本文整理汇总了Python中scrapy.http.request.Request.meta['disease_questions']方法的典型用法代码示例。如果您正苦于以下问题：Python Request.meta['disease_questions']方法的具体用法？Python Request.meta['disease_questions']怎么用？Python Request.meta['disease_questions']使用的例子？那么恭喜您, 这里精选的方法代码示例或许可以为您提供帮助。您也可以进一步了解该方法所在类scrapy.http.request.Request的用法示例。
在下文中一共展示了Request.meta['disease_questions']方法的1个代码示例，这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞，您的评价将有助于系统推荐出更棒的Python代码示例。
示例1: _parse_disease_question
# 需要导入模块: from scrapy.http.request import Request [as 别名]
# 或者: from scrapy.http.request.Request import meta['disease_questions'] [as 别名]
def _parse_disease_question(self, response):
disease_question_item = response.meta.get('disease_questions')
if not disease_question_item:
disease_question_item = DiseaseQuestionItem()
disease_question_item['disease_name'] = response.meta['disease_item']['name']
disease_question_item['qids'] = []
# parse
urls = response.xpath('//div[@class="p_list_li"]/div[@class="p_list_cent"]/div[@class="p_list_centt"]/dl/dt/a/@href').extract()
disease_question_item['qids'] += [u.split('/')[-1].split('.')[0] for u in urls]
# last_url = response.xpath('//div[@class="portldet-content"]/a/@href').extract()[-1]
next_url = response.xpath('//div[@class="portlet-content"]/a[text()="下一页 >"]/@href').extract()
if not next_url:
# 所有页都处理完了
print disease_question_item
yield disease_question_item
else:
url = next_url[0]
# print url
# print disease_question_item['qids']
request = Request(url, dont_filter=True, callback=self._parse_disease_question)
request.meta['disease_questions'] = disease_question_item
# print request
yield request