本文整理汇总了Python中past.types.basestring方法的典型用法代码示例。如果您正苦于以下问题:Python types.basestring方法的具体用法?Python types.basestring怎么用?Python types.basestring使用的例子?那么, 这里精选的方法代码示例或许可以为您提供帮助。您也可以进一步了解该方法所在类past.types
的用法示例。
在下文中一共展示了types.basestring方法的2个代码示例,这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞,您的评价将有助于系统推荐出更棒的Python代码示例。
示例1: oldfilter
# 需要导入模块: from past import types [as 别名]
# 或者: from past.types import basestring [as 别名]
def oldfilter(*args):
"""
filter(function or None, sequence) -> list, tuple, or string
Return those items of sequence for which function(item) is true.
If function is None, return the items that are true. If sequence
is a tuple or string, return the same type, else return a list.
"""
mytype = type(args[1])
if isinstance(args[1], basestring):
return mytype().join(builtins.filter(*args))
elif isinstance(args[1], (tuple, list)):
return mytype(builtins.filter(*args))
else:
# Fall back to list. Is this the right thing to do?
return list(builtins.filter(*args))
# This is surprisingly difficult to get right. For example, the
# solutions here fail with the test cases in the docstring below:
# http://stackoverflow.com/questions/8072755/
示例2: oldfilter
# 需要导入模块: from past import types [as 别名]
# 或者: from past.types import basestring [as 别名]
def oldfilter(*args):
"""
filter(function or None, sequence) -> list, tuple, or string
Return those items of sequence for which function(item) is true.
If function is None, return the items that are true. If sequence
is a tuple or string, return the same type, else return a list.
"""
mytype = type(args[1])
if isinstance(args[1], basestring):
return mytype().join(builtins.filter(*args))
elif isinstance(args[1], (tuple, list)):
return mytype(builtins.filter(*args))
else:
# Fall back to list. Is this the right thing to do?
return list(builtins.filter(*args))
# This is surprisingly difficult to get right. For example, the
# solutions here fail with the test cases in the docstring below:
# http://stackoverflow.com/questions/8072755/