本文整理汇总了Python中email.Utils.parsedate_tz方法的典型用法代码示例。如果您正苦于以下问题：Python Utils.parsedate_tz方法的具体用法？Python Utils.parsedate_tz怎么用？Python Utils.parsedate_tz使用的例子？那么恭喜您, 这里精选的方法代码示例或许可以为您提供帮助。您也可以进一步了解该方法所在类email.Utils的用法示例。
在下文中一共展示了Utils.parsedate_tz方法的7个代码示例，这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞，您的评价将有助于系统推荐出更棒的Python代码示例。
示例1: parse_date
# 需要导入模块: from email import Utils [as 别名]
# 或者: from email.Utils import parsedate_tz [as 别名]
def parse_date(value):
"""Parse one of the following date formats into a datetime object:
.. sourcecode:: text
Sun, 06 Nov 1994 08:49:37 GMT ; RFC 822, updated by RFC 1123
Sunday, 06-Nov-94 08:49:37 GMT ; RFC 850, obsoleted by RFC 1036
Sun Nov 6 08:49:37 1994 ; ANSI C's asctime() format
If parsing fails the return value is `None`.
:param value: a string with a supported date format.
:return: a :class:`datetime.datetime` object.
"""
if value:
t = parsedate_tz(value.strip())
if t is not None:
try:
year = t[0]
# unfortunately that function does not tell us if two digit
# years were part of the string, or if they were prefixed
# with two zeroes. So what we do is to assume that 69-99
# refer to 1900, and everything below to 2000
if year >= 0 and year <= 68:
year += 2000
elif year >= 69 and year <= 99:
year += 1900
return datetime(*((year,) + t[1:7])) - timedelta(seconds=t[-1] or 0)
except (ValueError, OverflowError):
return None 示例2: parse_date
# 需要导入模块: from email import Utils [as 别名]
# 或者: from email.Utils import parsedate_tz [as 别名]
def parse_date(value):
"""Parse one of the following date formats into a datetime object:
.. sourcecode:: text
Sun, 06 Nov 1994 08:49:37 GMT ; RFC 822, updated by RFC 1123
Sunday, 06-Nov-94 08:49:37 GMT ; RFC 850, obsoleted by RFC 1036
Sun Nov 6 08:49:37 1994 ; ANSI C's asctime() format
If parsing fails the return value is `None`.
:param value: a string with a supported date format.
:return: a :class:`datetime.datetime` object.
"""
if value:
t = parsedate_tz(value.strip())
if t is not None:
try:
year = t[0]
# unfortunately that function does not tell us if two digit
# years were part of the string, or if they were prefixed
# with two zeroes. So what we do is to assume that 69-99
# refer to 1900, and everything below to 2000
if year >= 0 and year <= 68:
year += 2000
elif year >= 69 and year <= 99:
year += 1900
return datetime(*((year,) + t[1:7])) - \
timedelta(seconds=t[-1] or 0)
except (ValueError, OverflowError):
return None 示例3: test_parsedate_no_dayofweek
# 需要导入模块: from email import Utils [as 别名]
# 或者: from email.Utils import parsedate_tz [as 别名]
def test_parsedate_no_dayofweek(self):
eq = self.assertEqual
eq(Utils.parsedate_tz('25 Feb 2003 13:47:26 -0800'),
(2003, 2, 25, 13, 47, 26, 0, 1, -1, -28800)) 示例4: test_parsedate_compact_no_dayofweek
# 需要导入模块: from email import Utils [as 别名]
# 或者: from email.Utils import parsedate_tz [as 别名]
def test_parsedate_compact_no_dayofweek(self):
eq = self.assertEqual
eq(Utils.parsedate_tz('5 Feb 2003 13:47:26 -0800'),
(2003, 2, 5, 13, 47, 26, 0, 1, -1, -28800)) 示例5: test_parsedate_acceptable_to_time_functions
# 需要导入模块: from email import Utils [as 别名]
# 或者: from email.Utils import parsedate_tz [as 别名]
def test_parsedate_acceptable_to_time_functions(self):
eq = self.assertEqual
timetup = Utils.parsedate('5 Feb 2003 13:47:26 -0800')
t = int(time.mktime(timetup))
eq(time.localtime(t)[:6], timetup[:6])
eq(int(time.strftime('%Y', timetup)), 2003)
timetup = Utils.parsedate_tz('5 Feb 2003 13:47:26 -0800')
t = int(time.mktime(timetup[:9]))
eq(time.localtime(t)[:6], timetup[:6])
eq(int(time.strftime('%Y', timetup[:9])), 2003) 示例6: test_parsedate_y2k
# 需要导入模块: from email import Utils [as 别名]
# 或者: from email.Utils import parsedate_tz [as 别名]
def test_parsedate_y2k(self):
"""Test for parsing a date with a two-digit year.
Parsing a date with a two-digit year should return the correct
four-digit year. RFC822 allows two-digit years, but RFC2822 (which
obsoletes RFC822) requires four-digit years.
"""
self.assertEqual(Utils.parsedate_tz('25 Feb 03 13:47:26 -0800'),
Utils.parsedate_tz('25 Feb 2003 13:47:26 -0800'))
self.assertEqual(Utils.parsedate_tz('25 Feb 71 13:47:26 -0800'),
Utils.parsedate_tz('25 Feb 1971 13:47:26 -0800')) 示例7: parse_date
# 需要导入模块: from email import Utils [as 别名]
# 或者: from email.Utils import parsedate_tz [as 别名]
def parse_date(value):
"""Parse one of the following date formats into a datetime object:
.. sourcecode:: text
Sun, 06 Nov 1994 08:49:37 GMT ; RFC 822, updated by RFC 1123
Sunday, 06-Nov-94 08:49:37 GMT ; RFC 850, obsoleted by RFC 1036
Sun Nov 6 08:49:37 1994 ; ANSI C's asctime() format
If parsing fails the return value is `None`.
:param value: a string with a supported date format.
:return: a :class:`datetime.datetime` object.
"""
if value:
t = parsedate_tz(value.strip())
if t is not None:
try:
year = t[0]
# unfortunately that function does not tell us if two digit
# years were part of the string, or if they were prefixed
# with two zeroes. So what we do is to assume that 69-99
# refer to 1900, and everything below to 2000
if year >= 0 and year <= 68:
year += 2000
elif year >= 69 and year <= 99:
year += 1900
return datetime(*((year,) + t[1:7])) - \
timedelta(seconds=t[-1] or 0)
except (ValueError, OverflowError):
return None