本文整理汇总了Python中webob.multidict.MultiDict.mixed方法的典型用法代码示例。如果您正苦于以下问题:Python MultiDict.mixed方法的具体用法?Python MultiDict.mixed怎么用?Python MultiDict.mixed使用的例子?那么恭喜您, 这里精选的方法代码示例或许可以为您提供帮助。您也可以进一步了解该方法所在类webob.multidict.MultiDict
的用法示例。
在下文中一共展示了MultiDict.mixed方法的2个代码示例,这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞,您的评价将有助于系统推荐出更棒的Python代码示例。
示例1: test_multidict
# 需要导入模块: from webob.multidict import MultiDict [as 别名]
# 或者: from webob.multidict.MultiDict import mixed [as 别名]
def test_multidict():
d = MultiDict(a=1, b=2)
assert d['a'] == 1
assert d.getall('c') == []
d.add('a', 2)
assert d['a'] == 2
assert d.getall('a') == [1, 2]
d['b'] = 4
assert d.getall('b') == [4]
assert list(d.keys()) == ['a', 'a', 'b']
assert list(d.items()) == [('a', 1), ('a', 2), ('b', 4)]
assert d.mixed() == {'a': [1, 2], 'b': 4}
# test getone
# KeyError: "Multiple values match 'a': [1, 2]"
with pytest.raises(KeyError):
d.getone('a')
assert d.getone('b') == 4
# KeyError: "Key not found: 'g'"
with pytest.raises(KeyError):
d.getone('g')
assert d.dict_of_lists() == {'a': [1, 2], 'b': [4]}
assert 'b' in d
assert 'e' not in d
d.clear()
assert 'b' not in d
d['a'] = 4
d.add('a', 5)
e = d.copy()
assert 'a' in e
e.clear()
e['f'] = 42
d.update(e)
assert d == MultiDict([('a', 4), ('a', 5), ('f', 42)])
f = d.pop('a')
assert f == 4
assert d['a'] == 5
assert d.pop('g', 42) == 42
with pytest.raises(KeyError):
d.pop('n')
# TypeError: pop expected at most 2 arguments, got 3
with pytest.raises(TypeError):
d.pop(4, 2, 3)
d.setdefault('g', []).append(4)
assert d == MultiDict([('a', 5), ('f', 42), ('g', [4])])
示例2: test_multidict
# 需要导入模块: from webob.multidict import MultiDict [as 别名]
# 或者: from webob.multidict.MultiDict import mixed [as 别名]
def test_multidict():
d = MultiDict(a=1, b=2)
eq(d['a'], 1)
eq(d.getall('c'), [])
d.add('a', 2)
eq(d['a'], 2)
eq(d.getall('a'), [1, 2])
d['b'] = 4
eq(d.getall('b'), [4])
eq(list(d.keys()), ['a', 'a', 'b'])
eq(list(d.items()), [('a', 1), ('a', 2), ('b', 4)])
eq(d.mixed(), {'a': [1, 2], 'b': 4})
# test getone
# KeyError: "Multiple values match 'a': [1, 2]"
assert_raises(KeyError, d.getone, 'a')
eq(d.getone('b'), 4)
# KeyError: "Key not found: 'g'"
assert_raises(KeyError, d.getone, 'g')
eq(d.dict_of_lists(), {'a': [1, 2], 'b': [4]})
assert 'b' in d
assert 'e' not in d
d.clear()
assert 'b' not in d
d['a'] = 4
d.add('a', 5)
e = d.copy()
assert 'a' in e
e.clear()
e['f'] = 42
d.update(e)
eq(d, MultiDict([('a', 4), ('a', 5), ('f', 42)]))
f = d.pop('a')
eq(f, 4)
eq(d['a'], 5)
eq(d.pop('g', 42), 42)
assert_raises(KeyError, d.pop, 'n')
# TypeError: pop expected at most 2 arguments, got 3
assert_raises(TypeError, d.pop, 4, 2, 3)
d.setdefault('g', []).append(4)
eq(d, MultiDict([('a', 5), ('f', 42), ('g', [4])]))