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Python common._not_none方法代码示例

本文整理汇总了Python中pandas.core.common._not_none方法的典型用法代码示例。如果您正苦于以下问题:Python common._not_none方法的具体用法?Python common._not_none怎么用?Python common._not_none使用的例子?那么, 这里精选的方法代码示例或许可以为您提供帮助。您也可以进一步了解该方法所在pandas.core.common的用法示例。


在下文中一共展示了common._not_none方法的2个代码示例,这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞,您的评价将有助于系统推荐出更棒的Python代码示例。

示例1: _concat_objects

# 需要导入模块: from pandas.core import common [as 别名]
# 或者: from pandas.core.common import _not_none [as 别名]
def _concat_objects(self, keys, values, not_indexed_same=False):
        from pandas.core.reshape.concat import concat

        def reset_identity(values):
            # reset the identities of the components
            # of the values to prevent aliasing
            for v in com._not_none(*values):
                ax = v._get_axis(self.axis)
                ax._reset_identity()
            return values

        if not not_indexed_same:
            result = concat(values, axis=self.axis)
            ax = self._selected_obj._get_axis(self.axis)

            if isinstance(result, Series):
                result = result.reindex(ax)
            else:

                # this is a very unfortunate situation
                # we have a multi-index that is NOT lexsorted
                # and we have a result which is duplicated
                # we can't reindex, so we resort to this
                # GH 14776
                if isinstance(ax, MultiIndex) and not ax.is_unique:
                    indexer = algorithms.unique1d(
                        result.index.get_indexer_for(ax.values))
                    result = result.take(indexer, axis=self.axis)
                else:
                    result = result.reindex(ax, axis=self.axis)

        elif self.group_keys:

            values = reset_identity(values)
            if self.as_index:

                # possible MI return case
                group_keys = keys
                group_levels = self.grouper.levels
                group_names = self.grouper.names

                result = concat(values, axis=self.axis, keys=group_keys,
                                levels=group_levels, names=group_names,
                                sort=False)
            else:

                # GH5610, returns a MI, with the first level being a
                # range index
                keys = list(range(len(values)))
                result = concat(values, axis=self.axis, keys=keys)
        else:
            values = reset_identity(values)
            result = concat(values, axis=self.axis)

        if (isinstance(result, Series) and
                getattr(self, '_selection_name', None) is not None):

            result.name = self._selection_name

        return result 
开发者ID:Frank-qlu,项目名称:recruit,代码行数:62,代码来源:groupby.py

示例2: _join_multi

# 需要导入模块: from pandas.core import common [as 别名]
# 或者: from pandas.core.common import _not_none [as 别名]
def _join_multi(self, other, how, return_indexers=True):
        from .multi import MultiIndex
        self_is_mi = isinstance(self, MultiIndex)
        other_is_mi = isinstance(other, MultiIndex)

        # figure out join names
        self_names = com._not_none(*self.names)
        other_names = com._not_none(*other.names)
        overlap = list(set(self_names) & set(other_names))

        # need at least 1 in common, but not more than 1
        if not len(overlap):
            raise ValueError("cannot join with no level specified and no "
                             "overlapping names")
        if len(overlap) > 1:
            raise NotImplementedError("merging with more than one level "
                                      "overlap on a multi-index is not "
                                      "implemented")
        jl = overlap[0]

        # make the indices into mi's that match
        if not (self_is_mi and other_is_mi):

            flip_order = False
            if self_is_mi:
                self, other = other, self
                flip_order = True
                # flip if join method is right or left
                how = {'right': 'left', 'left': 'right'}.get(how, how)

            level = other.names.index(jl)
            result = self._join_level(other, level, how=how,
                                      return_indexers=return_indexers)

            if flip_order:
                if isinstance(result, tuple):
                    return result[0], result[2], result[1]
            return result

        # 2 multi-indexes
        raise NotImplementedError("merging with both multi-indexes is not "
                                  "implemented") 
开发者ID:birforce,项目名称:vnpy_crypto,代码行数:44,代码来源:base.py


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