本文整理汇总了Python中pandas.compat.intern方法的典型用法代码示例。如果您正苦于以下问题：Python compat.intern方法的具体用法？Python compat.intern怎么用？Python compat.intern使用的例子？那么, 这里精选的方法代码示例或许可以为您提供帮助。您也可以进一步了解该方法所在类pandas.compat的用法示例。
在下文中一共展示了compat.intern方法的2个代码示例，这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞，您的评价将有助于系统推荐出更棒的Python代码示例。
示例1: test_interned
# 需要导入模块: from pandas import compat [as 别名]
# 或者: from pandas.compat import intern [as 别名]
def test_interned():
salt = uuid4().hex
def make_string():
# We need to actually create a new string so that it has refcount
# one. We use a uuid so that we know the string could not already
# be in the intern table.
return "".join(("testing: ", salt))
# This should work, the string has one reference on the stack.
move_into_mutable_buffer(make_string())
refcount = [None] # nonlocal
def ref_capture(ob):
# Subtract two because those are the references owned by this frame:
# 1. The local variables of this stack frame.
# 2. The python data stack of this stack frame.
refcount[0] = sys.getrefcount(ob) - 2
return ob
with pytest.raises(BadMove, match="testing"):
# If we intern the string, it will still have one reference. Now,
# it is in the intern table, so if other people intern the same
# string while the mutable buffer holds the first string they will
# be the same instance.
move_into_mutable_buffer(ref_capture(intern(make_string()))) # noqa
assert refcount[0] == 1 示例2: test_interned
# 需要导入模块: from pandas import compat [as 别名]
# 或者: from pandas.compat import intern [as 别名]
def test_interned(self):
salt = uuid4().hex
def make_string():
# We need to actually create a new string so that it has refcount
# one. We use a uuid so that we know the string could not already
# be in the intern table.
return ''.join(('testing: ', salt))
# This should work, the string has one reference on the stack.
move_into_mutable_buffer(make_string())
refcount = [None] # nonlocal
def ref_capture(ob):
# Subtract two because those are the references owned by this
# frame:
# 1. The local variables of this stack frame.
# 2. The python data stack of this stack frame.
refcount[0] = sys.getrefcount(ob) - 2
return ob
with pytest.raises(BadMove):
# If we intern the string it will still have one reference but now
# it is in the intern table so if other people intern the same
# string while the mutable buffer holds the first string they will
# be the same instance.
move_into_mutable_buffer(ref_capture(intern(make_string()))) # noqa
assert refcount[0] == 1