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Python FormRequest.meta["large_category_name"]方法代码示例

本文整理汇总了Python中scrapy.FormRequest.meta["large_category_name"]方法的典型用法代码示例。如果您正苦于以下问题:Python FormRequest.meta["large_category_name"]方法的具体用法?Python FormRequest.meta["large_category_name"]怎么用?Python FormRequest.meta["large_category_name"]使用的例子?那么, 这里精选的方法代码示例或许可以为您提供帮助。您也可以进一步了解该方法所在scrapy.FormRequest的用法示例。


在下文中一共展示了FormRequest.meta["large_category_name"]方法的4个代码示例,这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞,您的评价将有助于系统推荐出更棒的Python代码示例。

示例1: _parse_list

# 需要导入模块: from scrapy import FormRequest [as 别名]
# 或者: from scrapy.FormRequest import meta["large_category_name"] [as 别名]
 def _parse_list(self, response):
     report_list = response.xpath("//div[@class=\"reportlist bluelink\"]/ul//a/@href")
     for report_url in report_list:
         request = FormRequest(urljoin(self.base_url, report_url.extract()), callback=self.parse_item, dont_filter=False)
         request.meta["large_category_name"] = response.meta["large_category_name"]
         request.meta["mid_category_name"] = response.meta["mid_category_name"]
         request.meta["report_type"] = response.meta["report_type"]
         yield request
开发者ID:hanwei2008,项目名称:crawl,代码行数:10,代码来源:chinaidrSpider.py

示例2: parse_middle_category

# 需要导入模块: from scrapy import FormRequest [as 别名]
# 或者: from scrapy.FormRequest import meta["large_category_name"] [as 别名]
 def parse_middle_category(self, response):
     report_types = response.xpath(u"//li[contains(text(),'报告')]")
     for report_type in report_types:
         mid_category_url = urljoin(self.base_url, report_type.xpath(u"./preceding-sibling::span[1]/a/@href").extract()[0])
         request = FormRequest(mid_category_url, callback=self.parse_page, dont_filter=True)
         request.meta["large_category_name"] = response.meta["large_category_name"]
         request.meta["mid_category_name"] = response.meta["mid_category_name"]
         request.meta["report_type"] = clean_text(report_type.xpath("./text()").extract()[0].strip())
         request.meta["page_base_url"] = mid_category_url
         yield request
开发者ID:hanwei2008,项目名称:crawl,代码行数:12,代码来源:chinaidrSpider.py

示例3: parse

# 需要导入模块: from scrapy import FormRequest [as 别名]
# 或者: from scrapy.FormRequest import meta["large_category_name"] [as 别名]
 def parse(self, response):
     large_categories = response.xpath("//*[@class='tabContent bluelink']//*[contains(@style, 'padding')]/a")
     for large_category in large_categories:
         large_category_name = clean_text(large_category.xpath(".//text()").extract()[0].strip())
         mid_categorys = large_category.xpath("./parent::*/following-sibling::*[1]/a")
         for mid_category in mid_categorys:
             mid_category_name = clean_text(mid_category.xpath("./text()").extract()[0])
             mid_category_url = urljoin(self.base_url, mid_category.xpath("./@href").extract()[0])
             request = FormRequest(mid_category_url, callback=self.parse_middle_category, dont_filter=True)
             request.meta["large_category_name"] = large_category_name
             request.meta["mid_category_name"] = mid_category_name
             yield request
开发者ID:hanwei2008,项目名称:crawl,代码行数:14,代码来源:chinaidrSpider.py

示例4: parse_page

# 需要导入模块: from scrapy import FormRequest [as 别名]
# 或者: from scrapy.FormRequest import meta["large_category_name"] [as 别名]
 def parse_page(self, response):
     request_list = self._parse_list(response)
     for r in request_list:
         yield r
     next_page = response.xpath(u"//*[@id='AspNetPager1']/a[text()=\"下一页\"]/@href")
     if len(next_page) > 0:
         next_page_url = urljoin(self.base_url, next_page.extract()[0])
         if not next_page_url.startswith(response.meta["page_base_url"]):
             if next_page_url.endswith("html"):
                 next_page_url = response.meta["page_base_url"] + next_page_url[next_page_url.rindex("/") + 1:len(next_page_url)]
         request = FormRequest(next_page_url, callback=self.parse_page, dont_filter=True)
         request.meta["large_category_name"] = response.meta["large_category_name"]
         request.meta["mid_category_name"] = response.meta["mid_category_name"]
         request.meta["report_type"] = response.meta["report_type"]
         request.meta["page_base_url"] = response.meta["page_base_url"]
         yield request
开发者ID:hanwei2008,项目名称:crawl,代码行数:18,代码来源:chinaidrSpider.py


注:本文中的scrapy.FormRequest.meta["large_category_name"]方法示例由纯净天空整理自Github/MSDocs等开源代码及文档管理平台,相关代码片段筛选自各路编程大神贡献的开源项目,源码版权归原作者所有,传播和使用请参考对应项目的License;未经允许,请勿转载。