当前位置: 首页>>代码示例>>Python>>正文


Python LineString.overlaps方法代码示例

本文整理汇总了Python中shapely.geometry.LineString.overlaps方法的典型用法代码示例。如果您正苦于以下问题:Python LineString.overlaps方法的具体用法?Python LineString.overlaps怎么用?Python LineString.overlaps使用的例子?那么恭喜您, 这里精选的方法代码示例或许可以为您提供帮助。您也可以进一步了解该方法所在shapely.geometry.LineString的用法示例。


在下文中一共展示了LineString.overlaps方法的1个代码示例,这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞,您的评价将有助于系统推荐出更棒的Python代码示例。

示例1: SpatialToplogy

# 需要导入模块: from shapely.geometry import LineString [as 别名]
# 或者: from shapely.geometry.LineString import overlaps [as 别名]
 def SpatialToplogy (Spatial_A,Spatial_B):
            if Spatial_A[4] == 'Point' and Spatial_B[4]== 'Point':
              Point_0=Point(Spatial_A[0],Spatial_A[1])
              Point_1=Point(Spatial_B[0],Spatial_B[1])
              #Point to point relationships
              if Point_0.equals(Point_1): return 'Point1 equals Point2'
              if Point_0.within(Point_1.buffer(2)): return 'Point1 lies within a buffer of 2 m from Point2'
              if Point_0.overlaps(Point_1): return 'Point1 overlaps Point2'
              #if Point_0.disjoint(Point_1): return 'Point1 disjoint Point2'
              
              #Point to line relationships
            if Spatial_A[4] == 'Point' and Spatial_B[4]== 'Line':
                 Point_0=Point(Spatial_A[0],Spatial_A[1])
                 Line_0=LineString([(Spatial_B[0],Spatial_B[1]),(Spatial_B[2],Spatial_B[3])])
                 if Point_0.touches(Line_0):return 'Point1 touches Line1'
                 if Point_0.within(Line_0.buffer(2)):return 'Point1 lies within a buffer of 2 m from L1'
              #Point to polygon relationships
            if Spatial_A[4] == 'Point' and Spatial_B[4]== 'Polygon':
                 Point_0=Point(Spatial_A[0],Spatial_A[1])
                 Polygon_0=Polygon([(Spatial_B[0],Spatial_B[1]),(Spatial_B[2],Spatial_B[1]),(Spatial_B[2],Spatial_B[3]),(Spatial_B[0],Spatial_B[3])])
                 if Point_0.touches(Polygon_0):return 'Point1 touches Polygon1'
                 if Point_0.within(Polygon_0):return'Point1 lies within Polygon1'
                 if Point_0.overlaps(Polygon_0):return 'Point1 lies overlaps Polygon1'
             #Line to line relationships
            if Spatial_A[4]=='Line' and Spatial_B[4]=='Line':
                 Line_0=LineString([(Spatial_A[0],Spatial_A[1]),(Spatial_A[2],Spatial_A[3])])
                 Line_1=LineString([(Spatial_B[0],Spatial_B[1]),(Spatial_B[2],Spatial_B[3])])
                 if Line_0.equals(Line_1):return 'Line0 equals Line1'
                 if Line_0.touches(Line_1):return 'Line0 touches Line1'
                 if Line_0.crosses(Line_1):return 'Line0 crosses Line1'
                 if Line_0.within(Line_1.buffer(2)):return 'Line0 lies within a buffer of 2 m Line1'
                 if Line_0.overlaps(Line_1):return 'Line0 overlaps Line1'
              #Line to polygon relationships  
            if Spatial_A[4]=='Line' and Spatial_B[4]=='Polygon':
                 Line_0=LineString([(Spatial_A[0],Spatial_A[1]),(Spatial_A[2],Spatial_A[3])])
                 Polygon_0=Polygon([(Spatial_B[0],Spatial_B[1]),(Spatial_B[2],Spatial_B[1]),(Spatial_B[2],Spatial_B[3]),(Spatial_B[0],Spatial_B[3])])
                 if Line_0.touches(Polygon_0):return 'Line0 touches Polygon1'
                 if Line_0.crosses(Polygon_0):return 'Line0 crosses Polygon1'
                 if Line_0.within(Polygon_0):return 'Line0 lies within Polygon1'
              #Polygon to Polygon relationships
            if Spatial_A[4]=='Polygon' and Spatial_B[4]=='Polygon':
                 Polygon_0=Polygon([(Spatial_A[0],Spatial_A[1]),(Spatial_A[2],Spatial_A[1]),(Spatial_A[2],Spatial_A[3]),(Spatial_A[0],Spatial_A[3])])
                 Polygon_1=Polygon([(Spatial_B[0],Spatial_B[1]),(Spatial_B[2],Spatial_B[1]),(Spatial_B[2],Spatial_B[3]),(Spatial_B[0],Spatial_B[3])])
                 if Polygon_0.touches(Polygon_1):return 'Polygon touches Polygon1'
                 if Polygon_0.equals(Polygon_1):return 'Polygon0 equals Polygon1'
                 if Polygon_0.within(Polygon_1):return 'Polygon lies within Polygon1'
                 if Polygon_0.within(Polygon_1.buffer(2)):return 'Polygon lies within a buffer of 2m  Polygon1'
开发者ID:HydroComplexity,项目名称:Data-Network,代码行数:49,代码来源:Datanetwork.py


注:本文中的shapely.geometry.LineString.overlaps方法示例由纯净天空整理自Github/MSDocs等开源代码及文档管理平台,相关代码片段筛选自各路编程大神贡献的开源项目,源码版权归原作者所有,传播和使用请参考对应项目的License;未经允许,请勿转载。