Python operator.indexOf方法代码示例

# 需要导入模块: import operator [as 别名]
# 或者: from operator import indexOf [as 别名]
def merge_practices(*args, **kwargs):
  """Merge two or more dictionaries, preferring values in increasing order of index in `order`.

  Treats practices with no `status` as 'na'.
  """
  order = kwargs.pop('order', ['unknown', 'na', 'nudge', 'warn', 'ok'])
  if len(kwargs) > 0:
    raise TypeError("merge_practices() got unexpected keyword argument(s) {:s}"
                    "".format(', '.join("'{:s}'".format(kw) for kw in six.iterkeys(kwargs))))

  practices = dict()
  for practice in set(itertools.chain.from_iterable(arg.keys() for arg in args)):
    practices[practice] = max(
        (arg.get(practice, {'status': 'unknown'}) for arg in args),
        key=lambda _practice: operator.indexOf(order, _practice.get('status', 'unknown'))
    )
  return practices 

# 需要导入模块: import operator [as 别名]
# 或者: from operator import indexOf [as 别名]
def operations_to_part_lens(
        qubit_order: Sequence['cirq.Qid'],
        op_tree: 'cirq.OP_TREE',
) -> Tuple[int, ...]:
    qubit_sort_key = functools.partial(operator.indexOf, qubit_order)
    op_parts = [tuple(sorted(op.qubits,key=qubit_sort_key))
                for op in ops.flatten_op_tree(op_tree)]
    singletons = [(q,) for q in set(qubit_order).difference(*op_parts)
                 ]  # type: List[Tuple['cirq.Qid', ...]]
    part_sort_key = lambda p: min(qubit_sort_key(q) for q in p)
    parts = tuple(tuple(part) for part in
                  sorted(singletons + op_parts, key=part_sort_key))

    if sum(parts, ()) != tuple(qubit_order):
        raise ValueError('sum(parts, ()) != tuple(qubit_order)')

    return tuple(len(part) for part in parts) 

# 需要导入模块: import operator [as 别名]
# 或者: from operator import indexOf [as 别名]
def test_countOf(self):
        from operator import countOf
        self.assertEqual(countOf([1,2,2,3,2,5], 2), 3)
        self.assertEqual(countOf((1,2,2,3,2,5), 2), 3)
        self.assertEqual(countOf("122325", "2"), 3)
        self.assertEqual(countOf("122325", "6"), 0)

        self.assertRaises(TypeError, countOf, 42, 1)
        self.assertRaises(TypeError, countOf, countOf, countOf)

        d = {"one": 3, "two": 3, "three": 3, 1j: 2j}
        for k in d:
            self.assertEqual(countOf(d, k), 1)
        self.assertEqual(countOf(d.itervalues(), 3), 3)
        self.assertEqual(countOf(d.itervalues(), 2j), 1)
        self.assertEqual(countOf(d.itervalues(), 1j), 0)

        f = open(TESTFN, "w")
        try:
            f.write("a\n" "b\n" "c\n" "b\n")
        finally:
            f.close()
        f = open(TESTFN, "r")
        try:
            for letter, count in ("a", 1), ("b", 2), ("c", 1), ("d", 0):
                f.seek(0, 0)
                self.assertEqual(countOf(f, letter + "\n"), count)
        finally:
            f.close()
            try:
                unlink(TESTFN)
            except OSError:
                pass

    # Test iterators with operator.indexOf (PySequence_Index). 

# 需要导入模块: import operator [as 别名]
# 或者: from operator import indexOf [as 别名]
def test_indexOf(self):
        from operator import indexOf
        self.assertEqual(indexOf([1,2,2,3,2,5], 1), 0)
        self.assertEqual(indexOf((1,2,2,3,2,5), 2), 1)
        self.assertEqual(indexOf((1,2,2,3,2,5), 3), 3)
        self.assertEqual(indexOf((1,2,2,3,2,5), 5), 5)
        self.assertRaises(ValueError, indexOf, (1,2,2,3,2,5), 0)
        self.assertRaises(ValueError, indexOf, (1,2,2,3,2,5), 6)

        self.assertEqual(indexOf("122325", "2"), 1)
        self.assertEqual(indexOf("122325", "5"), 5)
        self.assertRaises(ValueError, indexOf, "122325", "6")

        self.assertRaises(TypeError, indexOf, 42, 1)
        self.assertRaises(TypeError, indexOf, indexOf, indexOf)

        f = open(TESTFN, "w")
        try:
            f.write("a\n" "b\n" "c\n" "d\n" "e\n")
        finally:
            f.close()
        f = open(TESTFN, "r")
        try:
            fiter = iter(f)
            self.assertEqual(indexOf(fiter, "b\n"), 1)
            self.assertEqual(indexOf(fiter, "d\n"), 1)
            self.assertEqual(indexOf(fiter, "e\n"), 0)
            self.assertRaises(ValueError, indexOf, fiter, "a\n")
        finally:
            f.close()
            try:
                unlink(TESTFN)
            except OSError:
                pass

        iclass = IteratingSequenceClass(3)
        for i in range(3):
            self.assertEqual(indexOf(iclass, i), i)
        self.assertRaises(ValueError, indexOf, iclass, -1)

    # Test iterators with file.writelines(). 

# 需要导入模块: import operator [as 别名]
# 或者: from operator import indexOf [as 别名]
def test_indexOf(self):
        self.assertRaises(TypeError, operator.indexOf)
        self.assertRaises(TypeError, operator.indexOf, None, None)
        self.assertTrue(operator.indexOf([4, 3, 2, 1], 3) == 1)
        self.assertRaises(ValueError, operator.indexOf, [4, 3, 2, 1], 0) 

# 需要导入模块: import operator [as 别名]
# 或者: from operator import indexOf [as 别名]
def reshape(self, *newShape):
  if len(newShape)==1 and not type(newShape[0]) in _numberTypes: newShape = tuple(newShape[0])
  if not _all2_(newShape, _isNumber): raise TypeError('the parameters to reshape don\'t look like a valid shape')
  if -1 in newShape:
   if _prodT(newShape)==0: raise ValueError("-1 as a parameter to reshape is not allowed if one of the other parameters is zero.")
   newShape = _modifyT(newShape, operator.indexOf(newShape, -1), self.size//-_prodT(newShape))
  if _prodT(newShape) != self.size: raise ValueError('the total number of items cannot be changed in a reshape')
  return garray(self._base, newShape, self) 

# 需要导入模块: import operator [as 别名]
# 或者: from operator import indexOf [as 别名]
def test_countOf(self):
        from operator import countOf
        self.assertEqual(countOf([1,2,2,3,2,5], 2), 3)
        self.assertEqual(countOf((1,2,2,3,2,5), 2), 3)
        self.assertEqual(countOf("122325", "2"), 3)
        self.assertEqual(countOf("122325", "6"), 0)

        self.assertRaises(TypeError, countOf, 42, 1)
        self.assertRaises(TypeError, countOf, countOf, countOf)

        d = {"one": 3, "two": 3, "three": 3, 1j: 2j}
        for k in d:
            self.assertEqual(countOf(d, k), 1)
        self.assertEqual(countOf(d.values(), 3), 3)
        self.assertEqual(countOf(d.values(), 2j), 1)
        self.assertEqual(countOf(d.values(), 1j), 0)

        f = open(TESTFN, "w")
        try:
            f.write("a\n" "b\n" "c\n" "b\n")
        finally:
            f.close()
        f = open(TESTFN, "r")
        try:
            for letter, count in ("a", 1), ("b", 2), ("c", 1), ("d", 0):
                f.seek(0, 0)
                self.assertEqual(countOf(f, letter + "\n"), count)
        finally:
            f.close()
            try:
                unlink(TESTFN)
            except OSError:
                pass

    # Test iterators with operator.indexOf (PySequence_Index). 

# 需要导入模块: import operator [as 别名]
# 或者: from operator import indexOf [as 别名]
def _status_priority(match):
  return operator.indexOf(['unknown', 'nudge', 'warn', 'ok'], match[0]) 

# 需要导入模块: import operator [as 别名]
# 或者: from operator import indexOf [as 别名]
def test_indexOf(self):
        self.failUnlessRaises(TypeError, operator.indexOf)
        self.failUnlessRaises(TypeError, operator.indexOf, None, None)
        self.failUnless(operator.indexOf([4, 3, 2, 1], 3) == 1)
        self.assertRaises(ValueError, operator.indexOf, [4, 3, 2, 1], 0) 

# 需要导入模块: import operator [as 别名]
# 或者: from operator import indexOf [as 别名]
def timeframeAsStrForWebUI(self, frame=0):
        if self.isRelative(frame):
            webUIConsts = ["l_1_HOURS", "l_2_HOURS", "l_6_HOURS", "l_24_HOURS", "l_7_DAYS", "l_30_DAYS"]
            ix = operator.indexOf(self.allowedConsts, self.timeframestr[frame])
            return webUIConsts[ix]
        else:
            return str(self.timestamp[frame])