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Python itertools.takewhile方法代码示例

本文整理汇总了Python中itertools.takewhile方法的典型用法代码示例。如果您正苦于以下问题:Python itertools.takewhile方法的具体用法?Python itertools.takewhile怎么用?Python itertools.takewhile使用的例子?那么, 这里精选的方法代码示例或许可以为您提供帮助。您也可以进一步了解该方法所在itertools的用法示例。


在下文中一共展示了itertools.takewhile方法的8个代码示例,这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞,您的评价将有助于系统推荐出更棒的Python代码示例。

示例1: check_no_blank_before

# 需要导入模块: import itertools [as 别名]
# 或者: from itertools import takewhile [as 别名]
def check_no_blank_before(self, function, docstring):  # def
        """D20{1,2}: No blank lines allowed around function/method docstring.

        There's no blank line either before or after the docstring.

        """
        if docstring:
            before, _, after = function.source.partition(docstring)
            blanks_before = list(map(is_blank, before.split('\n')[:-1]))
            blanks_after = list(map(is_blank, after.split('\n')[1:]))
            blanks_before_count = sum(takewhile(bool, reversed(blanks_before)))
            blanks_after_count = sum(takewhile(bool, blanks_after))
            if blanks_before_count != 0:
                yield violations.D201(blanks_before_count)
            if not all(blanks_after) and blanks_after_count != 0:
                yield violations.D202(blanks_after_count) 
开发者ID:AtomLinter,项目名称:linter-pylama,代码行数:18,代码来源:checker.py

示例2: check_blank_after_summary

# 需要导入模块: import itertools [as 别名]
# 或者: from itertools import takewhile [as 别名]
def check_blank_after_summary(self, definition, docstring):
        """D205: Put one blank line between summary line and description.

        Multi-line docstrings consist of a summary line just like a one-line
        docstring, followed by a blank line, followed by a more elaborate
        description. The summary line may be used by automatic indexing tools;
        it is important that it fits on one line and is separated from the
        rest of the docstring by a blank line.

        """
        if docstring:
            lines = ast.literal_eval(docstring).strip().split('\n')
            if len(lines) > 1:
                post_summary_blanks = list(map(is_blank, lines[1:]))
                blanks_count = sum(takewhile(bool, post_summary_blanks))
                if blanks_count != 1:
                    return violations.D205(blanks_count) 
开发者ID:AtomLinter,项目名称:linter-pylama,代码行数:19,代码来源:checker.py

示例3: _compare_compatible

# 需要导入模块: import itertools [as 别名]
# 或者: from itertools import takewhile [as 别名]
def _compare_compatible(self, prospective, spec):
        # Compatible releases have an equivalent combination of >= and ==. That
        # is that ~=2.2 is equivalent to >=2.2,==2.*. This allows us to
        # implement this in terms of the other specifiers instead of
        # implementing it ourselves. The only thing we need to do is construct
        # the other specifiers.

        # We want everything but the last item in the version, but we want to
        # ignore post and dev releases and we want to treat the pre-release as
        # it's own separate segment.
        prefix = ".".join(
            list(
                itertools.takewhile(
                    lambda x: (not x.startswith("post") and not
                               x.startswith("dev")),
                    _version_split(spec),
                )
            )[:-1]
        )

        # Add the prefix notation to the end of our string
        prefix += ".*"

        return (self._get_operator(">=")(prospective, spec) and
                self._get_operator("==")(prospective, prefix)) 
开发者ID:Frank-qlu,项目名称:recruit,代码行数:27,代码来源:specifiers.py

示例4: _pad_version

# 需要导入模块: import itertools [as 别名]
# 或者: from itertools import takewhile [as 别名]
def _pad_version(left, right):
    left_split, right_split = [], []

    # Get the release segment of our versions
    left_split.append(list(itertools.takewhile(lambda x: x.isdigit(), left)))
    right_split.append(list(itertools.takewhile(lambda x: x.isdigit(), right)))

    # Get the rest of our versions
    left_split.append(left[len(left_split[0]):])
    right_split.append(right[len(right_split[0]):])

    # Insert our padding
    left_split.insert(
        1,
        ["0"] * max(0, len(right_split[0]) - len(left_split[0])),
    )
    right_split.insert(
        1,
        ["0"] * max(0, len(left_split[0]) - len(right_split[0])),
    )

    return (
        list(itertools.chain(*left_split)),
        list(itertools.chain(*right_split)),
    ) 
开发者ID:Frank-qlu,项目名称:recruit,代码行数:27,代码来源:specifiers.py

示例5: _compare_compatible

# 需要导入模块: import itertools [as 别名]
# 或者: from itertools import takewhile [as 别名]
def _compare_compatible(self, prospective, spec):
        # Compatible releases have an equivalent combination of >= and ==. That
        # is that ~=2.2 is equivalent to >=2.2,==2.*. This allows us to
        # implement this in terms of the other specifiers instead of
        # implementing it ourselves. The only thing we need to do is construct
        # the other specifiers.

        # We want everything but the last item in the version, but we want to
        # ignore post and dev releases and we want to treat the pre-release as
        # it's own separate segment.
        prefix = ".".join(
            list(
                itertools.takewhile(
                    lambda x: (not x.startswith("post") and not x.startswith("dev")),
                    _version_split(spec),
                )
            )[:-1]
        )

        # Add the prefix notation to the end of our string
        prefix += ".*"

        return self._get_operator(">=")(prospective, spec) and self._get_operator("==")(
            prospective, prefix
        ) 
开发者ID:sofia-netsurv,项目名称:python-netsurv,代码行数:27,代码来源:specifiers.py

示例6: _pad_version

# 需要导入模块: import itertools [as 别名]
# 或者: from itertools import takewhile [as 别名]
def _pad_version(left, right):
    left_split, right_split = [], []

    # Get the release segment of our versions
    left_split.append(list(itertools.takewhile(lambda x: x.isdigit(), left)))
    right_split.append(list(itertools.takewhile(lambda x: x.isdigit(), right)))

    # Get the rest of our versions
    left_split.append(left[len(left_split[0]) :])
    right_split.append(right[len(right_split[0]) :])

    # Insert our padding
    left_split.insert(1, ["0"] * max(0, len(right_split[0]) - len(left_split[0])))
    right_split.insert(1, ["0"] * max(0, len(left_split[0]) - len(right_split[0])))

    return (list(itertools.chain(*left_split)), list(itertools.chain(*right_split))) 
开发者ID:sofia-netsurv,项目名称:python-netsurv,代码行数:18,代码来源:specifiers.py

示例7: _compare_compatible

# 需要导入模块: import itertools [as 别名]
# 或者: from itertools import takewhile [as 别名]
def _compare_compatible(self, prospective, spec):
        # Compatible releases have an equivalent combination of >= and ==. That
        # is that ~=2.2 is equivalent to >=2.2,==2.*. This allows us to
        # implement this in terms of the other specifiers instead of
        # implementing it ourselves. The only thing we need to do is construct
        # the other specifiers.

        # We want everything but the last item in the version, but we want to
        # ignore post and dev releases and we want to treat the pre-release as
        # it's own separate segment.
        prefix = ".".join(
            list(
                itertools.takewhile(
                    lambda x: (not x.startswith("post")
                               and not x.startswith("dev")),
                    _version_split(spec),
                )
            )[:-1]
        )

        # Add the prefix notation to the end of our string
        prefix += ".*"

        return (self._get_operator(">=")(prospective, spec)
                and self._get_operator("==")(prospective, prefix)) 
开发者ID:awslabs,项目名称:lambda-chef-node-cleanup,代码行数:27,代码来源:specifiers.py

示例8: _pad_version

# 需要导入模块: import itertools [as 别名]
# 或者: from itertools import takewhile [as 别名]
def _pad_version(left, right):
    left_split, right_split = [], []

    # Get the release segment of our versions
    left_split.append(list(itertools.takewhile(lambda x: x.isdigit(), left)))
    right_split.append(list(itertools.takewhile(lambda x: x.isdigit(), right)))

    # Get the rest of our versions
    left_split.append(left[len(left_split):])
    right_split.append(left[len(right_split):])

    # Insert our padding
    left_split.insert(
        1,
        ["0"] * max(0, len(right_split[0]) - len(left_split[0])),
    )
    right_split.insert(
        1,
        ["0"] * max(0, len(left_split[0]) - len(right_split[0])),
    )

    return (
        list(itertools.chain(*left_split)),
        list(itertools.chain(*right_split)),
    ) 
开发者ID:awslabs,项目名称:lambda-chef-node-cleanup,代码行数:27,代码来源:specifiers.py


注:本文中的itertools.takewhile方法示例由纯净天空整理自Github/MSDocs等开源代码及文档管理平台,相关代码片段筛选自各路编程大神贡献的开源项目,源码版权归原作者所有,传播和使用请参考对应项目的License;未经允许,请勿转载。