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Python base64mime.body_encode方法代码示例

本文整理汇总了Python中email.base64mime.body_encode方法的典型用法代码示例。如果您正苦于以下问题:Python base64mime.body_encode方法的具体用法?Python base64mime.body_encode怎么用?Python base64mime.body_encode使用的例子?那么恭喜您, 这里精选的方法代码示例或许可以为您提供帮助。您也可以进一步了解该方法所在email.base64mime的用法示例。


在下文中一共展示了base64mime.body_encode方法的7个代码示例,这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞,您的评价将有助于系统推荐出更棒的Python代码示例。

示例1: test_encode

# 需要导入模块: from email import base64mime [as 别名]
# 或者: from email.base64mime import body_encode [as 别名]
def test_encode(self):
        eq = self.assertEqual
        eq(base64mime.body_encode(b''), b'')
        eq(base64mime.body_encode(b'hello'), 'aGVsbG8=\n')
        # Test the binary flag
        eq(base64mime.body_encode(b'hello\n'), 'aGVsbG8K\n')
        # Test the maxlinelen arg
        eq(base64mime.body_encode(b'xxxx ' * 20, maxlinelen=40), """\
eHh4eCB4eHh4IHh4eHggeHh4eCB4eHh4IHh4eHgg
eHh4eCB4eHh4IHh4eHggeHh4eCB4eHh4IHh4eHgg
eHh4eCB4eHh4IHh4eHggeHh4eCB4eHh4IHh4eHgg
eHh4eCB4eHh4IA==
""")
        # Test the eol argument
        eq(base64mime.body_encode(b'xxxx ' * 20, maxlinelen=40, eol='\r\n'),
           """\
eHh4eCB4eHh4IHh4eHggeHh4eCB4eHh4IHh4eHgg\r
eHh4eCB4eHh4IHh4eHggeHh4eCB4eHh4IHh4eHgg\r
eHh4eCB4eHh4IHh4eHggeHh4eCB4eHh4IHh4eHgg\r
eHh4eCB4eHh4IA==\r
""") 
开发者ID:IronLanguages,项目名称:ironpython3,代码行数:23,代码来源:test_email.py

示例2: _test_encode

# 需要导入模块: from email import base64mime [as 别名]
# 或者: from email.base64mime import body_encode [as 别名]
def _test_encode(self, body, expected_encoded_body, maxlinelen=None, eol=None):
        kwargs = {}
        if maxlinelen is None:
            # Use body_encode's default.
            maxlinelen = 76
        else:
            kwargs['maxlinelen'] = maxlinelen
        if eol is None:
            # Use body_encode's default.
            eol = '\n'
        else:
            kwargs['eol'] = eol
        encoded_body = quoprimime.body_encode(body, **kwargs)
        self.assertEqual(encoded_body, expected_encoded_body)
        if eol == '\n' or eol == '\r\n':
            # We know how to split the result back into lines, so maxlinelen
            # can be checked.
            for line in encoded_body.splitlines():
                self.assertLessEqual(len(line), maxlinelen) 
开发者ID:IronLanguages,项目名称:ironpython3,代码行数:21,代码来源:test_email.py

示例3: auth

# 需要导入模块: from email import base64mime [as 别名]
# 或者: from email.base64mime import body_encode [as 别名]
def auth(self, mechanism, authobject, *, initial_response_ok=True):
        """Authentication command - requires response processing.

        'mechanism' specifies which authentication mechanism is to
        be used - the valid values are those listed in the 'auth'
        element of 'esmtp_features'.

        'authobject' must be a callable object taking a single argument:

                data = authobject(challenge)

        It will be called to process the server's challenge response; the
        challenge argument it is passed will be a bytes.  It should return
        bytes data that will be base64 encoded and sent to the server.

        Keyword arguments:
            - initial_response_ok: Allow sending the RFC 4954 initial-response
              to the AUTH command, if the authentication methods supports it.
        """
        # RFC 4954 allows auth methods to provide an initial response.  Not all
        # methods support it.  By definition, if they return something other
        # than None when challenge is None, then they do.  See issue #15014.
        mechanism = mechanism.upper()
        initial_response = (authobject() if initial_response_ok else None)
        if initial_response is not None:
            response = encode_base64(initial_response.encode('ascii'), eol='')
            (code, resp) = self.docmd("AUTH", mechanism + " " + response)
        else:
            (code, resp) = self.docmd("AUTH", mechanism)
        # If server responds with a challenge, send the response.
        if code == 334:
            challenge = base64.decodebytes(resp)
            response = encode_base64(
                authobject(challenge).encode('ascii'), eol='')
            (code, resp) = self.docmd(response)
        if code in (235, 503):
            return (code, resp)
        raise SMTPAuthenticationError(code, resp) 
开发者ID:Microvellum,项目名称:Fluid-Designer,代码行数:40,代码来源:smtplib.py

示例4: auth

# 需要导入模块: from email import base64mime [as 别名]
# 或者: from email.base64mime import body_encode [as 别名]
def auth(self, mechanism, authobject, *, initial_response_ok=True):
        """Authentication command - requires response processing.

        'mechanism' specifies which authentication mechanism is to
        be used - the valid values are those listed in the 'auth'
        element of 'esmtp_features'.

        'authobject' must be a callable object taking a single argument:

                data = authobject(challenge)

        It will be called to process the server's challenge response; the
        challenge argument it is passed will be a bytes.  It should return
        an ASCII string that will be base64 encoded and sent to the server.

        Keyword arguments:
            - initial_response_ok: Allow sending the RFC 4954 initial-response
              to the AUTH command, if the authentication methods supports it.
        """
        # RFC 4954 allows auth methods to provide an initial response.  Not all
        # methods support it.  By definition, if they return something other
        # than None when challenge is None, then they do.  See issue #15014.
        mechanism = mechanism.upper()
        initial_response = (authobject() if initial_response_ok else None)
        if initial_response is not None:
            response = encode_base64(initial_response.encode('ascii'), eol='')
            (code, resp) = self.docmd("AUTH", mechanism + " " + response)
        else:
            (code, resp) = self.docmd("AUTH", mechanism)
        # If server responds with a challenge, send the response.
        if code == 334:
            challenge = base64.decodebytes(resp)
            response = encode_base64(
                authobject(challenge).encode('ascii'), eol='')
            (code, resp) = self.docmd(response)
        if code in (235, 503):
            return (code, resp)
        raise SMTPAuthenticationError(code, resp) 
开发者ID:CedricGuillemet,项目名称:Imogen,代码行数:40,代码来源:smtplib.py

示例5: test_len

# 需要导入模块: from email import base64mime [as 别名]
# 或者: from email.base64mime import body_encode [as 别名]
def test_len(self):
        eq = self.assertEqual
        eq(base64mime.header_length('hello'),
           len(base64mime.body_encode(b'hello', eol='')))
        for size in range(15):
            if   size == 0 : bsize = 0
            elif size <= 3 : bsize = 4
            elif size <= 6 : bsize = 8
            elif size <= 9 : bsize = 12
            elif size <= 12: bsize = 16
            else           : bsize = 20
            eq(base64mime.header_length('x' * size), bsize) 
开发者ID:IronLanguages,项目名称:ironpython3,代码行数:14,代码来源:test_email.py

示例6: test_encode_one_line_one_space

# 需要导入模块: from email import base64mime [as 别名]
# 或者: from email.base64mime import body_encode [as 别名]
def test_encode_one_line_one_space(self):
        self._test_encode(' \n', '=20\n')

# XXX: body_encode() expect strings, but uses ord(char) from these strings
# to index into a 256-entry list.  For code points above 255, this will fail.
# Should there be a check for 8-bit only ord() values in body, or at least
# a comment about the expected input? 
开发者ID:IronLanguages,项目名称:ironpython3,代码行数:9,代码来源:test_email.py

示例7: login

# 需要导入模块: from email import base64mime [as 别名]
# 或者: from email.base64mime import body_encode [as 别名]
def login(self, username, password):
        def encode_cram_md5(challenge, username, password): 
            challenge = base64.decodebytes(challenge)
            response = username + " " + hmac.HMAC(password.encode('ascii'), challenge, 'md5').hexdigest()
            return encode_base64(response.encode('ascii'), eol="")

        def encode_plain(user, password): 
            return encode_base64(("\0%s\0%s" % (user, password)).encode('ascii'), eol="")

        AUTH_PLAIN = "PLAIN"
        AUTH_CRAM_MD5 = "CRAM-MD5"
        AUTH_LOGIN = "LOGIN"

        yield self.ehlo_or_helo_if_needed()
        if not self.has_extn('auth'):
            raise smtplib.SMTPException("SMTP Auth extension not supported by server ")

        advertised_authlist = self.esmtp_features["auth"].split()

        preferred_auths = [AUTH_CRAM_MD5, AUTH_PLAIN, AUTH_LOGIN]

        authlist = [auth for auth in preferred_auths if auth in advertised_authlist]
        if not authlist:
            raise smtplib.SMTPException("No suitable authentication method found.")

        # Some servers advertise authentication methods they don't really
        # support, so if authentication fails, we continue until we've tried
        # all methods.
        for authmethod in authlist:
            if authmethod == AUTH_CRAM_MD5:
                (code, resp) = yield self.docmd(b'AUTH', AUTH_CRAM_MD5)
                if code == 334:
                    (code, resp) =yield self.docmd(encode_cram_md5(resp, username, password).encode('ascii'))
            elif authmethod == AUTH_PLAIN:
                (code, resp) =yield self.docmd(b'AUTH',
                 (AUTH_PLAIN + " " + encode_plain(username, password)).encode('ascii'))
            elif authmethod == AUTH_LOGIN:
                (code, resp) = yield self.docmd(b'AUTH',
                ("%s %s" % (AUTH_LOGIN, encode_base64(username.encode('ascii'), eol=''))).encode('ascii'))
                if code == 334:
                    (code, resp) = yield self.docmd(encode_base64(password.encode('ascii'), eol='').encode('ascii'))

            # 235 == 'Authentication successful'
            # 503 == 'Error: already authenticated'
            if code in (235, 503):
                return (code, resp)

        # We could not login sucessfully. Return result of last attempt.
        raise smtplib.SMTPAuthenticationError(code, resp) 
开发者ID:vuamitom,项目名称:tornado-smtpclient,代码行数:51,代码来源:client.py


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