本文整理汇总了Python中splunklib.client.namespace方法的典型用法代码示例。如果您正苦于以下问题：Python client.namespace方法的具体用法？Python client.namespace怎么用？Python client.namespace使用的例子？那么恭喜您, 这里精选的方法代码示例或许可以为您提供帮助。您也可以进一步了解该方法所在类splunklib.client的用法示例。
在下文中一共展示了client.namespace方法的4个代码示例，这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞，您的评价将有助于系统推荐出更棒的Python代码示例。
示例1: _proper_namespace
# 需要导入模块: from splunklib import client [as 别名]
# 或者: from splunklib.client import namespace [as 别名]
def _proper_namespace(self, owner=None, app=None, sharing=None):
"""Produce a namespace sans wildcards for use in entity requests.
This method tries to fill in the fields of the namespace which are `None`
or wildcard (`'-'`) from the entity's namespace. If that fails, it uses
the service's namespace.
:param owner:
:param app:
:param sharing:
:return:
"""
if owner is None and app is None and sharing is None: # No namespace provided
if self._state is not None and 'access' in self._state:
return (self._state.access.owner,
self._state.access.app,
self._state.access.sharing)
else:
return (self.service.namespace['owner'],
self.service.namespace['app'],
self.service.namespace['sharing'])
else:
return (owner,app,sharing) 示例2: _entity_path
# 需要导入模块: from splunklib import client [as 别名]
# 或者: from splunklib.client import namespace [as 别名]
def _entity_path(self, state):
"""Calculate the path to an entity to be returned.
*state* should be the dictionary returned by
:func:`_parse_atom_entry`. :func:`_entity_path` extracts the
link to this entity from *state*, and strips all the namespace
prefixes from it to leave only the relative path of the entity
itself, sans namespace.
:rtype: ``string``
:return: an absolute path
"""
# This has been factored out so that it can be easily
# overloaded by Configurations, which has to switch its
# entities' endpoints from its own properties/ to configs/.
raw_path = urllib.parse.unquote(state.links.alternate)
if 'servicesNS/' in raw_path:
return _trailing(raw_path, 'servicesNS/', '/', '/')
elif 'services/' in raw_path:
return _trailing(raw_path, 'services/')
else:
return raw_path 示例3: _entity_path
# 需要导入模块: from splunklib import client [as 别名]
# 或者: from splunklib.client import namespace [as 别名]
def _entity_path(self, state):
"""Calculate the path to an entity to be returned.
*state* should be the dictionary returned by
:func:`_parse_atom_entry`. :func:`_entity_path` extracts the
link to this entity from *state*, and strips all the namespace
prefixes from it to leave only the relative path of the entity
itself, sans namespace.
:rtype: ``string``
:return: an absolute path
"""
# This has been factored out so that it can be easily
# overloaded by Configurations, which has to switch its
# entities' endpoints from its own properties/ to configs/.
raw_path = urllib.unquote(state.links.alternate)
if 'servicesNS/' in raw_path:
return _trailing(raw_path, 'servicesNS/', '/', '/')
elif 'services/' in raw_path:
return _trailing(raw_path, 'services/')
else:
return raw_path 示例4: __init__
# 需要导入模块: from splunklib import client [as 别名]
# 或者: from splunklib.client import namespace [as 别名]
def __init__(self, service):
Collection.__init__(self, service, PATH_PROPERTIES, item=ConfigurationFile)
if self.service.namespace.owner == '-' or self.service.namespace.app == '-':
raise ValueError("Configurations cannot have wildcards in namespace.")