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Python MD4.new方法代码示例

本文整理汇总了Python中Crypto.Hash.MD4.new方法的典型用法代码示例。如果您正苦于以下问题:Python MD4.new方法的具体用法?Python MD4.new怎么用?Python MD4.new使用的例子?那么, 这里精选的方法代码示例或许可以为您提供帮助。您也可以进一步了解该方法所在Crypto.Hash.MD4的用法示例。


在下文中一共展示了MD4.new方法的15个代码示例,这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞,您的评价将有助于系统推荐出更棒的Python代码示例。

示例1: get_hbootkey

# 需要导入模块: from Crypto.Hash import MD4 [as 别名]
# 或者: from Crypto.Hash.MD4 import new [as 别名]
def get_hbootkey(sam_registry, bootkey):
    sam_account_path = ["SAM", "Domains", "Account"]

    sam_account_key = sam_registry.open_key(sam_account_path)

    # Get the F value
    F = sam_account_key.open_value("F").DecodedData
    if not F:
        return F

    md5 = MD5.new()
    md5.update(F[0x70:0x80] + aqwerty + bootkey + anum)
    rc4_key = md5.digest()

    rc4 = ARC4.new(rc4_key)
    hbootkey = rc4.encrypt(F[0x80:0xA0])

    return hbootkey 
开发者ID:google,项目名称:rekall,代码行数:20,代码来源:hashdump.py

示例2: getHBootKey

# 需要导入模块: from Crypto.Hash import MD4 [as 别名]
# 或者: from Crypto.Hash.MD4 import new [as 别名]
def getHBootKey(self):
        LOG.debug('Calculating HashedBootKey from SAM')
        QWERTY = "!@#$%^&*()qwertyUIOPAzxcvbnmQQQQQQQQQQQQ)(*@&%\0"
        DIGITS = "0123456789012345678901234567890123456789\0"

        F = self.getValue(ntpath.join('SAM\Domains\Account','F'))[1]

        domainData = DOMAIN_ACCOUNT_F(F)

        rc4Key = self.MD5(domainData['Key0']['Salt'] + QWERTY + self.__bootKey + DIGITS)

        rc4 = ARC4.new(rc4Key)
        self.__hashedBootKey = rc4.encrypt(domainData['Key0']['Key']+domainData['Key0']['CheckSum'])

        # Verify key with checksum
        checkSum = self.MD5( self.__hashedBootKey[:16] + DIGITS + self.__hashedBootKey[:16] + QWERTY)

        if checkSum != self.__hashedBootKey[16:]:
            raise Exception('hashedBootKey CheckSum failed, Syskey startup password probably in use! :(') 
开发者ID:joxeankoret,项目名称:CVE-2017-7494,代码行数:21,代码来源:secretsdump.py

示例3: __decryptSecret

# 需要导入模块: from Crypto.Hash import MD4 [as 别名]
# 或者: from Crypto.Hash.MD4 import new [as 别名]
def __decryptSecret(self, key, value):
        # [MS-LSAD] Section 5.1.2
        plainText = ''

        encryptedSecretSize = unpack('<I', value[:4])[0]
        value = value[len(value)-encryptedSecretSize:]

        key0 = key
        for i in range(0, len(value), 8):
            cipherText = value[:8]
            tmpStrKey = key0[:7]
            tmpKey = self.__cryptoCommon.transformKey(tmpStrKey)
            Crypt1 = DES.new(tmpKey, DES.MODE_ECB)
            plainText += Crypt1.decrypt(cipherText)
            key0 = key0[7:]
            value = value[8:]
            # AdvanceKey
            if len(key0) < 7:
                key0 = key[len(key0):]

        secret = LSA_SECRET_XP(plainText)
        return secret['Secret'] 
开发者ID:joxeankoret,项目名称:CVE-2017-7494,代码行数:24,代码来源:secretsdump.py

示例4: __decryptLSA

# 需要导入模块: from Crypto.Hash import MD4 [as 别名]
# 或者: from Crypto.Hash.MD4 import new [as 别名]
def __decryptLSA(self, value):
        if self.__vistaStyle is True:
            # ToDo: There could be more than one LSA Keys
            record = LSA_SECRET(value)
            tmpKey = self.__sha256(self.__bootKey, record['EncryptedData'][:32])
            plainText = self.__cryptoCommon.decryptAES(tmpKey, record['EncryptedData'][32:])
            record = LSA_SECRET_BLOB(plainText)
            self.__LSAKey = record['Secret'][52:][:32]

        else:
            md5 = hashlib.new('md5')
            md5.update(self.__bootKey)
            for i in range(1000):
                md5.update(value[60:76])
            tmpKey = md5.digest()
            rc4 = ARC4.new(tmpKey)
            plainText = rc4.decrypt(value[12:60])
            self.__LSAKey = plainText[0x10:0x20] 
开发者ID:joxeankoret,项目名称:CVE-2017-7494,代码行数:20,代码来源:secretsdump.py

示例5: computeResponseNTLMv1

# 需要导入模块: from Crypto.Hash import MD4 [as 别名]
# 或者: from Crypto.Hash.MD4 import new [as 别名]
def computeResponseNTLMv1(flags, serverChallenge, clientChallenge, serverName, domain, user, password, lmhash='',
                          nthash='', use_ntlmv2=USE_NTLMv2):
    if user == '' and password == '':
        # Special case for anonymous authentication
        lmResponse = ''
        ntResponse = ''
    else:
        lmhash = LMOWFv1(password, lmhash, nthash)
        nthash = NTOWFv1(password, lmhash, nthash)
        if flags & NTLMSSP_NEGOTIATE_LM_KEY:
           ntResponse = ''
           lmResponse = get_ntlmv1_response(lmhash, serverChallenge)
        elif flags & NTLMSSP_NEGOTIATE_EXTENDED_SESSIONSECURITY:
           md5 = hashlib.new('md5')
           chall = (serverChallenge + clientChallenge)
           md5.update(chall)
           ntResponse = ntlmssp_DES_encrypt(nthash, md5.digest()[:8])
           lmResponse = clientChallenge + '\x00'*16
        else:
           ntResponse = get_ntlmv1_response(nthash,serverChallenge)
           lmResponse = get_ntlmv1_response(lmhash, serverChallenge)
   
    sessionBaseKey = generateSessionKeyV1(password, lmhash, nthash)
    return ntResponse, lmResponse, sessionBaseKey 
开发者ID:joxeankoret,项目名称:CVE-2017-7494,代码行数:26,代码来源:ntlm.py

示例6: decrypt

# 需要导入模块: from Crypto.Hash import MD4 [as 别名]
# 或者: from Crypto.Hash.MD4 import new [as 别名]
def decrypt(cls, key, keyusage, ciphertext):
        if len(ciphertext) < 24:
            raise ValueError('ciphertext too short')
        cksum, basic_ctext = ciphertext[:16], ciphertext[16:]
        ki = HMAC.new(key.contents, cls.usage_str(keyusage), MD5).digest()
        ke = HMAC.new(ki, cksum, MD5).digest()
        basic_plaintext = ARC4.new(ke).decrypt(basic_ctext)
        exp_cksum = HMAC.new(ki, basic_plaintext, MD5).digest()
        ok = _mac_equal(cksum, exp_cksum)
        if not ok and keyusage == 9:
            # Try again with usage 8, due to RFC 4757 errata.
            ki = HMAC.new(key.contents, pack('<I', 8), MD5).digest()
            exp_cksum = HMAC.new(ki, basic_plaintext, MD5).digest()
            ok = _mac_equal(cksum, exp_cksum)
        if not ok:
            raise InvalidChecksum('ciphertext integrity failure')
        # Discard the confounder.
        return basic_plaintext[8:] 
开发者ID:joxeankoret,项目名称:CVE-2017-7494,代码行数:20,代码来源:crypto.py

示例7: __decryptHash

# 需要导入模块: from Crypto.Hash import MD4 [as 别名]
# 或者: from Crypto.Hash.MD4 import new [as 别名]
def __decryptHash(self, rid, cryptedHash, constant, newStyle = False):
        # Section 2.2.11.1.1 Encrypting an NT or LM Hash Value with a Specified Key
        # plus hashedBootKey stuff
        Key1,Key2 = self.__cryptoCommon.deriveKey(rid)

        Crypt1 = DES.new(Key1, DES.MODE_ECB)
        Crypt2 = DES.new(Key2, DES.MODE_ECB)

        if newStyle is False:
            rc4Key = self.MD5( self.__hashedBootKey[:0x10] + pack("<L",rid) + constant )
            rc4 = ARC4.new(rc4Key)
            key = rc4.encrypt(cryptedHash['Hash'])
        else:
            key = self.__cryptoCommon.decryptAES(self.__hashedBootKey[:0x10], cryptedHash['Hash'], cryptedHash['Salt'])[:16]

        decryptedHash = Crypt1.decrypt(key[:8]) + Crypt2.decrypt(key[8:])

        return decryptedHash 
开发者ID:eth0izzle,项目名称:cracke-dit,代码行数:20,代码来源:secretsdump.py

示例8: sha1

# 需要导入模块: from Crypto.Hash import MD4 [as 别名]
# 或者: from Crypto.Hash.MD4 import new [as 别名]
def sha1(self):
        """Get SHA1 hash
        
        The SHA (Secure Hash Algorithm) hash functions were designed by the NSA. 
        SHA-1 is the most established of the existing SHA hash functions and it is 
        used in a variety of security applications and protocols. However, SHA-1's 
        collision resistance has been weakening as new attacks are discovered or improved.

        Returns:
            Chepy: The Chepy object. 

        Examples:
            >>> Chepy("A").sha1().output
            "6dcd4ce23d88e2ee9568ba546c007c63d9131c1b"
        """
        self.state = hashlib.sha1(self._convert_to_bytes()).hexdigest()
        return self 
开发者ID:securisec,项目名称:chepy,代码行数:19,代码来源:hashing.py

示例9: sha2_512_truncate

# 需要导入模块: from Crypto.Hash import MD4 [as 别名]
# 或者: from Crypto.Hash.MD4 import new [as 别名]
def sha2_512_truncate(self, truncate: int = 256):
        """Get SHA2-512/bits hash
        
        The SHA-2 (Secure Hash Algorithm 2) hash functions were designed by the NSA. SHA-2 
        includes significant changes from its predecessor, SHA-1. The SHA-2 family consists of 
        hash functions with digests (hash values) that are 224, 256, 384 or 512 bits: SHA224, 
        SHA256, SHA384, SHA512. SHA-512 operates on 64-bit words. SHA-256 operates on 32-bit 
        words. SHA-384 is largely identical to SHA-512 but is truncated to 384 bytes. SHA-224 
        is largely identical to SHA-256 but is truncated to 224 bytes. SHA-512/224 and SHA-512/256 
        are truncated versions of SHA-512, but the initial values are generated using the method 
        described in Federal Information Processing Standards (FIPS) PUB 180-4.

        Args:
            truncate (int, optional): The bits to truncate by. Defaults to 256

        Returns:
            Chepy: The Chepy object. 
        """
        assert truncate in [256, 224], "Valid truncates are 256, 224"
        h = SHA512.new(self._convert_to_bytes(), truncate=str(truncate))
        self.state = h.hexdigest()
        return self 
开发者ID:securisec,项目名称:chepy,代码行数:24,代码来源:hashing.py

示例10: hash_lm

# 需要导入模块: from Crypto.Hash import MD4 [as 别名]
# 或者: from Crypto.Hash.MD4 import new [as 别名]
def hash_lm(pw):
    pw = pw[:14].upper()
    pw = pw + ('\0' * (14 - len(pw)))
    d1 = DES.new(str_to_key(pw[:7]), DES.MODE_ECB)
    d2 = DES.new(str_to_key(pw[7:]), DES.MODE_ECB)
    return d1.encrypt(lmkey) + d2.encrypt(lmkey) 
开发者ID:google,项目名称:rekall,代码行数:8,代码来源:hashdump.py

示例11: hash_nt

# 需要导入模块: from Crypto.Hash import MD4 [as 别名]
# 或者: from Crypto.Hash.MD4 import new [as 别名]
def hash_nt(pw):
    return MD4.new(pw.encode('utf-16-le')).digest() 
开发者ID:google,项目名称:rekall,代码行数:4,代码来源:hashdump.py

示例12: decrypt_single_hash

# 需要导入模块: from Crypto.Hash import MD4 [as 别名]
# 或者: from Crypto.Hash.MD4 import new [as 别名]
def decrypt_single_hash(rid, hbootkey, enc_hash, lmntstr):
    (des_k1, des_k2) = sid_to_key(rid)
    d1 = DES.new(des_k1, DES.MODE_ECB)
    d2 = DES.new(des_k2, DES.MODE_ECB)

    md5 = MD5.new()
    md5.update(hbootkey[:0x10] + struct.pack("<L", rid) + lmntstr)
    rc4_key = md5.digest()
    rc4 = ARC4.new(rc4_key)
    obfkey = rc4.encrypt(enc_hash)
    hash = d1.decrypt(obfkey[:8]) + d2.decrypt(obfkey[8:])

    return hash 
开发者ID:google,项目名称:rekall,代码行数:15,代码来源:hashdump.py

示例13: encrypt_single_hash

# 需要导入模块: from Crypto.Hash import MD4 [as 别名]
# 或者: from Crypto.Hash.MD4 import new [as 别名]
def encrypt_single_hash(rid, hbootkey, hash, lmntstr):
    (des_k1, des_k2) = sid_to_key(rid)
    d1 = DES.new(des_k1, DES.MODE_ECB)
    d2 = DES.new(des_k2, DES.MODE_ECB)

    enc_hash = d1.encrypt(hash[:8]) + d2.encrypt(hash[8:])

    md5 = MD5.new()
    md5.update(hbootkey[:0x10] + struct.pack("<L", rid) + lmntstr)
    rc4_key = md5.digest()
    rc4 = ARC4.new(rc4_key)
    obfkey = rc4.encrypt(enc_hash)

    return obfkey 
开发者ID:google,项目名称:rekall,代码行数:16,代码来源:hashdump.py

示例14: __restore

# 需要导入模块: from Crypto.Hash import MD4 [as 别名]
# 或者: from Crypto.Hash.MD4 import new [as 别名]
def __restore(self):
        # First of all stop the service if it was originally stopped
        if self.__shouldStop is True:
            LOG.info('Stopping service %s' % self.__serviceName)
            scmr.hRControlService(self.__scmr, self.__serviceHandle, scmr.SERVICE_CONTROL_STOP)
        if self.__disabled is True:
            LOG.info('Restoring the disabled state for service %s' % self.__serviceName)
            scmr.hRChangeServiceConfigW(self.__scmr, self.__serviceHandle, dwStartType = 0x4)
        if self.__serviceDeleted is False:
            # Check again the service we created does not exist, starting a new connection
            # Why?.. Hitting CTRL+C might break the whole existing DCE connection
            try:
                rpc = transport.DCERPCTransportFactory(r'ncacn_np:%s[\pipe\svcctl]' % self.__smbConnection.getRemoteHost())
                if hasattr(rpc, 'set_credentials'):
                    # This method exists only for selected protocol sequences.
                    rpc.set_credentials(*self.__smbConnection.getCredentials())
                    rpc.set_kerberos(self.__doKerberos, self.__kdcHost)
                self.__scmr = rpc.get_dce_rpc()
                self.__scmr.connect()
                self.__scmr.bind(scmr.MSRPC_UUID_SCMR)
                # Open SC Manager
                ans = scmr.hROpenSCManagerW(self.__scmr)
                self.__scManagerHandle = ans['lpScHandle']
                # Now let's open the service
                resp = scmr.hROpenServiceW(self.__scmr, self.__scManagerHandle, self.__tmpServiceName)
                service = resp['lpServiceHandle']
                scmr.hRDeleteService(self.__scmr, service)
                scmr.hRControlService(self.__scmr, service, scmr.SERVICE_CONTROL_STOP)
                scmr.hRCloseServiceHandle(self.__scmr, service)
                scmr.hRCloseServiceHandle(self.__scmr, self.__serviceHandle)
                scmr.hRCloseServiceHandle(self.__scmr, self.__scManagerHandle)
                rpc.disconnect()
            except Exception, e:
                # If service is stopped it'll trigger an exception
                # If service does not exist it'll trigger an exception
                # So. we just wanna be sure we delete it, no need to 
                # show this exception message
                pass 
开发者ID:joxeankoret,项目名称:CVE-2017-7494,代码行数:40,代码来源:secretsdump.py

示例15: decryptAES

# 需要导入模块: from Crypto.Hash import MD4 [as 别名]
# 或者: from Crypto.Hash.MD4 import new [as 别名]
def decryptAES(key, value, iv='\x00'*16):
        plainText = ''
        if iv != '\x00'*16:
            aes256 = AES.new(key,AES.MODE_CBC, iv)

        for index in range(0, len(value), 16):
            if iv == '\x00'*16:
                aes256 = AES.new(key,AES.MODE_CBC, iv)
            cipherBuffer = value[index:index+16]
            # Pad buffer to 16 bytes
            if len(cipherBuffer) < 16:
                cipherBuffer += '\x00' * (16-len(cipherBuffer))
            plainText += aes256.decrypt(cipherBuffer)

        return plainText 
开发者ID:joxeankoret,项目名称:CVE-2017-7494,代码行数:17,代码来源:secretsdump.py


注:本文中的Crypto.Hash.MD4.new方法示例由纯净天空整理自Github/MSDocs等开源代码及文档管理平台,相关代码片段筛选自各路编程大神贡献的开源项目,源码版权归原作者所有,传播和使用请参考对应项目的License;未经允许,请勿转载。