本文整理汇总了Python中sympy.Rational.subs方法的典型用法代码示例。如果您正苦于以下问题:Python Rational.subs方法的具体用法?Python Rational.subs怎么用?Python Rational.subs使用的例子?那么恭喜您, 这里精选的方法代码示例或许可以为您提供帮助。您也可以进一步了解该方法所在类sympy.Rational
的用法示例。
在下文中一共展示了Rational.subs方法的2个代码示例,这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞,您的评价将有助于系统推荐出更棒的Python代码示例。
示例1: test_composite_sums
# 需要导入模块: from sympy import Rational [as 别名]
# 或者: from sympy.Rational import subs [as 别名]
def test_composite_sums():
f = Rational(1, 2)*(7 - 6*n + Rational(1, 7)*n**3)
s = summation(f, (n, a, b))
assert not isinstance(s, Sum)
A = 0
for i in range(-3, 5):
A += f.subs(n, i)
B = s.subs(a, -3).subs(b, 4)
assert A == B
示例2: laguerre_poly
# 需要导入模块: from sympy import Rational [as 别名]
# 或者: from sympy.Rational import subs [as 别名]
print alphavar, nvar, LaguerreP.subs(n, nvar).subs(alpha, alphavar).doit(), LaguerreP.subs(n, nvar).subs(
alpha, alphavar
).doit() == laguerre_poly(
nvar, x, alpha=alphavar
) # True
(LaguerreF.subs(n, n + 1) / LaguerreF).simplify() # (alpha + n + 1)/(-k + n + 1)
(LaguerreF.subs(k, k + 1) / LaguerreF).simplify() # x*(k - n)/((k + 1)*(alpha + k + 1))
LegendreF = Rat(1) / (Rat(2) ** n) * (binomial(n, k)) ** 2 * (x - Rat(1)) ** k * (x + Rat(1)) ** (n - k)
LegendreP = Sum(LegendreF, (k, 0, n))
for nvar in range(4):
legendre_poly(nvar, x) == LegendreP.subs(n, nvar).doit().expand() # True
(LegendreF.subs(n, n + 1) / LegendreF).simplify() # (n + 1)**2*(x + 1)/(2*(k - n - 1)**2)
(LegendreF.subs(k, k + 1) / LegendreF).simplify() # (k - n)**2*(x - 1)/((k + 1)**2*(x + 1))
JacobiF = (
Rat(1)
/ (Rat(2) ** n)
* binomial(n + alpha, n - k)
* binomial(n + beta, k)
* (x - Rat(1)) ** k
* (x + Rat(1)) ** (n - k)
)
JacobiP = Sum(JacobiF, (k, 0, n))
for alphvar in range(5):
for betvar in range(5):
for nvar in range(5):
jacobi_poly(nvar, alphvar, betvar, x) == JacobiP.subs(n, nvar).subs(alpha, alphvar).subs(