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Python sympy.acosh函数代码示例

本文整理汇总了Python中sympy.acosh函数的典型用法代码示例。如果您正苦于以下问题:Python acosh函数的具体用法?Python acosh怎么用?Python acosh使用的例子?那么恭喜您, 这里精选的函数代码示例或许可以为您提供帮助。


在下文中一共展示了acosh函数的15个代码示例,这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞,您的评价将有助于系统推荐出更棒的Python代码示例。

示例1: test_acosh_series

def test_acosh_series():
    x = Symbol('x')
    assert acosh(x).series(x, 0, 8) == \
            -I*x + pi*I/2 - I*x**3/6 - 3*I*x**5/40 - 5*I*x**7/112 + O(x**8)
    t5 = acosh(x).taylor_term(5, x)
    assert t5 == - 3*I*x**5/40
    assert acosh(x).taylor_term(7, x, t5, 0) == - 5*I*x**7/112
开发者ID:Aang,项目名称:sympy,代码行数:7,代码来源:test_hyperbolic.py

示例2: test_acosh

def test_acosh():
    # TODO please write more tests  -- see #652
    # From http://functions.wolfram.com/ElementaryFunctions/ArcCosh/03/01/
    # at specific points
    assert acosh(1) == 0
    assert acosh(-1) == pi*I
    assert acosh(0) == I*pi/2
    assert acosh(Rational(1,2))  == I*pi/3
    assert acosh(Rational(-1,2)) == 2*pi*I/3
开发者ID:Aang,项目名称:sympy,代码行数:9,代码来源:test_hyperbolic.py

示例3: test_asech

def test_asech():
    x = Symbol('x')

    assert asech(-x) == asech(-x)

    # values at fixed points
    assert asech(1) == 0
    assert asech(-1) == pi*I
    assert asech(0) == oo
    assert asech(2) == I*pi/3
    assert asech(-2) == 2*I*pi / 3

    # at infinites
    assert asech(oo) == I*pi/2
    assert asech(-oo) == I*pi/2
    assert asech(zoo) == nan

    assert asech(I) == log(1 + sqrt(2)) - I*pi/2
    assert asech(-I) == log(1 + sqrt(2)) + I*pi/2
    assert asech(sqrt(2) - sqrt(6)) == 11*I*pi / 12
    assert asech(sqrt(2 - 2/sqrt(5))) == I*pi / 10
    assert asech(-sqrt(2 - 2/sqrt(5))) == 9*I*pi / 10
    assert asech(2 / sqrt(2 + sqrt(2))) == I*pi / 8
    assert asech(-2 / sqrt(2 + sqrt(2))) == 7*I*pi / 8
    assert asech(sqrt(5) - 1) == I*pi / 5
    assert asech(1 - sqrt(5)) == 4*I*pi / 5
    assert asech(-sqrt(2*(2 + sqrt(2)))) == 5*I*pi / 8

    # properties
    # asech(x) == acosh(1/x)
    assert asech(sqrt(2)) == acosh(1/sqrt(2))
    assert asech(2/sqrt(3)) == acosh(sqrt(3)/2)
    assert asech(2/sqrt(2 + sqrt(2))) == acosh(sqrt(2 + sqrt(2))/2)
    assert asech(S(2)) == acosh(1/S(2))

    # asech(x) == I*acos(1/x)
    # (Note: the exact formula is asech(x) == +/- I*acos(1/x))
    assert asech(-sqrt(2)) == I*acos(-1/sqrt(2))
    assert asech(-2/sqrt(3)) == I*acos(-sqrt(3)/2)
    assert asech(-S(2)) == I*acos(-S.Half)
    assert asech(-2/sqrt(2)) == I*acos(-sqrt(2)/2)

    # sech(asech(x)) / x == 1
    assert expand_mul(sech(asech(sqrt(6) - sqrt(2))) / (sqrt(6) - sqrt(2))) == 1
    assert expand_mul(sech(asech(sqrt(6) + sqrt(2))) / (sqrt(6) + sqrt(2))) == 1
    assert (sech(asech(sqrt(2 + 2/sqrt(5)))) / (sqrt(2 + 2/sqrt(5)))).simplify() == 1
    assert (sech(asech(-sqrt(2 + 2/sqrt(5)))) / (-sqrt(2 + 2/sqrt(5)))).simplify() == 1
    assert (sech(asech(sqrt(2*(2 + sqrt(2))))) / (sqrt(2*(2 + sqrt(2))))).simplify() == 1
    assert expand_mul(sech(asech((1 + sqrt(5)))) / ((1 + sqrt(5)))) == 1
    assert expand_mul(sech(asech((-1 - sqrt(5)))) / ((-1 - sqrt(5)))) == 1
    assert expand_mul(sech(asech((-sqrt(6) - sqrt(2)))) / ((-sqrt(6) - sqrt(2)))) == 1

    # numerical evaluation
    assert str(asech(5*I).n(6)) == '0.19869 - 1.5708*I'
    assert str(asech(-5*I).n(6)) == '0.19869 + 1.5708*I'
开发者ID:certik,项目名称:sympy,代码行数:55,代码来源:test_hyperbolic.py

示例4: test_manualintegrate_inversetrig

def test_manualintegrate_inversetrig():
    # atan
    assert manualintegrate(exp(x) / (1 + exp(2*x)), x) == atan(exp(x))
    assert manualintegrate(1 / (4 + 9 * x**2), x) == atan(3 * x/2) / 6
    assert manualintegrate(1 / (16 + 16 * x**2), x) == atan(x) / 16
    assert manualintegrate(1 / (4 + x**2), x) == atan(x / 2) / 2
    assert manualintegrate(1 / (1 + 4 * x**2), x) == atan(2*x) / 2
    assert manualintegrate(1/(a + b*x**2), x) == \
        Piecewise(((sqrt(a/b)*atan(x*sqrt(b/a))/a), And(a > 0, b > 0)))
    assert manualintegrate(1/(4 + b*x**2), x) == \
        Piecewise((sqrt(1/b)*atan(sqrt(b)*x/2)/2, b > 0))
    assert manualintegrate(1/(a + 4*x**2), x) == \
        Piecewise((atan(2*x*sqrt(1/a))/(2*sqrt(a)), a > 0))
    assert manualintegrate(1/(4 + 4*x**2), x) == atan(x) / 4

    # asin
    assert manualintegrate(1/sqrt(1-x**2), x) == asin(x)
    assert manualintegrate(1/sqrt(4-4*x**2), x) == asin(x)/2
    assert manualintegrate(3/sqrt(1-9*x**2), x) == asin(3*x)
    assert manualintegrate(1/sqrt(4-9*x**2), x) == asin(3*x/2)/3

    # asinh
    assert manualintegrate(1/sqrt(x**2 + 1), x) == \
        asinh(x)
    assert manualintegrate(1/sqrt(x**2 + 4), x) == \
        asinh(x/2)
    assert manualintegrate(1/sqrt(4*x**2 + 4), x) == \
        asinh(x)/2
    assert manualintegrate(1/sqrt(4*x**2 + 1), x) == \
        asinh(2*x)/2
    assert manualintegrate(1/sqrt(a*x**2 + 1), x) == \
        Piecewise((sqrt(-1/a)*asin(x*sqrt(-a)), a < 0), (sqrt(1/a)*asinh(sqrt(a)*x), a > 0))
    assert manualintegrate(1/sqrt(a + x**2), x) == \
        Piecewise((asinh(x*sqrt(1/a)), a > 0), (acosh(x*sqrt(-1/a)), a < 0))

    # acosh
    assert manualintegrate(1/sqrt(x**2 - 1), x) == \
        acosh(x)
    assert manualintegrate(1/sqrt(x**2 - 4), x) == \
        acosh(x/2)
    assert manualintegrate(1/sqrt(4*x**2 - 4), x) == \
        acosh(x)/2
    assert manualintegrate(1/sqrt(9*x**2 - 1), x) == \
        acosh(3*x)/3
    assert manualintegrate(1/sqrt(a*x**2 - 4), x) == \
        Piecewise((sqrt(1/a)*acosh(sqrt(a)*x/2), a > 0))
    assert manualintegrate(1/sqrt(-a + 4*x**2), x) == \
        Piecewise((asinh(2*x*sqrt(-1/a))/2, -a > 0), (acosh(2*x*sqrt(1/a))/2, -a < 0))

    # piecewise
    assert manualintegrate(1/sqrt(a-b*x**2), x) == \
        Piecewise((sqrt(a/b)*asin(x*sqrt(b/a))/sqrt(a), And(-b < 0, a > 0)),
                  (sqrt(-a/b)*asinh(x*sqrt(-b/a))/sqrt(a), And(-b > 0, a > 0)),
                  (sqrt(a/b)*acosh(x*sqrt(b/a))/sqrt(-a), And(-b > 0, a < 0)))
    assert manualintegrate(1/sqrt(a + b*x**2), x) == \
        Piecewise((sqrt(-a/b)*asin(x*sqrt(-b/a))/sqrt(a), And(a > 0, b < 0)),
                  (sqrt(a/b)*asinh(x*sqrt(b/a))/sqrt(a), And(a > 0, b > 0)),
                  (sqrt(-a/b)*acosh(x*sqrt(-b/a))/sqrt(-a), And(a < 0, b > 0)))
开发者ID:A-turing-machine,项目名称:sympy,代码行数:58,代码来源:test_manual.py

示例5: test_simplifications

def test_simplifications():
    x = Symbol("x")
    assert sinh(asinh(x)) == x
    assert sinh(acosh(x)) == sqrt(x - 1) * sqrt(x + 1)
    assert sinh(atanh(x)) == x / sqrt(1 - x ** 2)

    assert cosh(asinh(x)) == sqrt(1 + x ** 2)
    assert cosh(acosh(x)) == x
    assert cosh(atanh(x)) == 1 / sqrt(1 - x ** 2)

    assert tanh(asinh(x)) == x / sqrt(1 + x ** 2)
    assert tanh(acosh(x)) == sqrt(x - 1) * sqrt(x + 1) / x
    assert tanh(atanh(x)) == x
开发者ID:rkern,项目名称:sympy-rkern,代码行数:13,代码来源:test_hyperbolic.py

示例6: test_messy

def test_messy():
    from sympy import (laplace_transform, Si, Shi, Chi, atan, Piecewise,
                       acoth, E1, besselj, acosh, asin, And, re,
                       fourier_transform, sqrt)
    assert laplace_transform(Si(x), x, s) == ((-atan(s) + pi/2)/s, 0, True)

    assert laplace_transform(Shi(x), x, s) == (acoth(s)/s, 1, True)

    # where should the logs be simplified?
    assert laplace_transform(Chi(x), x, s) == \
        ((log(s**(-2)) - log((s**2 - 1)/s**2))/(2*s), 1, True)

    # TODO maybe simplify the inequalities?
    assert laplace_transform(besselj(a, x), x, s)[1:] == \
        (0, And(S(0) < re(a/2) + S(1)/2, S(0) < re(a/2) + 1))

    # NOTE s < 0 can be done, but argument reduction is not good enough yet
    assert fourier_transform(besselj(1, x)/x, x, s, noconds=False) == \
        (Piecewise((0, 4*abs(pi**2*s**2) > 1),
                   (2*sqrt(-4*pi**2*s**2 + 1), True)), s > 0)
    # TODO FT(besselj(0,x)) - conditions are messy (but for acceptable reasons)
    #                       - folding could be better

    assert integrate(E1(x)*besselj(0, x), (x, 0, oo), meijerg=True) == \
        log(1 + sqrt(2))
    assert integrate(E1(x)*besselj(1, x), (x, 0, oo), meijerg=True) == \
        log(S(1)/2 + sqrt(2)/2)

    assert integrate(1/x/sqrt(1 - x**2), x, meijerg=True) == \
        Piecewise((-acosh(1/x), 1 < abs(x**(-2))), (I*asin(1/x), True))
开发者ID:chaffra,项目名称:sympy,代码行数:30,代码来源:test_meijerint.py

示例7: test_issue_1304

def test_issue_1304():
    z = Symbol("z", positive=True)
    assert integrate(sqrt(x ** 2 + z ** 2), x) == z ** 2 * asinh(x / z) / 2 + x * (x ** 2 + z ** 2) ** (S(1) / 2) / 2
    assert integrate(sqrt(x ** 2 - z ** 2), x) == -z ** 2 * acosh(x / z) / 2 + x * (x ** 2 - z ** 2) ** (S(1) / 2) / 2
    assert (
        integrate(sqrt(-x ** 2 - 4), x)
        == -2 * atan(x / (-4 - x ** 2) ** (S(1) / 2)) + x * (-4 - x ** 2) ** (S(1) / 2) / 2
    )
开发者ID:vks,项目名称:sympy,代码行数:8,代码来源:test_integrals.py

示例8: test_inverses

def test_inverses():
    x = Symbol('x')
    assert sinh(x).inverse() == asinh
    raises(AttributeError, lambda: cosh(x).inverse())
    assert tanh(x).inverse() == atanh
    assert coth(x).inverse() == acoth
    assert asinh(x).inverse() == sinh
    assert acosh(x).inverse() == cosh
    assert atanh(x).inverse() == tanh
    assert acoth(x).inverse() == coth
开发者ID:Bercio,项目名称:sympy,代码行数:10,代码来源:test_hyperbolic.py

示例9: test_hyperbolic

def test_hyperbolic():
    x = Symbol("x")
    assert sinh(x).nseries(x, 0, 6) == x + x**3/6 + x**5/120 + O(x**6)
    assert cosh(x).nseries(x, 0, 5) == 1 + x**2/2 + x**4/24 + O(x**5)
    assert tanh(x).nseries(x, 0, 6) == x - x**3/3 + 2*x**5/15 + O(x**6)
    assert coth(x).nseries(x, 0, 6) == 1/x - x**3/45 + x/3 + 2*x**5/945 + O(x**6)
    assert asinh(x).nseries(x, 0, 6) == x - x**3/6 + 3*x**5/40 + O(x**6)
    assert acosh(x).nseries(x, 0, 6) == pi*I/2 - I*x - 3*I*x**5/40 - I*x**3/6 + O(x**6)
    assert atanh(x).nseries(x, 0, 6) == x + x**3/3 + x**5/5 + O(x**6)
    assert acoth(x).nseries(x, 0, 6) == x + x**3/3 + x**5/5 + pi*I/2 + O(x**6)
开发者ID:jcockayne,项目名称:sympy-rkern,代码行数:10,代码来源:test_nseries.py

示例10: test_derivs

def test_derivs():
    x = Symbol('x')
    assert coth(x).diff(x) == -sinh(x)**(-2)
    assert sinh(x).diff(x) == cosh(x)
    assert cosh(x).diff(x) == sinh(x)
    assert tanh(x).diff(x) == -tanh(x)**2 + 1
    assert acoth(x).diff(x) == 1/(-x**2 + 1)
    assert asinh(x).diff(x) == 1/sqrt(x**2 + 1)
    assert acosh(x).diff(x) == 1/sqrt(x**2 - 1)
    assert atanh(x).diff(x) == 1/(-x**2 + 1)
开发者ID:Bercio,项目名称:sympy,代码行数:10,代码来源:test_hyperbolic.py

示例11: test_conv12b

def test_conv12b():
    x = sympy.Symbol("x")
    y = sympy.Symbol("y")
    assert sympify(sympy.sinh(x/3)) == sinh(Symbol("x") / 3)
    assert sympify(sympy.cosh(x/3)) == cosh(Symbol("x") / 3)
    assert sympify(sympy.tanh(x/3)) == tanh(Symbol("x") / 3)
    assert sympify(sympy.coth(x/3)) == coth(Symbol("x") / 3)
    assert sympify(sympy.asinh(x/3)) == asinh(Symbol("x") / 3)
    assert sympify(sympy.acosh(x/3)) == acosh(Symbol("x") / 3)
    assert sympify(sympy.atanh(x/3)) == atanh(Symbol("x") / 3)
    assert sympify(sympy.acoth(x/3)) == acoth(Symbol("x") / 3)
开发者ID:cbehan,项目名称:symengine.py,代码行数:11,代码来源:test_sympy_conv.py

示例12: test_leading_term

def test_leading_term():
    x = Symbol('x')
    assert cosh(x).as_leading_term(x) == 1
    assert coth(x).as_leading_term(x) == 1/x
    assert acosh(x).as_leading_term(x) == I*pi/2
    assert acoth(x).as_leading_term(x) == I*pi/2
    for func in [sinh, tanh, asinh, atanh]:
        assert func(x).as_leading_term(x) == x
    for func in [sinh, cosh, tanh, coth, asinh, acosh, atanh, acoth]:
        for arg in (1/x, S.Half):
            eq = func(arg)
            assert eq.as_leading_term(x) == eq
开发者ID:Devendra0910,项目名称:sympy,代码行数:12,代码来源:test_hyperbolic.py

示例13: test_numpy_numexpr

def test_numpy_numexpr():
    if not numpy:
        skip("numpy not installed.")
    if not numexpr:
        skip("numexpr not installed.")
    a, b, c = numpy.random.randn(3, 128, 128)
    # ensure that numpy and numexpr return same value for complicated expression
    expr = sin(x) + cos(y) + tan(z)**2 + Abs(z-y)*acos(sin(y*z)) + \
           Abs(y-z)*acosh(2+exp(y-x))- sqrt(x**2+I*y**2)
    npfunc = lambdify((x, y, z), expr, modules='numpy')
    nefunc = lambdify((x, y, z), expr, modules='numexpr')
    assert numpy.allclose(npfunc(a, b, c), nefunc(a, b, c))
开发者ID:KonstantinTogoi,项目名称:sympy,代码行数:12,代码来源:test_lambdify.py

示例14: test_simplifications

def test_simplifications():
    x = Symbol('x')
    assert sinh(asinh(x)) == x
    assert sinh(acosh(x)) == sqrt(x - 1) * sqrt(x + 1)
    assert sinh(atanh(x)) == x/sqrt(1 - x**2)
    assert sinh(acoth(x)) == 1/(sqrt(x - 1) * sqrt(x + 1))

    assert cosh(asinh(x)) == sqrt(1 + x**2)
    assert cosh(acosh(x)) == x
    assert cosh(atanh(x)) == 1/sqrt(1 - x**2)
    assert cosh(acoth(x)) == x/(sqrt(x - 1) * sqrt(x + 1))

    assert tanh(asinh(x)) == x/sqrt(1 + x**2)
    assert tanh(acosh(x)) == sqrt(x - 1) * sqrt(x + 1) / x
    assert tanh(atanh(x)) == x
    assert tanh(acoth(x)) == 1/x

    assert coth(asinh(x)) == sqrt(1 + x**2)/x
    assert coth(acosh(x)) == x/(sqrt(x - 1) * sqrt(x + 1))
    assert coth(atanh(x)) == 1/x
    assert coth(acoth(x)) == x

    assert csch(asinh(x)) == 1/x
    assert csch(acosh(x)) == 1/(sqrt(x - 1) * sqrt(x + 1))
    assert csch(atanh(x)) == sqrt(1 - x**2)/x
    assert csch(acoth(x)) == sqrt(x - 1) * sqrt(x + 1)

    assert sech(asinh(x)) == 1/sqrt(1 + x**2)
    assert sech(acosh(x)) == 1/x
    assert sech(atanh(x)) == sqrt(1 - x**2)
    assert sech(acoth(x)) == sqrt(x - 1) * sqrt(x + 1)/x
开发者ID:certik,项目名称:sympy,代码行数:31,代码来源:test_hyperbolic.py

示例15: test_issue_4403

def test_issue_4403():
    x = Symbol('x')
    y = Symbol('y')
    z = Symbol('z', positive=True)
    assert integrate(sqrt(x**2 + z**2), x) == \
        z**2*asinh(x/z)/2 + x*sqrt(x**2 + z**2)/2
    assert integrate(sqrt(x**2 - z**2), x) == \
        -z**2*acosh(x/z)/2 + x*sqrt(x**2 - z**2)/2

    x = Symbol('x', real=True)
    y = Symbol('y', positive=True)
    assert integrate(1/(x**2 + y**2)**S('3/2'), x) == \
        x/(y**2*sqrt(x**2 + y**2))
开发者ID:baoqchau,项目名称:sympy,代码行数:13,代码来源:test_integrals.py


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