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Python numpy.matmul方法代码示例

本文整理汇总了Python中numpy.matmul方法的典型用法代码示例。如果您正苦于以下问题:Python numpy.matmul方法的具体用法?Python numpy.matmul怎么用?Python numpy.matmul使用的例子?那么, 这里精选的方法代码示例或许可以为您提供帮助。您也可以进一步了解该方法所在numpy的用法示例。


在下文中一共展示了numpy.matmul方法的15个代码示例,这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞,您的评价将有助于系统推荐出更棒的Python代码示例。

示例1: _BtDB

# 需要导入模块: import numpy [as 别名]
# 或者: from numpy import matmul [as 别名]
def _BtDB(self,s,r):
        """
        dot product of B^T, D, B
        params:
            s,r:natural position of evalue point.2-array.
        returns:
            3x3 matrix.
        """
        print(self._B(s,r).transpose(2,0,1).shape)
        print(
            np.matmul(
                np.dot(self._B(s,r).T,self._D),
                self._B(s,r).transpose(2,0,1)).shape
            )
        print(self._D.shape)
       
        
        return np.matmul(np.dot(self._B(s,r).T,self._D),self._B(s,r).transpose(2,0,1)).transpose(1,2,0) 
开发者ID:zhuoju36,项目名称:StructEngPy,代码行数:20,代码来源:element.py

示例2: DataProjection

# 需要导入模块: import numpy [as 别名]
# 或者: from numpy import matmul [as 别名]
def DataProjection(X, r, type='NormalProj'):
    Xp = None
    D, N = X.shape
    if r == 0:
        Xp = X
    else:
        if type == 'PCA':
            isEcon = False
            if D > N:
                isEcon = True
            U, S, V = np.linalg.svd(X.T, full_matrices=isEcon)
            Xp = U[:, 0:r].T
        if type == 'NormalProj':
            normP = (1.0 / math.sqrt(r)) * np.random.randn(r * D, 1)
            PrN = normP.reshape(r, D, order='F')
            Xp = np.matmul(PrN, X)
        if type == 'BernoulliProj':
            bp = np.random.rand(r * D, 1)
            Bp = (1.0 / math.sqrt(r)) * (bp >= .5) - (1.0 / math.sqrt(r)) * (bp < .5)
            PrB = Bp.reshape(r, D, order='F')
            Xp = np.matmul(PrB, X)
    return Xp 
开发者ID:abhinav4192,项目名称:sparse-subspace-clustering-python,代码行数:24,代码来源:DataProjection.py

示例3: SpectralClustering

# 需要导入模块: import numpy [as 别名]
# 或者: from numpy import matmul [as 别名]
def SpectralClustering(CKSym, n):
    # This is direct port of JHU vision lab code. Could probably use sklearn SpectralClustering.
    CKSym = CKSym.astype(float)
    N, _ = CKSym.shape
    MAXiter = 1000  # Maximum number of iterations for KMeans
    REPlic = 20  # Number of replications for KMeans

    DN = np.diag(np.divide(1, np.sqrt(np.sum(CKSym, axis=0) + np.finfo(float).eps)))
    LapN = identity(N).toarray().astype(float) - np.matmul(np.matmul(DN, CKSym), DN)
    _, _, vN = np.linalg.svd(LapN)
    vN = vN.T
    kerN = vN[:, N - n:N]
    normN = np.sqrt(np.sum(np.square(kerN), axis=1))
    kerNS = np.divide(kerN, normN.reshape(len(normN), 1) + np.finfo(float).eps)
    km = KMeans(n_clusters=n, n_init=REPlic, max_iter=MAXiter, n_jobs=-1).fit(kerNS)
    return km.labels_ 
开发者ID:abhinav4192,项目名称:sparse-subspace-clustering-python,代码行数:18,代码来源:SpectralClustering.py

示例4: _evaluate

# 需要导入模块: import numpy [as 别名]
# 或者: from numpy import matmul [as 别名]
def _evaluate(self, X, out, *args, **kwargs):
        if self.w == 0:
            X1 = X[:, 0]
            X2 = X[:, 1]
        else:
            # If rotated, we rotate it back by applying the inverted rotation matrix to X
            Y = np.array([np.matmul(self.IRM, x) for x in X])
            X1 = Y[:, 0]
            X2 = Y[:, 1]

        a, b, c = self.a, self.b, self.c
        t1_hat = sign(X1) * ceil((abs(X1) - a - c / 2) / (2 * a + c))
        t2_hat = sign(X2) * ceil((abs(X2) - b / 2) / b)
        one = ones(len(X))
        t1 = sign(t1_hat) * min(np.vstack((abs(t1_hat), one)), axis=0)
        t2 = sign(t2_hat) * min(np.vstack((abs(t2_hat), one)), axis=0)

        p1 = X1 - t1 * c
        p2 = X2 - t2 * b

        f1 = (p1 + a) ** 2 + p2 ** 2
        f2 = (p1 - a) ** 2 + p2 ** 2
        out["F"] = np.vstack((f1, f2)).T 
开发者ID:msu-coinlab,项目名称:pymoo,代码行数:25,代码来源:sympart.py

示例5: _calc_pareto_set

# 需要导入模块: import numpy [as 别名]
# 或者: from numpy import matmul [as 别名]
def _calc_pareto_set(self, n_pareto_points=500):
        # The SYM-PART test problem has 9 equivalent Pareto subsets.
        h = int(n_pareto_points / 9)
        PS = zeros((h * 9, self.n_var))
        cnt = 0
        for row in [-1, 0, 1]:
            for col in [1, 0, -1]:
                X1 = np.linspace(row * self.c - self.a, row * self.c + self.a, h)
                X2 = np.tile(col * self.b, h)
                PS[cnt * h:cnt * h + h, :] = np.vstack((X1, X2)).T
                cnt = cnt + 1
        if self.w != 0:
            # If rotated, we apply the rotation matrix to PS
            # Calculate the rotation matrix
            RM = np.array([
                [cos(self.w), -sin(self.w)],
                [sin(self.w), cos(self.w)]
            ])
            PS = np.array([np.matmul(RM, x) for x in PS])
        return PS 
开发者ID:msu-coinlab,项目名称:pymoo,代码行数:22,代码来源:sympart.py

示例6: overlap_ni

# 需要导入模块: import numpy [as 别名]
# 或者: from numpy import matmul [as 别名]
def overlap_ni(me, sp1,R1, sp2,R2, **kw):
    """
      Computes overlap for an atom pair. The atom pair is given by a pair of species indices
      and the coordinates of the atoms.
      Args: 
        sp1,sp2 : specie indices, and
        R1,R2 :   respective coordinates in Bohr, atomic units
      Result:
        matrix of orbital overlaps
      The procedure uses the numerical integration in coordinate space.
    """
    from pyscf.nao.m_ao_matelem import build_3dgrid
    from pyscf.nao.m_ao_eval_libnao import ao_eval_libnao as ao_eval #_libnao

    grids = build_3dgrid(me, sp1, R1, sp2, R2, **kw)

    ao1 = ao_eval(me.ao1, R1, sp1, grids.coords)
    ao1 = ao1 * grids.weights

    ao2 = ao_eval(me.ao2, R2, sp2, grids.coords)

    overlaps = np.einsum("ij,kj->ik", ao1, ao2) #      overlaps = np.matmul(ao1, ao2.T)

    return overlaps 
开发者ID:pyscf,项目名称:pyscf,代码行数:26,代码来源:m_overlap_ni.py

示例7: get_3d_box_batch

# 需要导入模块: import numpy [as 别名]
# 或者: from numpy import matmul [as 别名]
def get_3d_box_batch(box_size, heading_angle, center):
    ''' box_size: [x1,x2,...,xn,3]
        heading_angle: [x1,x2,...,xn]
        center: [x1,x2,...,xn,3]
    Return:
        [x1,x3,...,xn,8,3]
    '''
    input_shape = heading_angle.shape
    R = roty_batch(heading_angle)
    l = np.expand_dims(box_size[...,0], -1) # [x1,...,xn,1]
    w = np.expand_dims(box_size[...,1], -1)
    h = np.expand_dims(box_size[...,2], -1)
    corners_3d = np.zeros(tuple(list(input_shape)+[8,3]))
    corners_3d[...,:,0] = np.concatenate((l/2,l/2,-l/2,-l/2,l/2,l/2,-l/2,-l/2), -1)
    corners_3d[...,:,1] = np.concatenate((h/2,h/2,h/2,h/2,-h/2,-h/2,-h/2,-h/2), -1)
    corners_3d[...,:,2] = np.concatenate((w/2,-w/2,-w/2,w/2,w/2,-w/2,-w/2,w/2), -1)
    tlist = [i for i in range(len(input_shape))]
    tlist += [len(input_shape)+1, len(input_shape)]
    corners_3d = np.matmul(corners_3d, np.transpose(R, tuple(tlist)))
    corners_3d += np.expand_dims(center, -2)
    return corners_3d 
开发者ID:zaiweizhang,项目名称:H3DNet,代码行数:23,代码来源:box_util.py

示例8: rotate_molecule

# 需要导入模块: import numpy [as 别名]
# 或者: from numpy import matmul [as 别名]
def rotate_molecule(path, target_path, count=10):
    # Load dataset
    mols = Chem.SDMolSupplier(path)
    rotated_mols = []

    print("Loaded {} Molecules from {}".format(len(mols), path))

    print("Rotating Molecules...")
    for mol in mols:
        for _ in range(count):
            for atom in mol.GetAtoms():
                atom_idx = atom.GetIdx()

                pos = list(mol.GetConformer().GetAtomPosition(atom_idx))
                pos_rotated = np.matmul(random_rotation_matrix(), pos)

                mol.GetConformer().SetAtomPosition(atom_idx, pos_rotated)

            rotated_mols.append(mol)

    w = Chem.SDWriter(target_path)
    for m in rotated_mols:
        if m is not None:
            w.write(m)
    print("Saved {} Molecules to {}".format(len(rotated_mols), target_path)) 
开发者ID:blackmints,项目名称:3DGCN,代码行数:27,代码来源:converter.py

示例9: backward

# 需要导入模块: import numpy [as 别名]
# 或者: from numpy import matmul [as 别名]
def backward(self, Z, O, E, W):
        outdim = W.shape[-1]
        time, batch, zdim = Z.shape
        indim = zdim - outdim

        bwO = self.actfn.backward(O)

        for t in range(time-1, -1, -1):
            E[t] *= bwO[t]
            deltaZ = np.dot(E[t], W.T)
            E[t-1] += deltaZ[:, indim:] if t else 0.

        dX = E[:, :, :indim]
        nablaW = np.matmul(Z.transpose(0, 2, 1), E).sum(axis=0)
        nablab = E.sum(axis=(0, 1))
        return dX, nablaW, nablab 
开发者ID:csxeba,项目名称:brainforge,代码行数:18,代码来源:recurrent_op.py

示例10: valid

# 需要导入模块: import numpy [as 别名]
# 或者: from numpy import matmul [as 别名]
def valid(A, F):
        im, ic, iy, ix = A.shape
        nf, fc, fy, fx = F.shape
        # fx, fy, fc, nf = F.shape
        recfield_size = fx * fy * fc
        oy, ox = iy - fy + 1, ix - fx + 1
        rfields = np.zeros((im, oy*ox, recfield_size))
        Frsh = F.reshape(nf, recfield_size)

        if fc != ic:
            err = "Supplied filter (F) is incompatible with supplied input! (X)\n"
            err += "input depth: {} != {} :filter depth".format(ic, fc)
            raise ValueError(err)

        for i, sy, sx in ((idx, shy, shx) for shx in range(ox) for shy in range(oy) for idx in range(im)):
            rfields[i][sy*ox + sx] = A[i, :, sy:sy+fy, sx:sx+fx].ravel()

        # output = np.zeros((im, oy*ox, nf))
        # for m in range(im):
        #     output[m] = np.dot(rfields[m], Frsh.T)

        output = np.matmul(rfields, Frsh.T)
        output = output.transpose((0, 2, 1)).reshape((im, nf, oy, ox))
        return output 
开发者ID:csxeba,项目名称:brainforge,代码行数:26,代码来源:tensor_op.py

示例11: _parse_gufunc_signature

# 需要导入模块: import numpy [as 别名]
# 或者: from numpy import matmul [as 别名]
def _parse_gufunc_signature(signature):
    """
    Parse string signatures for a generalized universal function.

    Arguments
    ---------
    signature : string
        Generalized universal function signature, e.g., ``(m,n),(n,p)->(m,p)``
        for ``np.matmul``.

    Returns
    -------
    Tuple of input and output core dimensions parsed from the signature, each
    of the form List[Tuple[str, ...]].
    """
    if not re.match(_SIGNATURE, signature):
        raise ValueError(
            'not a valid gufunc signature: {}'.format(signature))
    return tuple([tuple(re.findall(_DIMENSION_NAME, arg))
                  for arg in re.findall(_ARGUMENT, arg_list)]
                 for arg_list in signature.split('->')) 
开发者ID:Frank-qlu,项目名称:recruit,代码行数:23,代码来源:function_base.py

示例12: test_basic_property

# 需要导入模块: import numpy [as 别名]
# 或者: from numpy import matmul [as 别名]
def test_basic_property(self):
        # Check A = L L^H
        shapes = [(1, 1), (2, 2), (3, 3), (50, 50), (3, 10, 10)]
        dtypes = (np.float32, np.float64, np.complex64, np.complex128)

        for shape, dtype in itertools.product(shapes, dtypes):
            np.random.seed(1)
            a = np.random.randn(*shape)
            if np.issubdtype(dtype, np.complexfloating):
                a = a + 1j*np.random.randn(*shape)

            t = list(range(len(shape)))
            t[-2:] = -1, -2

            a = np.matmul(a.transpose(t).conj(), a)
            a = np.asarray(a, dtype=dtype)

            c = np.linalg.cholesky(a)

            b = np.matmul(c, c.transpose(t).conj())
            assert_allclose(b, a,
                            err_msg="{} {}\n{}\n{}".format(shape, dtype, a, c),
                            atol=500 * a.shape[0] * np.finfo(dtype).eps) 
开发者ID:Frank-qlu,项目名称:recruit,代码行数:25,代码来源:test_linalg.py

示例13: dictionary_update

# 需要导入模块: import numpy [as 别名]
# 或者: from numpy import matmul [as 别名]
def dictionary_update(self, Y: np.ndarray):
        # iterate rows
        D = self.dictionary.matrix
        n, K = D.shape
        for k in range(K):
            wk = np.nonzero(self.alphas[k, :])[0]
            if len(wk) == 0:
                continue
            D[:, k] = 0
            g = np.transpose(self.alphas)[wk, k]
            d = np.matmul(Y[:, wk], g) - np.matmul(D, self.alphas[:, wk]).dot(g)
            d = d / np.linalg.norm(d)
            g = np.matmul(Y[:, wk].T, d) - np.transpose(np.matmul(D, self.alphas[:, wk])).dot(d)
            D[:, k] = d
            self.alphas[k, wk] = g.T
        self.dictionary = Dictionary(D) 
开发者ID:fubel,项目名称:sparselandtools,代码行数:18,代码来源:learning.py

示例14: rgb2ycbcr

# 需要导入模块: import numpy [as 别名]
# 或者: from numpy import matmul [as 别名]
def rgb2ycbcr(img, only_y=True):
    '''same as matlab rgb2ycbcr
    only_y: only return Y channel
    Input:
        uint8, [0, 255]
        float, [0, 1]
    '''
    in_img_type = img.dtype
    img.astype(np.float32)
    if in_img_type != np.uint8:
        img *= 255.
    # convert
    if only_y:
        rlt = np.dot(img, [65.481, 128.553, 24.966]) / 255.0 + 16.0
    else:
        rlt = np.matmul(img, [[65.481, -37.797, 112.0], [128.553, -74.203, -93.786],
                              [24.966, 112.0, -18.214]]) / 255.0 + [16, 128, 128]
    if in_img_type == np.uint8:
        rlt = rlt.round()
    else:
        rlt /= 255.
    return rlt.astype(in_img_type) 
开发者ID:cszn,项目名称:KAIR,代码行数:24,代码来源:utils_image.py

示例15: ycbcr2rgb

# 需要导入模块: import numpy [as 别名]
# 或者: from numpy import matmul [as 别名]
def ycbcr2rgb(img):
    '''same as matlab ycbcr2rgb
    Input:
        uint8, [0, 255]
        float, [0, 1]
    '''
    in_img_type = img.dtype
    img.astype(np.float32)
    if in_img_type != np.uint8:
        img *= 255.
    # convert
    rlt = np.matmul(img, [[0.00456621, 0.00456621, 0.00456621], [0, -0.00153632, 0.00791071],
                          [0.00625893, -0.00318811, 0]]) * 255.0 + [-222.921, 135.576, -276.836]
    if in_img_type == np.uint8:
        rlt = rlt.round()
    else:
        rlt /= 255.
    return rlt.astype(in_img_type) 
开发者ID:cszn,项目名称:KAIR,代码行数:20,代码来源:utils_image.py


注:本文中的numpy.matmul方法示例由纯净天空整理自Github/MSDocs等开源代码及文档管理平台,相关代码片段筛选自各路编程大神贡献的开源项目,源码版权归原作者所有,传播和使用请参考对应项目的License;未经允许,请勿转载。