本文整理汇总了Python中framework.framework_info方法的典型用法代码示例。如果您正苦于以下问题：Python framework.framework_info方法的具体用法？Python framework.framework_info怎么用？Python framework.framework_info使用的例子？那么恭喜您, 这里精选的方法代码示例或许可以为您提供帮助。您也可以进一步了解该方法所在类framework的用法示例。
在下文中一共展示了framework.framework_info方法的2个代码示例，这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞，您的评价将有助于系统推荐出更棒的Python代码示例。
示例1: dyld_override_search
# 需要导入模块: import framework [as 别名]
# 或者: from framework import framework_info [as 别名]
def dyld_override_search(name, env=None):
# If DYLD_FRAMEWORK_PATH is set and this dylib_name is a
# framework name, use the first file that exists in the framework
# path if any. If there is none go on to search the DYLD_LIBRARY_PATH
# if any.
framework = framework_info(name)
if framework is not None:
for path in dyld_framework_path(env):
yield os.path.join(path, framework['name'])
# If DYLD_LIBRARY_PATH is set then use the first file that exists
# in the path. If none use the original name.
for path in dyld_library_path(env):
yield os.path.join(path, os.path.basename(name)) 示例2: dyld_default_search
# 需要导入模块: import framework [as 别名]
# 或者: from framework import framework_info [as 别名]
def dyld_default_search(name, env=None):
yield name
framework = framework_info(name)
if framework is not None:
fallback_framework_path = dyld_fallback_framework_path(env)
for path in fallback_framework_path:
yield os.path.join(path, framework['name'])
fallback_library_path = dyld_fallback_library_path(env)
for path in fallback_library_path:
yield os.path.join(path, os.path.basename(name))
if framework is not None and not fallback_framework_path:
for path in DEFAULT_FRAMEWORK_FALLBACK:
yield os.path.join(path, framework['name'])
if not fallback_library_path:
for path in DEFAULT_LIBRARY_FALLBACK:
yield os.path.join(path, os.path.basename(name))