_pyo) and \
os.stat(file_pyo).st_mtime >= os.stat(file_py).st_mtime:
fname = file_pyo # Use .pyo file
elif not os.path.isfile(file_pyc) or \
os.stat(file_pyc).st_mtime < os.stat(file_py).st_mtime:
import py_compile
if self.debug:
print("Compiling", file_py)
try:
py_compile.compile(file_py, file_pyc, None, True)
except py_compile.PyCompileError as err:
print(err.msg)
fname = file_pyc
else:
fname = file_pyc
archivename = os.path.split(fname)[1]
if basename:
archivename = "%s/%s" % (basename, archivename)
return (fname, archivename) 示例3: _get_codename
# 需要导入模块: import string [as 别名]
# 或者: from string import pyc [as 别名]
def _get_codename(self, pathname, basename):
"""Return (filename, archivename) for the path.
Given a module name path, return the correct file path and
archive name, compiling if necessary. For example, given
/python/lib/string, return (/python/lib/string.pyc, string).
"""
file_py = pathname + ".py"
if _is_jython:
import imp
file_pyc = imp._makeCompiledFilename(file_py)
else:
file_pyc = pathname + ".pyc"
file_pyo = pathname + ".pyo"
if os.path.isfile(file_pyo) and \
os.stat(file_pyo).st_mtime >= os.stat(file_py).st_mtime:
fname = file_pyo # Use .pyo file
elif not os.path.isfile(file_pyc) or \
os.stat(file_pyc).st_mtime < os.stat(file_py).st_mtime:
import py_compile
if self.debug:
print "Compiling", file_py
try:
py_compile.compile(file_py, file_pyc, None, True)
except py_compile.PyCompileError,err:
print err.msg
fname = file_pyc