Python Popen.__init__方法代码示例

# 需要导入模块: from subprocess32 import Popen [as 别名]
# 或者: from subprocess32.Popen import __init__ [as 别名]
    def __init__(self, cmd, cwd=None, env=None, flags=None,
                 stdin=PIPE, stdout=PIPE, stderr=PIPE,
                 universal_newlines=True):
        """Create a child process.

        "cmd" is the command to run, either a list of arguments or a string.
        "cwd" is a working directory in which to start the child process.
        "env" is an environment dictionary for the child.
        "flags" are system-specific process creation flags. On Windows
            this can be a bitwise-OR of any of the win32process.CREATE_*
            constants (Note: win32process.CREATE_NEW_PROCESS_GROUP is always
            OR'd in). On Unix, this is currently ignored.
        "stdin", "stdout", "stderr" can be used to specify file objects
            to handle read (stdout/stderr) and write (stdin) events from/to
            the child. By default a file handle will be created for each
            io channel automatically, unless set explicitly to None. When set
            to None, the parent io handles will be used, which can mean the
            output is redirected to Komodo's log files.
        "universal_newlines": On by default (the opposite of subprocess).
        """
        self._child_created = False
        self.__use_killpg = False
        auto_piped_stdin = False
        preexec_fn = None
        shell = False
        if not isinstance(cmd, (list, tuple)):
            # The cmd is the already formatted, ready for the shell. Otherwise
            # subprocess.Popen will treat this as simply one command with
            # no arguments, resulting in an unknown command.
            shell = True
        if sys.platform.startswith("win"):
            # On Windows, cmd requires some special handling of multiple quoted
            # arguments, as this is what cmd will do:
            #    See if the first character is a quote character and if so,
            #    strip the leading character and remove the last quote character
            #    on the command line, preserving any text after the last quote
            #    character.
            if cmd and shell and cmd.count('"') > 2:
                if not cmd.startswith('""') or not cmd.endswith('""'):
                    # Needs to be a re-quoted with additional double quotes.
                    # http://bugs.activestate.com/show_bug.cgi?id=75467
                    cmd = '"%s"' % (cmd, )

            # XXX - subprocess needs to be updated to use the wide string API.
            # subprocess uses a Windows API that does not accept unicode, so
            # we need to convert all the environment variables to strings
            # before we make the call. Temporary fix to bug:
            #   http://bugs.activestate.com/show_bug.cgi?id=72311
            if env:
                encoding = sys.getfilesystemencoding()
                _enc_env = {}
                for key, value in env.items():
                    try:
                        _enc_env[key.encode(encoding)] = value.encode(encoding)
                    except (UnicodeEncodeError, UnicodeDecodeError):
                        # Could not encode it, warn we are dropping it.
                        log.warn("Could not encode environment variable %r "
                                 "so removing it", key)
                env = _enc_env

            if flags is None:
                flags = CREATE_NO_WINDOW

            # If we don't have standard handles to pass to the child process
            # (e.g. we don't have a console app), then
            # `subprocess.GetStdHandle(...)` will return None. `subprocess.py`
            # handles that (http://bugs.python.org/issue1124861)
            #
            # However, if Komodo is started from the command line, then
            # the shell's stdin handle is inherited, i.e. in subprocess.py:
            #      p2cread = GetStdHandle(STD_INPUT_HANDLE)   # p2cread == 3
            # A few lines later this leads to:
            #    Traceback (most recent call last):
            #      ...
            #      File "...\lib\mozilla\python\komodo\process.py", line 130, in __init__
            #        creationflags=flags)
            #      File "...\lib\python\lib\subprocess.py", line 588, in __init__
            #        errread, errwrite) = self._get_handles(stdin, stdout, stderr)
            #      File "...\lib\python\lib\subprocess.py", line 709, in _get_handles
            #        p2cread = self._make_inheritable(p2cread)
            #      File "...\lib\python\lib\subprocess.py", line 773, in _make_inheritable
            #        DUPLICATE_SAME_ACCESS)
            #    WindowsError: [Error 6] The handle is invalid
            #
            # I suspect this indicates that the stdin handle inherited by
            # the subsystem:windows komodo.exe process is invalid -- perhaps
            # because of mis-used of the Windows API for passing that handle
            # through. The same error can be demonstrated in PythonWin:
            #   from _subprocess import *
            #   from subprocess import *
            #   h = GetStdHandle(STD_INPUT_HANDLE)
            #   p = Popen("python -c '1'")
            #   p._make_interitable(h)
            #
            # I don't understand why the inherited stdin is invalid for
            # `DuplicateHandle`, but here is how we are working around this:
            # If we detect the condition where this can fail, then work around
            # it by setting the handle to `subprocess.PIPE`, resulting in
            # a different and workable code path.
            if self._needToHackAroundStdHandles() \
#.........这里部分代码省略.........

# 需要导入模块: from subprocess32 import Popen [as 别名]
# 或者: from subprocess32.Popen import __init__ [as 别名]
 def __init__(self, cargs, *args, **kwargs):
     Popen.__init__(self, cargs, *args, start_new_session=True)
     self.args = cargs