本文整理汇总了Python中sympy.core.mul.Mul.could_extract_minus_sign方法的典型用法代码示例。如果您正苦于以下问题：Python Mul.could_extract_minus_sign方法的具体用法？Python Mul.could_extract_minus_sign怎么用？Python Mul.could_extract_minus_sign使用的例子？那么恭喜您, 这里精选的方法代码示例或许可以为您提供帮助。您也可以进一步了解该方法所在类sympy.core.mul.Mul的用法示例。
在下文中一共展示了Mul.could_extract_minus_sign方法的1个代码示例，这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞，您的评价将有助于系统推荐出更棒的Python代码示例。
示例1: eval
# 需要导入模块: from sympy.core.mul import Mul [as 别名]
# 或者: from sympy.core.mul.Mul import could_extract_minus_sign [as 别名]
#.........这里部分代码省略.........
return p
elif isinstance(p, Add):
# separating into modulus and non modulus
both_l = non_mod_l, mod_l = [], []
for arg in p.args:
both_l[isinstance(arg, cls)].append(arg)
# if q same for all
if mod_l and all(inner.args[1] == q for inner in mod_l):
net = Add(*non_mod_l) + Add(*[i.args[0] for i in mod_l])
return cls(net, q)
elif isinstance(p, Mul):
# separating into modulus and non modulus
both_l = non_mod_l, mod_l = [], []
for arg in p.args:
both_l[isinstance(arg, cls)].append(arg)
if mod_l and all(inner.args[1] == q for inner in mod_l):
# finding distributive term
non_mod_l = [cls(x, q) for x in non_mod_l]
mod = []
non_mod = []
for j in non_mod_l:
if isinstance(j, cls):
mod.append(j.args[0])
else:
non_mod.append(j)
prod_mod = Mul(*mod)
prod_non_mod = Mul(*non_mod)
prod_mod1 = Mul(*[i.args[0] for i in mod_l])
net = prod_mod1*prod_mod
return prod_non_mod*cls(net, q)
if q.is_Integer and q is not S.One:
_ = []
for i in non_mod_l:
if i.is_Integer and (i % q is not S.Zero):
_.append(i%q)
else:
_.append(i)
non_mod_l = _
p = Mul(*(non_mod_l + mod_l))
# XXX other possibilities?
# extract gcd; any further simplification should be done by the user
G = gcd(p, q)
if G != 1:
p, q = [
gcd_terms(i/G, clear=False, fraction=False) for i in (p, q)]
pwas, qwas = p, q
# simplify terms
# (x + y + 2) % x -> Mod(y + 2, x)
if p.is_Add:
args = []
for i in p.args:
a = cls(i, q)
if a.count(cls) > i.count(cls):
args.append(i)
else:
args.append(a)
if args != list(p.args):
p = Add(*args)
else:
# handle coefficients if they are not Rational
# since those are not handled by factor_terms
# e.g. Mod(.6*x, .3*y) -> 0.3*Mod(2*x, y)
cp, p = p.as_coeff_Mul()
cq, q = q.as_coeff_Mul()
ok = False
if not cp.is_Rational or not cq.is_Rational:
r = cp % cq
if r == 0:
G *= cq
p *= int(cp/cq)
ok = True
if not ok:
p = cp*p
q = cq*q
# simple -1 extraction
if p.could_extract_minus_sign() and q.could_extract_minus_sign():
G, p, q = [-i for i in (G, p, q)]
# check again to see if p and q can now be handled as numbers
rv = doit(p, q)
if rv is not None:
return rv*G
# put 1.0 from G on inside
if G.is_Float and G == 1:
p *= G
return cls(p, q, evaluate=False)
elif G.is_Mul and G.args[0].is_Float and G.args[0] == 1:
p = G.args[0]*p
G = Mul._from_args(G.args[1:])
return G*cls(p, q, evaluate=(p, q) != (pwas, qwas))