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Python iterables.common_prefix函数代码示例

本文整理汇总了Python中sympy.utilities.iterables.common_prefix函数的典型用法代码示例。如果您正苦于以下问题:Python common_prefix函数的具体用法?Python common_prefix怎么用?Python common_prefix使用的例子?那么恭喜您, 这里精选的函数代码示例或许可以为您提供帮助。


在下文中一共展示了common_prefix函数的3个代码示例,这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞,您的评价将有助于系统推荐出更棒的Python代码示例。

示例1: test_common_prefix_suffix

def test_common_prefix_suffix():
    assert common_prefix([], [1]) == []
    assert common_prefix(range(3)) == [0, 1, 2]
    assert common_prefix(range(3), range(4)) == [0, 1, 2]
    assert common_prefix([1, 2, 3], [1, 2, 5]) == [1, 2]
    assert common_prefix([1, 2, 3], [1, 3, 5]) == [1]

    assert common_suffix([], [1]) == []
    assert common_suffix(range(3)) == [0, 1, 2]
    assert common_suffix(range(3), range(3)) == [0, 1, 2]
    assert common_suffix(range(3), range(4)) == []
    assert common_suffix([1, 2, 3], [9, 2, 3]) == [2, 3]
    assert common_suffix([1, 2, 3], [9, 7, 3]) == [3]
开发者ID:Acebulf,项目名称:sympy,代码行数:13,代码来源:test_iterables.py

示例2: factor_nc

def factor_nc(expr):
    """Return the factored form of ``expr`` while handling non-commutative
    expressions.

    **examples**
    >>> from sympy.core.exprtools import factor_nc
    >>> from sympy import Symbol
    >>> from sympy.abc import x
    >>> A = Symbol('A', commutative=False)
    >>> B = Symbol('B', commutative=False)
    >>> factor_nc((x**2 + 2*A*x + A**2).expand())
    (x + A)**2
    >>> factor_nc(((x + A)*(x + B)).expand())
    (x + A)*(x + B)
    """
    from sympy.simplify.simplify import _mexpand
    from sympy.polys import gcd, factor

    expr = sympify(expr)
    if not isinstance(expr, Expr) or not expr.args:
        return expr
    if not expr.is_Add:
        return expr.func(*[factor_nc(a) for a in expr.args])

    expr, rep, nc_symbols = _mask_nc(expr)
    if rep:
        return factor(expr).subs(rep)
    else:
        args = [a.args_cnc() for a in Add.make_args(expr)]
        c = g = l = r = S.One
        hit = False
        # find any commutative gcd term
        for i, a in enumerate(args):
            if i == 0:
                c = Mul._from_args(a[0])
            elif a[0]:
                c = gcd(c, Mul._from_args(a[0]))
            else:
                c = S.One
        if c is not S.One:
            hit = True
            c, g = c.as_coeff_Mul()
            if g is not S.One:
                for i, (cc, _) in enumerate(args):
                    cc = list(Mul.make_args(Mul._from_args(list(cc))/g))
                    args[i][0] = cc
            else:
                for i, (cc, _) in enumerate(args):
                    cc[0] = cc[0]/c
                    args[i][0] = cc
        # find any noncommutative common prefix
        for i, a in enumerate(args):
            if i == 0:
                n = a[1][:]
            else:
                n = common_prefix(n, a[1])
            if not n:
                # is there a power that can be extracted?
                if not args[0][1]:
                    break
                b, e = args[0][1][0].as_base_exp()
                ok = False
                if e.is_Integer:
                    for t in args:
                        if not t[1]:
                            break
                        bt, et = t[1][0].as_base_exp()
                        if et.is_Integer and bt == b:
                            e = min(e, et)
                        else:
                            break
                    else:
                        ok = hit = True
                        l = b**e
                        il = b**-e
                        for i, a in enumerate(args):
                            args[i][1][0] = il*args[i][1][0]
                        break
                if not ok:
                    break
        else:
            hit = True
            lenn = len(n)
            l = Mul(*n)
            for i, a in enumerate(args):
                args[i][1] = args[i][1][lenn:]
        # find any noncommutative common suffix
        for i, a in enumerate(args):
            if i == 0:
                n = a[1][:]
            else:
                n = common_suffix(n, a[1])
            if not n:
                # is there a power that can be extracted?
                if not args[0][1]:
                    break
                b, e = args[0][1][-1].as_base_exp()
                ok = False
                if e.is_Integer:
                    for t in args:
#.........这里部分代码省略.........
开发者ID:FireJade,项目名称:sympy,代码行数:101,代码来源:exprtools.py

示例3: piecewise_fold

def piecewise_fold(expr):
    """
    Takes an expression containing a piecewise function and returns the
    expression in piecewise form. In addition, any ITE conditions are
    rewritten in negation normal form and simplified.

    Examples
    ========

    >>> from sympy import Piecewise, piecewise_fold, sympify as S
    >>> from sympy.abc import x
    >>> p = Piecewise((x, x < 1), (1, S(1) <= x))
    >>> piecewise_fold(x*p)
    Piecewise((x**2, x < 1), (x, True))

    See Also
    ========

    Piecewise
    """
    if not isinstance(expr, Basic) or not expr.has(Piecewise):
        return expr

    new_args = []
    if isinstance(expr, (ExprCondPair, Piecewise)):
        for e, c in expr.args:
            if not isinstance(e, Piecewise):
                e = piecewise_fold(e)
            # we don't keep Piecewise in condition because
            # it has to be checked to see that it's complete
            # and we convert it to ITE at that time
            assert not c.has(Piecewise)  # pragma: no cover
            if isinstance(c, ITE):
                c = c.to_nnf()
                c = simplify_logic(c, form='cnf')
            if isinstance(e, Piecewise):
                new_args.extend([(piecewise_fold(ei), And(ci, c))
                    for ei, ci in e.args])
            else:
                new_args.append((e, c))
    else:
        from sympy.utilities.iterables import cartes, sift, common_prefix
        # Given
        #     P1 = Piecewise((e11, c1), (e12, c2), A)
        #     P2 = Piecewise((e21, c1), (e22, c2), B)
        #     ...
        # the folding of f(P1, P2) is trivially
        # Piecewise(
        #   (f(e11, e21), c1),
        #   (f(e12, e22), c2),
        #   (f(Piecewise(A), Piecewise(B)), True))
        # Certain objects end up rewriting themselves as thus, so
        # we do that grouping before the more generic folding.
        # The following applies this idea when f = Add or f = Mul
        # (and the expression is commutative).
        if expr.is_Add or expr.is_Mul and expr.is_commutative:
            p, args = sift(expr.args, lambda x: x.is_Piecewise, binary=True)
            pc = sift(p, lambda x: x.args[0].cond)
            for c in pc:
                if len(pc[c]) > 1:
                    pargs = [list(i.args) for i in pc[c]]
                    # the first one is the same; there may be more
                    com = common_prefix(*[
                        [i.cond for i in j] for j in pargs])
                    n = len(com)
                    collected = []
                    for i in range(n):
                        collected.append((
                            expr.func(*[ai[i].expr for ai in pargs]),
                            com[i]))
                    remains = []
                    for a in pargs:
                        if n == len(a):  # no more args
                            continue
                        if a[n].cond == True:  # no longer Piecewise
                            remains.append(a[n].expr)
                        else:  # restore the remaining Piecewise
                            remains.append(
                                Piecewise(*a[n:], evaluate=False))
                    if remains:
                        collected.append((expr.func(*remains), True))
                    args.append(Piecewise(*collected, evaluate=False))
                    continue
                args.extend(pc[c])
        else:
            args = expr.args
        # fold
        folded = list(map(piecewise_fold, args))
        for ec in cartes(*[
                (i.args if isinstance(i, Piecewise) else
                 [(i, true)]) for i in folded]):
            e, c = zip(*ec)
            new_args.append((expr.func(*e), And(*c)))

    return Piecewise(*new_args)
开发者ID:Lenqth,项目名称:sympy,代码行数:95,代码来源:piecewise.py


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