本文整理汇总了Python中pyautogui.locateOnScreen方法的典型用法代码示例。如果您正苦于以下问题:Python pyautogui.locateOnScreen方法的具体用法?Python pyautogui.locateOnScreen怎么用?Python pyautogui.locateOnScreen使用的例子?那么, 这里精选的方法代码示例或许可以为您提供帮助。您也可以进一步了解该方法所在类pyautogui
的用法示例。
在下文中一共展示了pyautogui.locateOnScreen方法的5个代码示例,这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞,您的评价将有助于系统推荐出更棒的Python代码示例。
示例1: open_firefox
# 需要导入模块: import pyautogui [as 别名]
# 或者: from pyautogui import locateOnScreen [as 别名]
def open_firefox():
# Printing basic message
msg(1,'Opening Firefox...')
# Location the start button
_start_button_=pyautogui.locateOnScreen('images/start_button.png')
_location_=pyautogui.center(_start_button_)
# Clicking the start button
if not pyautogui.click(_location_):
msg(1,'Opened start menu successfully!')
else:
msg(3,'Failed to open start menu!')
ext()
time.sleep(2)
# Search for Firefox in the menu search
pyautogui.typewrite('firefox')
pyautogui.typewrite('\n')
# Print message
msg(1,'Firefox is now open and running.')
# Function used to locate GMail
示例2: send_message
# 需要导入模块: import pyautogui [as 别名]
# 或者: from pyautogui import locateOnScreen [as 别名]
def send_message(contact, message):
"""Sends message to an active slack contact
Args:
contact (str): contacts name on slack
message (str): message to send to friend
Returns:
None
"""
try:
print('5 seconds to navigate to slack app..')
time.sleep(5)
# Use JumpTo slack feature
pyautogui.hotkey('command', 'k')
time.sleep(1)
# Enter contact name in search box, click enter
pyautogui.typewrite(contact)
time.sleep(1)
pyautogui.typewrite(['enter'])
time.sleep(1)
active = pyautogui.locateOnScreen('active_identifier.png')
if not active:
print(f'{contact} is not active, skipped contact')
return
print('Contact is active, sending message...')
pyautogui.typewrite(['tab'])
pyautogui.typewrite(message)
pyautogui.typewrite(['enter'])
except KeyboardInterrupt:
print('Process was cancelled..')
示例3: auto_message
# 需要导入模块: import pyautogui [as 别名]
# 或者: from pyautogui import locateOnScreen [as 别名]
def auto_message(name, message):
"""Searches for friend on Google Hangouts and messages them."""
print("Make sure the Google Hangout 'Conversations' page is visible and "
"your cursor is not currently on the page.")
time.sleep(3)
search_bar = pyautogui.locateOnScreen('search.png')
pyautogui.click(search_bar)
pyautogui.typewrite(name)
time.sleep(1)
online_select = pyautogui.locateOnScreen('online-friend.png')
if online_select is None:
print('Friend not found or currently offline.')
return
else:
pyautogui.doubleClick(online_select)
attempts = 3
while attempts > 0:
message_box = pyautogui.locateOnScreen('message.png')
pyautogui.click(message_box)
pyautogui.typewrite(message)
# If it can no longer be found it is because the message was entered.
if pyautogui.locateOnScreen('message.png') is None:
pyautogui.press('enter')
pyautogui.press('esc')
print('Message sent to {}'.format(name))
break
else:
if attempts == 1:
print('Unable to send message to {}.'.format(name))
pyautogui.press('esc')
else:
print('Sending message to {} failed. Another {} attempts will '
'be made before moving on.'.format(name, attempts))
attempts -= 1
示例4: locate_gmail
# 需要导入模块: import pyautogui [as 别名]
# 或者: from pyautogui import locateOnScreen [as 别名]
def locate_gmail():
#Sleep for a while and wait for Firefox to open
time.sleep(3)
# Printing message
msg(1,'Opening Gmail...')
# Typing the website on the browser
pyautogui.keyDown('ctrlleft'); pyautogui.typewrite('a'); pyautogui.keyUp('ctrlleft')
pyautogui.typewrite('https://accounts.google.com/SignUp?service=mail&continue=https%3A%2F%2Fmail.google.com%2Fmail%2F<mpl=default')
pyautogui.typewrite('\n')
# Wait for a while until the website responds
time.sleep(6)
# Print a simple message
msg(1,'Locating the form...')
# Locate the form
pyautogui.press('tab')
time.sleep(2)
_gmail_ = pyautogui.locateOnScreen('images/gmail_form.png')
formx, formy = pyautogui.center(_gmail_)
pyautogui.click(formx, formy)
# Check and print message
if not pyautogui.click(formx, formy):
msg(1,'Located the form.')
else:
msg(3,'Failed to locate the form.')
ext()
# Function used to randomize credentials
示例5: test_locateFunctions
# 需要导入模块: import pyautogui [as 别名]
# 或者: from pyautogui import locateOnScreen [as 别名]
def test_locateFunctions(self):
# TODO - for now, we only test that the "return None" and "raise pyautogui.ImageNotFoundException" is raised.
pyautogui.useImageNotFoundException()
with self.assertRaises(pyautogui.ImageNotFoundException):
pyautogui.locate("100x100blueimage.png", "100x100redimage.png")
# Commenting out the locateAll*() functions because they return generators, even if the image can't be found. Should they instead raise an exception? This is a question for pyscreeze's design.
# with self.assertRaises(pyautogui.ImageNotFoundException):
# pyautogui.locateAll('100x100blueimage.png', '100x100redimage.png')
# with self.assertRaises(pyautogui.ImageNotFoundException):
# pyautogui.locateAllOnScreen('100x100blueimage.png') # NOTE: This test fails if there is a blue square visible on the screen.
with self.assertRaises(pyautogui.ImageNotFoundException):
pyautogui.locateOnScreen(
"100x100blueimage.png"
) # NOTE: This test fails if there is a blue square visible on the screen.
with self.assertRaises(pyautogui.ImageNotFoundException):
pyautogui.locateCenterOnScreen(
"100x100blueimage.png"
) # NOTE: This test fails if there is a blue square visible on the screen.
pyautogui.useImageNotFoundException(False)
self.assertEqual(pyautogui.locate("100x100blueimage.png", "100x100redimage.png"), None)
# self.assertEqual(pyautogui.locateAll('100x100blueimage.png', '100x100redimage.png'), None)
# self.assertEqual(pyautogui.locateAllOnScreen('100x100blueimage.png'), None) # NOTE: This test fails if there is a blue square visible on the screen.
self.assertEqual(
pyautogui.locateOnScreen("100x100blueimage.png"), None
) # NOTE: This test fails if there is a blue square visible on the screen.
self.assertEqual(
pyautogui.locateCenterOnScreen("100x100blueimage.png"), None
) # NOTE: This test fails if there is a blue square visible on the screen.