本文整理汇总了Python中nltk.tag.util.str2tuple方法的典型用法代码示例。如果您正苦于以下问题：Python util.str2tuple方法的具体用法？Python util.str2tuple怎么用？Python util.str2tuple使用的例子？那么恭喜您, 这里精选的方法代码示例或许可以为您提供帮助。您也可以进一步了解该方法所在类nltk.tag.util的用法示例。
在下文中一共展示了util.str2tuple方法的3个代码示例，这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞，您的评价将有助于系统推荐出更棒的Python代码示例。
示例1: tagstr2tree
# 需要导入模块: from nltk.tag import util [as 别名]
# 或者: from nltk.tag.util import str2tuple [as 别名]
def tagstr2tree(s, chunk_label="NP", root_label="S", sep='/',
source_tagset=None, target_tagset=None):
"""
Divide a string of bracketted tagged text into
chunks and unchunked tokens, and produce a Tree.
Chunks are marked by square brackets (``[...]``). Words are
delimited by whitespace, and each word should have the form
``text/tag``. Words that do not contain a slash are
assigned a ``tag`` of None.
:param s: The string to be converted
:type s: str
:param chunk_label: The label to use for chunk nodes
:type chunk_label: str
:param root_label: The label to use for the root of the tree
:type root_label: str
:rtype: Tree
"""
WORD_OR_BRACKET = re.compile(r'\[|\]|[^\[\]\s]+')
stack = [Tree(root_label, [])]
for match in WORD_OR_BRACKET.finditer(s):
text = match.group()
if text[0] == '[':
if len(stack) != 1:
raise ValueError('Unexpected [ at char %d' % match.start())
chunk = Tree(chunk_label, [])
stack[-1].append(chunk)
stack.append(chunk)
elif text[0] == ']':
if len(stack) != 2:
raise ValueError('Unexpected ] at char %d' % match.start())
stack.pop()
else:
if sep is None:
stack[-1].append(text)
else:
word, tag = str2tuple(text, sep)
if source_tagset and target_tagset:
tag = map_tag(source_tagset, target_tagset, tag)
stack[-1].append((word, tag))
if len(stack) != 1:
raise ValueError('Expected ] at char %d' % len(s))
return stack[0]
### CONLL 示例2: tagstr2tree
# 需要导入模块: from nltk.tag import util [as 别名]
# 或者: from nltk.tag.util import str2tuple [as 别名]
def tagstr2tree(s, chunk_label="NP", root_label="S", sep='/',
source_tagset=None, target_tagset=None):
"""
Divide a string of bracketted tagged text into
chunks and unchunked tokens, and produce a Tree.
Chunks are marked by square brackets (``[...]``). Words are
delimited by whitespace, and each word should have the form
``text/tag``. Words that do not contain a slash are
assigned a ``tag`` of None.
:param s: The string to be converted
:type s: str
:param chunk_label: The label to use for chunk nodes
:type chunk_label: str
:param root_label: The label to use for the root of the tree
:type root_label: str
:rtype: Tree
"""
WORD_OR_BRACKET = re.compile(r'\[|\]|[^\[\]\s]+')
stack = [Tree(root_label, [])]
for match in WORD_OR_BRACKET.finditer(s):
text = match.group()
if text[0] == '[':
if len(stack) != 1:
raise ValueError('Unexpected [ at char {:d}'.format(match.start()))
chunk = Tree(chunk_label, [])
stack[-1].append(chunk)
stack.append(chunk)
elif text[0] == ']':
if len(stack) != 2:
raise ValueError('Unexpected ] at char {:d}'.format(match.start()))
stack.pop()
else:
if sep is None:
stack[-1].append(text)
else:
word, tag = str2tuple(text, sep)
if source_tagset and target_tagset:
tag = map_tag(source_tagset, target_tagset, tag)
stack[-1].append((word, tag))
if len(stack) != 1:
raise ValueError('Expected ] at char {:d}'.format(len(s)))
return stack[0]
### CONLL 示例3: tagstr2tree
# 需要导入模块: from nltk.tag import util [as 别名]
# 或者: from nltk.tag.util import str2tuple [as 别名]
def tagstr2tree(s, chunk_label="NP", root_label="S", sep='/'):
"""
Divide a string of bracketted tagged text into
chunks and unchunked tokens, and produce a Tree.
Chunks are marked by square brackets (``[...]``). Words are
delimited by whitespace, and each word should have the form
``text/tag``. Words that do not contain a slash are
assigned a ``tag`` of None.
:param s: The string to be converted
:type s: str
:param chunk_label: The label to use for chunk nodes
:type chunk_label: str
:param root_label: The label to use for the root of the tree
:type root_label: str
:rtype: Tree
"""
WORD_OR_BRACKET = re.compile(r'\[|\]|[^\[\]\s]+')
stack = [Tree(root_label, [])]
for match in WORD_OR_BRACKET.finditer(s):
text = match.group()
if text[0] == '[':
if len(stack) != 1:
raise ValueError('Unexpected [ at char %d' % match.start())
chunk = Tree(chunk_label, [])
stack[-1].append(chunk)
stack.append(chunk)
elif text[0] == ']':
if len(stack) != 2:
raise ValueError('Unexpected ] at char %d' % match.start())
stack.pop()
else:
if sep is None:
stack[-1].append(text)
else:
stack[-1].append(str2tuple(text, sep))
if len(stack) != 1:
raise ValueError('Expected ] at char %d' % len(s))
return stack[0]
### CONLL