本文整理汇总了Python中sympy.Symbol.match方法的典型用法代码示例。如果您正苦于以下问题：Python Symbol.match方法的具体用法？Python Symbol.match怎么用？Python Symbol.match使用的例子？那么恭喜您, 这里精选的方法代码示例或许可以为您提供帮助。您也可以进一步了解该方法所在类sympy.Symbol的用法示例。
在下文中一共展示了Symbol.match方法的1个代码示例，这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞，您的评价将有助于系统推荐出更棒的Python代码示例。
示例1: test_issue_1460
# 需要导入模块: from sympy import Symbol [as 别名]
# 或者: from sympy.Symbol import match [as 别名]
def test_issue_1460():
x = Symbol('x')
e = Symbol('e')
w = Wild('w', exclude=[x])
y = Wild('y')
# this is as it should be
assert (3/x).match(w/y) == {w: 3, y: x}
assert (3*x).match(w*y) == {w: 3, y: x}
assert (x/3).match(y/w) == {w: 3, y: x}
assert (3*x).match(y/w) == {w: S(1)/3, y: x}
# these could be allowed to fail
assert (x/3).match(w/y) == {w: S(1)/3, y: 1/x}
assert (3*x).match(w/y) == {w: 3, y: 1/x}
assert (3/x).match(w*y) == {w: 3, y: 1/x}
# Note that solve will give
# multiple roots but match only gives one:
#
# >>> solve(x**r-y**2,y)
# [-x**(r/2), x**(r/2)]
r = Symbol('r', rational=True)
assert (x**r).match(y**2) == {y: x**(r/2)}
assert (x**e).match(y**2) == {y: sqrt(x**e)}
# since (x**i = y) -> x = y**(1/i) where i is an integer
# the following should also be valid as long as y is not
# zero when i is negative.
a = Wild('a')
e = S(0)
assert e.match(a) == {a: e}
assert e.match(1/a) is None
assert e.match(a**.3) is None
e = S(3)
assert e.match(1/a) == {a: 1/e}
assert e.match(1/a**2) == {a: 1/sqrt(e)}
e = pi
assert e.match(1/a) == {a: 1/e}
assert e.match(1/a**2) == {a: 1/sqrt(e)}
assert (-e).match(sqrt(a)) is None
assert (-e).match(a**2) == {a: I*sqrt(pi)}