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Python Name.Function方法代码示例

本文整理汇总了Python中pygments.token.Name.Function方法的典型用法代码示例。如果您正苦于以下问题:Python Name.Function方法的具体用法?Python Name.Function怎么用?Python Name.Function使用的例子?那么恭喜您, 这里精选的方法代码示例或许可以为您提供帮助。您也可以进一步了解该方法所在pygments.token.Name的用法示例。


在下文中一共展示了Name.Function方法的5个代码示例,这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞,您的评价将有助于系统推荐出更棒的Python代码示例。

示例1: test_can_cope_with_backtick_names_in_functions

# 需要导入模块: from pygments.token import Name [as 别名]
# 或者: from pygments.token.Name import Function [as 别名]
def test_can_cope_with_backtick_names_in_functions(lexer):
    fragment = u'fun `wo bble`'
    tokens = [
        (Keyword, u'fun'),
        (Text, u' '),
        (Name.Function, u'`wo bble`'),
        (Text, u'\n')
    ]
    assert list(lexer.get_tokens(fragment)) == tokens 
开发者ID:pygments,项目名称:pygments,代码行数:11,代码来源:test_kotlin.py

示例2: test_can_cope_with_commas_and_dashes_in_backtick_Names

# 需要导入模块: from pygments.token import Name [as 别名]
# 或者: from pygments.token.Name import Function [as 别名]
def test_can_cope_with_commas_and_dashes_in_backtick_Names(lexer):
    fragment = u'fun `wo,-bble`'
    tokens = [
        (Keyword, u'fun'),
        (Text, u' '),
        (Name.Function, u'`wo,-bble`'),
        (Text, u'\n')
    ]
    assert list(lexer.get_tokens(fragment)) == tokens 
开发者ID:pygments,项目名称:pygments,代码行数:11,代码来源:test_kotlin.py

示例3: test_can_cope_with_generics

# 需要导入模块: from pygments.token import Name [as 别名]
# 或者: from pygments.token.Name import Function [as 别名]
def test_can_cope_with_generics(lexer):
    fragment = u'inline fun <reified T : ContractState> VaultService.queryBy(): Vault.Page<T> {'
    tokens = [
        (Keyword, u'inline fun'),
        (Text, u' '),
        (Punctuation, u'<'),
        (Keyword, u'reified'),
        (Text, u' '),
        (Name, u'T'),
        (Text, u' '),
        (Punctuation, u':'),
        (Text, u' '),
        (Name, u'ContractState'),
        (Punctuation, u'>'),
        (Text, u' '),
        (Name.Class, u'VaultService'),
        (Punctuation, u'.'),
        (Name.Function, u'queryBy'),
        (Punctuation, u'('),
        (Punctuation, u')'),
        (Punctuation, u':'),
        (Text, u' '),
        (Name, u'Vault'),
        (Punctuation, u'.'),
        (Name, u'Page'),
        (Punctuation, u'<'),
        (Name, u'T'),
        (Punctuation, u'>'),
        (Text, u' '),
        (Punctuation, u'{'),
        (Text, u'\n')
    ]
    assert list(lexer.get_tokens(fragment)) == tokens 
开发者ID:pygments,项目名称:pygments,代码行数:35,代码来源:test_kotlin.py

示例4: test_reserved_word

# 需要导入模块: from pygments.token import Name [as 别名]
# 或者: from pygments.token.Name import Function [as 别名]
def test_reserved_word(lexer):
    fragment = u'namespace Foobar\n  links : String\n  links = "abc"'
    tokens = [
        (Keyword.Reserved, u'namespace'),
        (Text, u' '),
        (Keyword.Type, u'Foobar'),
        (Text, u'\n'),
        (Text, u'  '),
        (Name.Function, u'links'),
        (Text, u' '),
        (Operator.Word, u':'),
        (Text, u' '),
        (Keyword.Type, u'String'),
        (Text, u'\n'),
        (Text, u' '),
        (Text, u' '),
        (Text, u'links'),
        (Text, u' '),
        (Operator.Word, u'='),
        (Text, u' '),
        (Literal.String, u'"'),
        (Literal.String, u'abc'),
        (Literal.String, u'"'),
        (Text, u'\n')
    ]
    assert list(lexer.get_tokens(fragment)) == tokens 
开发者ID:pygments,项目名称:pygments,代码行数:28,代码来源:test_idris.py

示例5: test_call

# 需要导入模块: from pygments.token import Name [as 别名]
# 或者: from pygments.token.Name import Function [as 别名]
def test_call(lexer):
    fragment = u'f(1, a)\n'
    tokens = [
        (Name.Function, u'f'),
        (Punctuation, u'('),
        (Token.Literal.Number, u'1'),
        (Punctuation, u','),
        (Token.Text, u' '),
        (Token.Name, u'a'),
        (Punctuation, u')'),
        (Token.Text, u'\n'),
    ]
    assert list(lexer.get_tokens(fragment)) == tokens 
开发者ID:pygments,项目名称:pygments,代码行数:15,代码来源:test_r.py


注:本文中的pygments.token.Name.Function方法示例由纯净天空整理自Github/MSDocs等开源代码及文档管理平台,相关代码片段筛选自各路编程大神贡献的开源项目,源码版权归原作者所有,传播和使用请参考对应项目的License;未经允许,请勿转载。