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Python noniterators.filter方法代码示例

本文整理汇总了Python中past.builtins.noniterators.filter方法的典型用法代码示例。如果您正苦于以下问题:Python noniterators.filter方法的具体用法?Python noniterators.filter怎么用?Python noniterators.filter使用的例子?那么恭喜您, 这里精选的方法代码示例或许可以为您提供帮助。您也可以进一步了解该方法所在past.builtins.noniterators的用法示例。


在下文中一共展示了noniterators.filter方法的2个代码示例,这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞,您的评价将有助于系统推荐出更棒的Python代码示例。

示例1: oldfilter

# 需要导入模块: from past.builtins import noniterators [as 别名]
# 或者: from past.builtins.noniterators import filter [as 别名]
def oldfilter(*args):
        """
        filter(function or None, sequence) -> list, tuple, or string

        Return those items of sequence for which function(item) is true.
        If function is None, return the items that are true.  If sequence
        is a tuple or string, return the same type, else return a list.
        """
        mytype = type(args[1])
        if isinstance(args[1], basestring):
            return mytype().join(builtins.filter(*args))
        elif isinstance(args[1], (tuple, list)):
            return mytype(builtins.filter(*args))
        else:
            # Fall back to list. Is this the right thing to do?
            return list(builtins.filter(*args))

    # This is surprisingly difficult to get right. For example, the
    # solutions here fail with the test cases in the docstring below:
    # http://stackoverflow.com/questions/8072755/ 
开发者ID:remg427,项目名称:misp42splunk,代码行数:22,代码来源:noniterators.py

示例2: oldfilter

# 需要导入模块: from past.builtins import noniterators [as 别名]
# 或者: from past.builtins.noniterators import filter [as 别名]
def oldfilter(*args):
        """
        filter(function or None, sequence) -> list, tuple, or string
        
        Return those items of sequence for which function(item) is true.
        If function is None, return the items that are true.  If sequence
        is a tuple or string, return the same type, else return a list.
        """
        mytype = type(args[1])
        if isinstance(args[1], basestring):
            return mytype().join(builtins.filter(*args))
        elif isinstance(args[1], (tuple, list)):
            return mytype(builtins.filter(*args))
        else:
            # Fall back to list. Is this the right thing to do?
            return list(builtins.filter(*args))

    # This is surprisingly difficult to get right. For example, the
    # solutions here fail with the test cases in the docstring below:
    # http://stackoverflow.com/questions/8072755/ 
开发者ID:QData,项目名称:deepWordBug,代码行数:22,代码来源:noniterators.py


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