本文整理汇总了Python中_imp.release_lock方法的典型用法代码示例。如果您正苦于以下问题：Python _imp.release_lock方法的具体用法？Python _imp.release_lock怎么用？Python _imp.release_lock使用的例子？那么恭喜您, 这里精选的方法代码示例或许可以为您提供帮助。您也可以进一步了解该方法所在类_imp的用法示例。
在下文中一共展示了_imp.release_lock方法的5个代码示例，这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞，您的评价将有助于系统推荐出更棒的Python代码示例。
示例1: declare_namespace
# 需要导入模块: import _imp [as 别名]
# 或者: from _imp import release_lock [as 别名]
def declare_namespace(packageName):
"""Declare that package 'packageName' is a namespace package"""
_imp.acquire_lock()
try:
if packageName in _namespace_packages:
return
path, parent = sys.path, None
if '.' in packageName:
parent = '.'.join(packageName.split('.')[:-1])
declare_namespace(parent)
if parent not in _namespace_packages:
__import__(parent)
try:
path = sys.modules[parent].__path__
except AttributeError:
raise TypeError("Not a package:", parent)
# Track what packages are namespaces, so when new path items are added,
# they can be updated
_namespace_packages.setdefault(parent, []).append(packageName)
_namespace_packages.setdefault(packageName, [])
for path_item in path:
# Ensure all the parent's path items are reflected in the child,
# if they apply
_handle_ns(packageName, path_item)
finally:
_imp.release_lock() 示例2: fixup_namespace_packages
# 需要导入模块: import _imp [as 别名]
# 或者: from _imp import release_lock [as 别名]
def fixup_namespace_packages(path_item, parent=None):
"""Ensure that previously-declared namespace packages include path_item"""
_imp.acquire_lock()
try:
for package in _namespace_packages.get(parent, ()):
subpath = _handle_ns(package, path_item)
if subpath:
fixup_namespace_packages(subpath, package)
finally:
_imp.release_lock() 示例3: declare_namespace
# 需要导入模块: import _imp [as 别名]
# 或者: from _imp import release_lock [as 别名]
def declare_namespace(packageName):
"""Declare that package 'packageName' is a namespace package"""
_imp.acquire_lock()
try:
if packageName in _namespace_packages:
return
path, parent = sys.path, None
if '.' in packageName:
parent = '.'.join(packageName.split('.')[:-1])
declare_namespace(parent)
if parent not in _namespace_packages:
__import__(parent)
try:
path = sys.modules[parent].__path__
except AttributeError:
raise TypeError("Not a package:", parent)
# Track what packages are namespaces, so when new path items are added,
# they can be updated
_namespace_packages.setdefault(parent,[]).append(packageName)
_namespace_packages.setdefault(packageName,[])
for path_item in path:
# Ensure all the parent's path items are reflected in the child,
# if they apply
_handle_ns(packageName, path_item)
finally:
_imp.release_lock() 示例4: fixup_namespace_packages
# 需要导入模块: import _imp [as 别名]
# 或者: from _imp import release_lock [as 别名]
def fixup_namespace_packages(path_item, parent=None):
"""Ensure that previously-declared namespace packages include path_item"""
_imp.acquire_lock()
try:
for package in _namespace_packages.get(parent,()):
subpath = _handle_ns(package, path_item)
if subpath:
fixup_namespace_packages(subpath, package)
finally:
_imp.release_lock() 示例5: declare_namespace
# 需要导入模块: import _imp [as 别名]
# 或者: from _imp import release_lock [as 别名]
def declare_namespace(packageName):
"""Declare that package 'packageName' is a namespace package"""
_imp.acquire_lock()
try:
if packageName in _namespace_packages:
return
path = sys.path
parent, _, _ = packageName.rpartition('.')
if parent:
declare_namespace(parent)
if parent not in _namespace_packages:
__import__(parent)
try:
path = sys.modules[parent].__path__
except AttributeError:
raise TypeError("Not a package:", parent)
# Track what packages are namespaces, so when new path items are added,
# they can be updated
_namespace_packages.setdefault(parent or None, []).append(packageName)
_namespace_packages.setdefault(packageName, [])
for path_item in path:
# Ensure all the parent's path items are reflected in the child,
# if they apply
_handle_ns(packageName, path_item)
finally:
_imp.release_lock()