当前位置: 首页>>代码示例>>Python>>正文


Python timedelta.resolution方法代码示例

本文整理汇总了Python中datetime.timedelta.resolution方法的典型用法代码示例。如果您正苦于以下问题:Python timedelta.resolution方法的具体用法?Python timedelta.resolution怎么用?Python timedelta.resolution使用的例子?那么恭喜您, 这里精选的方法代码示例或许可以为您提供帮助。您也可以进一步了解该方法所在datetime.timedelta的用法示例。


在下文中一共展示了timedelta.resolution方法的7个代码示例,这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞,您的评价将有助于系统推荐出更棒的Python代码示例。

示例1: test_overflow

# 需要导入模块: from datetime import timedelta [as 别名]
# 或者: from datetime.timedelta import resolution [as 别名]
def test_overflow(self):
        tiny = timedelta.resolution

        td = timedelta.min + tiny
        td -= tiny  # no problem
        self.assertRaises(OverflowError, td.__sub__, tiny)
        self.assertRaises(OverflowError, td.__add__, -tiny)

        td = timedelta.max - tiny
        td += tiny  # no problem
        self.assertRaises(OverflowError, td.__add__, tiny)
        self.assertRaises(OverflowError, td.__sub__, -tiny)

        self.assertRaises(OverflowError, lambda: -timedelta.max)

        day = timedelta(1)
        self.assertRaises(OverflowError, day.__mul__, 10**9)
        self.assertRaises(OverflowError, day.__mul__, 1e9)
        self.assertRaises(OverflowError, day.__truediv__, 1e-20)
        self.assertRaises(OverflowError, day.__truediv__, 1e-10)
        self.assertRaises(OverflowError, day.__truediv__, 9e-10) 
开发者ID:Microvellum,项目名称:Fluid-Designer,代码行数:23,代码来源:datetimetester.py

示例2: test_tz_independent_comparing

# 需要导入模块: from datetime import timedelta [as 别名]
# 或者: from datetime.timedelta import resolution [as 别名]
def test_tz_independent_comparing(self):
        dt1 = self.theclass(2002, 3, 1, 9, 0, 0)
        dt2 = self.theclass(2002, 3, 1, 10, 0, 0)
        dt3 = self.theclass(2002, 3, 1, 9, 0, 0)
        self.assertEqual(dt1, dt3)
        self.assertTrue(dt2 > dt3)

        # Make sure comparison doesn't forget microseconds, and isn't done
        # via comparing a float timestamp (an IEEE double doesn't have enough
        # precision to span microsecond resolution across years 1 thru 9999,
        # so comparing via timestamp necessarily calls some distinct values
        # equal).
        dt1 = self.theclass(MAXYEAR, 12, 31, 23, 59, 59, 999998)
        us = timedelta(microseconds=1)
        dt2 = dt1 + us
        self.assertEqual(dt2 - dt1, us)
        self.assertTrue(dt1 < dt2) 
开发者ID:Microvellum,项目名称:Fluid-Designer,代码行数:19,代码来源:datetimetester.py

示例3: test_resolution_info

# 需要导入模块: from datetime import timedelta [as 别名]
# 或者: from datetime.timedelta import resolution [as 别名]
def test_resolution_info(self):
        self.assertIsInstance(timedelta.min, timedelta)
        self.assertIsInstance(timedelta.max, timedelta)
        self.assertIsInstance(timedelta.resolution, timedelta)
        self.assertTrue(timedelta.max > timedelta.min)
        self.assertEqual(timedelta.min, timedelta(-999999999))
        self.assertEqual(timedelta.max, timedelta(999999999, 24*3600-1, 1e6-1))
        self.assertEqual(timedelta.resolution, timedelta(0, 0, 1)) 
开发者ID:IronLanguages,项目名称:ironpython2,代码行数:10,代码来源:test_datetime.py

示例4: test_overflow

# 需要导入模块: from datetime import timedelta [as 别名]
# 或者: from datetime.timedelta import resolution [as 别名]
def test_overflow(self):
        tiny = timedelta.resolution

        td = timedelta.min + tiny
        td -= tiny  # no problem
        self.assertRaises(OverflowError, td.__sub__, tiny)
        self.assertRaises(OverflowError, td.__add__, -tiny)

        td = timedelta.max - tiny
        td += tiny  # no problem
        self.assertRaises(OverflowError, td.__add__, tiny)
        self.assertRaises(OverflowError, td.__sub__, -tiny)

        self.assertRaises(OverflowError, lambda: -timedelta.max) 
开发者ID:IronLanguages,项目名称:ironpython2,代码行数:16,代码来源:test_datetime.py

示例5: test_today

# 需要导入模块: from datetime import timedelta [as 别名]
# 或者: from datetime.timedelta import resolution [as 别名]
def test_today(self):
        import time

        # We claim that today() is like fromtimestamp(time.time()), so
        # prove it.
        for dummy in range(3):
            today = self.theclass.today()
            ts = time.time()
            todayagain = self.theclass.fromtimestamp(ts)
            if today == todayagain:
                break
            # There are several legit reasons that could fail:
            # 1. It recently became midnight, between the today() and the
            #    time() calls.
            # 2. The platform time() has such fine resolution that we'll
            #    never get the same value twice.
            # 3. The platform time() has poor resolution, and we just
            #    happened to call today() right before a resolution quantum
            #    boundary.
            # 4. The system clock got fiddled between calls.
            # In any case, wait a little while and try again.
            time.sleep(0.1)

        # It worked or it didn't.  If it didn't, assume it's reason #2, and
        # let the test pass if they're within half a second of each other.
        if today != todayagain:
            self.assertAlmostEqual(todayagain, today,
                                   delta=timedelta(seconds=0.5)) 
开发者ID:IronLanguages,项目名称:ironpython2,代码行数:30,代码来源:test_datetime.py

示例6: test_today

# 需要导入模块: from datetime import timedelta [as 别名]
# 或者: from datetime.timedelta import resolution [as 别名]
def test_today(self):
        import time

        # We claim that today() is like fromtimestamp(time.time()), so
        # prove it.
        for dummy in range(3):
            today = self.theclass.today()
            ts = time.time()
            todayagain = self.theclass.fromtimestamp(ts)
            if today == todayagain:
                break
            # There are several legit reasons that could fail:
            # 1. It recently became midnight, between the today() and the
            #    time() calls.
            # 2. The platform time() has such fine resolution that we'll
            #    never get the same value twice.
            # 3. The platform time() has poor resolution, and we just
            #    happened to call today() right before a resolution quantum
            #    boundary.
            # 4. The system clock got fiddled between calls.
            # In any case, wait a little while and try again.
            time.sleep(0.1)

        # It worked or it didn't.  If it didn't, assume it's reason #2, and
        # let the test pass if they're within half a second of each other.
        self.assertTrue(today == todayagain or
                        abs(todayagain - today) < timedelta(seconds=0.5)) 
开发者ID:dxwu,项目名称:BinderFilter,代码行数:29,代码来源:test_datetime.py

示例7: test_microsecond_rounding

# 需要导入模块: from datetime import timedelta [as 别名]
# 或者: from datetime.timedelta import resolution [as 别名]
def test_microsecond_rounding(self):
        td = timedelta
        eq = self.assertEqual

        # Single-field rounding.
        eq(td(milliseconds=0.4/1000), td(0))    # rounds to 0
        eq(td(milliseconds=-0.4/1000), td(0))    # rounds to 0
        eq(td(milliseconds=0.5/1000), td(microseconds=0))
        eq(td(milliseconds=-0.5/1000), td(microseconds=-0))
        eq(td(milliseconds=0.6/1000), td(microseconds=1))
        eq(td(milliseconds=-0.6/1000), td(microseconds=-1))
        eq(td(milliseconds=1.5/1000), td(microseconds=2))
        eq(td(milliseconds=-1.5/1000), td(microseconds=-2))
        eq(td(seconds=0.5/10**6), td(microseconds=0))
        eq(td(seconds=-0.5/10**6), td(microseconds=-0))
        eq(td(seconds=1/2**7), td(microseconds=7812))
        eq(td(seconds=-1/2**7), td(microseconds=-7812))

        # Rounding due to contributions from more than one field.
        us_per_hour = 3600e6
        us_per_day = us_per_hour * 24
        eq(td(days=.4/us_per_day), td(0))
        eq(td(hours=.2/us_per_hour), td(0))
        eq(td(days=.4/us_per_day, hours=.2/us_per_hour), td(microseconds=1))

        eq(td(days=-.4/us_per_day), td(0))
        eq(td(hours=-.2/us_per_hour), td(0))
        eq(td(days=-.4/us_per_day, hours=-.2/us_per_hour), td(microseconds=-1))

        # Test for a patch in Issue 8860
        eq(td(microseconds=0.5), 0.5*td(microseconds=1.0))
        eq(td(microseconds=0.5)//td.resolution, 0.5*td.resolution//td.resolution) 
开发者ID:Microvellum,项目名称:Fluid-Designer,代码行数:34,代码来源:datetimetester.py


注:本文中的datetime.timedelta.resolution方法示例由纯净天空整理自Github/MSDocs等开源代码及文档管理平台,相关代码片段筛选自各路编程大神贡献的开源项目,源码版权归原作者所有,传播和使用请参考对应项目的License;未经允许,请勿转载。