本文整理汇总了Python中datetime.timedelta.resolution方法的典型用法代码示例。如果您正苦于以下问题:Python timedelta.resolution方法的具体用法?Python timedelta.resolution怎么用?Python timedelta.resolution使用的例子?那么恭喜您, 这里精选的方法代码示例或许可以为您提供帮助。您也可以进一步了解该方法所在类datetime.timedelta
的用法示例。
在下文中一共展示了timedelta.resolution方法的7个代码示例,这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞,您的评价将有助于系统推荐出更棒的Python代码示例。
示例1: test_overflow
# 需要导入模块: from datetime import timedelta [as 别名]
# 或者: from datetime.timedelta import resolution [as 别名]
def test_overflow(self):
tiny = timedelta.resolution
td = timedelta.min + tiny
td -= tiny # no problem
self.assertRaises(OverflowError, td.__sub__, tiny)
self.assertRaises(OverflowError, td.__add__, -tiny)
td = timedelta.max - tiny
td += tiny # no problem
self.assertRaises(OverflowError, td.__add__, tiny)
self.assertRaises(OverflowError, td.__sub__, -tiny)
self.assertRaises(OverflowError, lambda: -timedelta.max)
day = timedelta(1)
self.assertRaises(OverflowError, day.__mul__, 10**9)
self.assertRaises(OverflowError, day.__mul__, 1e9)
self.assertRaises(OverflowError, day.__truediv__, 1e-20)
self.assertRaises(OverflowError, day.__truediv__, 1e-10)
self.assertRaises(OverflowError, day.__truediv__, 9e-10)
示例2: test_tz_independent_comparing
# 需要导入模块: from datetime import timedelta [as 别名]
# 或者: from datetime.timedelta import resolution [as 别名]
def test_tz_independent_comparing(self):
dt1 = self.theclass(2002, 3, 1, 9, 0, 0)
dt2 = self.theclass(2002, 3, 1, 10, 0, 0)
dt3 = self.theclass(2002, 3, 1, 9, 0, 0)
self.assertEqual(dt1, dt3)
self.assertTrue(dt2 > dt3)
# Make sure comparison doesn't forget microseconds, and isn't done
# via comparing a float timestamp (an IEEE double doesn't have enough
# precision to span microsecond resolution across years 1 thru 9999,
# so comparing via timestamp necessarily calls some distinct values
# equal).
dt1 = self.theclass(MAXYEAR, 12, 31, 23, 59, 59, 999998)
us = timedelta(microseconds=1)
dt2 = dt1 + us
self.assertEqual(dt2 - dt1, us)
self.assertTrue(dt1 < dt2)
示例3: test_resolution_info
# 需要导入模块: from datetime import timedelta [as 别名]
# 或者: from datetime.timedelta import resolution [as 别名]
def test_resolution_info(self):
self.assertIsInstance(timedelta.min, timedelta)
self.assertIsInstance(timedelta.max, timedelta)
self.assertIsInstance(timedelta.resolution, timedelta)
self.assertTrue(timedelta.max > timedelta.min)
self.assertEqual(timedelta.min, timedelta(-999999999))
self.assertEqual(timedelta.max, timedelta(999999999, 24*3600-1, 1e6-1))
self.assertEqual(timedelta.resolution, timedelta(0, 0, 1))
示例4: test_overflow
# 需要导入模块: from datetime import timedelta [as 别名]
# 或者: from datetime.timedelta import resolution [as 别名]
def test_overflow(self):
tiny = timedelta.resolution
td = timedelta.min + tiny
td -= tiny # no problem
self.assertRaises(OverflowError, td.__sub__, tiny)
self.assertRaises(OverflowError, td.__add__, -tiny)
td = timedelta.max - tiny
td += tiny # no problem
self.assertRaises(OverflowError, td.__add__, tiny)
self.assertRaises(OverflowError, td.__sub__, -tiny)
self.assertRaises(OverflowError, lambda: -timedelta.max)
示例5: test_today
# 需要导入模块: from datetime import timedelta [as 别名]
# 或者: from datetime.timedelta import resolution [as 别名]
def test_today(self):
import time
# We claim that today() is like fromtimestamp(time.time()), so
# prove it.
for dummy in range(3):
today = self.theclass.today()
ts = time.time()
todayagain = self.theclass.fromtimestamp(ts)
if today == todayagain:
break
# There are several legit reasons that could fail:
# 1. It recently became midnight, between the today() and the
# time() calls.
# 2. The platform time() has such fine resolution that we'll
# never get the same value twice.
# 3. The platform time() has poor resolution, and we just
# happened to call today() right before a resolution quantum
# boundary.
# 4. The system clock got fiddled between calls.
# In any case, wait a little while and try again.
time.sleep(0.1)
# It worked or it didn't. If it didn't, assume it's reason #2, and
# let the test pass if they're within half a second of each other.
if today != todayagain:
self.assertAlmostEqual(todayagain, today,
delta=timedelta(seconds=0.5))
示例6: test_today
# 需要导入模块: from datetime import timedelta [as 别名]
# 或者: from datetime.timedelta import resolution [as 别名]
def test_today(self):
import time
# We claim that today() is like fromtimestamp(time.time()), so
# prove it.
for dummy in range(3):
today = self.theclass.today()
ts = time.time()
todayagain = self.theclass.fromtimestamp(ts)
if today == todayagain:
break
# There are several legit reasons that could fail:
# 1. It recently became midnight, between the today() and the
# time() calls.
# 2. The platform time() has such fine resolution that we'll
# never get the same value twice.
# 3. The platform time() has poor resolution, and we just
# happened to call today() right before a resolution quantum
# boundary.
# 4. The system clock got fiddled between calls.
# In any case, wait a little while and try again.
time.sleep(0.1)
# It worked or it didn't. If it didn't, assume it's reason #2, and
# let the test pass if they're within half a second of each other.
self.assertTrue(today == todayagain or
abs(todayagain - today) < timedelta(seconds=0.5))
示例7: test_microsecond_rounding
# 需要导入模块: from datetime import timedelta [as 别名]
# 或者: from datetime.timedelta import resolution [as 别名]
def test_microsecond_rounding(self):
td = timedelta
eq = self.assertEqual
# Single-field rounding.
eq(td(milliseconds=0.4/1000), td(0)) # rounds to 0
eq(td(milliseconds=-0.4/1000), td(0)) # rounds to 0
eq(td(milliseconds=0.5/1000), td(microseconds=0))
eq(td(milliseconds=-0.5/1000), td(microseconds=-0))
eq(td(milliseconds=0.6/1000), td(microseconds=1))
eq(td(milliseconds=-0.6/1000), td(microseconds=-1))
eq(td(milliseconds=1.5/1000), td(microseconds=2))
eq(td(milliseconds=-1.5/1000), td(microseconds=-2))
eq(td(seconds=0.5/10**6), td(microseconds=0))
eq(td(seconds=-0.5/10**6), td(microseconds=-0))
eq(td(seconds=1/2**7), td(microseconds=7812))
eq(td(seconds=-1/2**7), td(microseconds=-7812))
# Rounding due to contributions from more than one field.
us_per_hour = 3600e6
us_per_day = us_per_hour * 24
eq(td(days=.4/us_per_day), td(0))
eq(td(hours=.2/us_per_hour), td(0))
eq(td(days=.4/us_per_day, hours=.2/us_per_hour), td(microseconds=1))
eq(td(days=-.4/us_per_day), td(0))
eq(td(hours=-.2/us_per_hour), td(0))
eq(td(days=-.4/us_per_day, hours=-.2/us_per_hour), td(microseconds=-1))
# Test for a patch in Issue 8860
eq(td(microseconds=0.5), 0.5*td(microseconds=1.0))
eq(td(microseconds=0.5)//td.resolution, 0.5*td.resolution//td.resolution)