本文整理汇总了Python中rx.core.Observable.merge方法的典型用法代码示例。如果您正苦于以下问题：Python Observable.merge方法的具体用法？Python Observable.merge怎么用？Python Observable.merge使用的例子？那么恭喜您, 这里精选的方法代码示例或许可以为您提供帮助。您也可以进一步了解该方法所在类rx.core.Observable的用法示例。
在下文中一共展示了Observable.merge方法的1个代码示例，这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞，您的评价将有助于系统推荐出更棒的Python代码示例。
示例1: merge
# 需要导入模块: from rx.core import Observable [as 别名]
# 或者: from rx.core.Observable import merge [as 别名]
def merge(self, *args, **kwargs):
"""Merges an observable sequence of observable sequences into an
observable sequence, limiting the number of concurrent subscriptions
to inner sequences. Or merges two observable sequences into a single
observable sequence.
1 - merged = sources.merge(1)
2 - merged = source.merge(other_source)
max_concurrent_or_other [Optional] Maximum number of inner observable
sequences being subscribed to concurrently or the second
observable sequence.
Returns the observable sequence that merges the elements of the inner
sequences.
"""
if not isinstance(args[0], int):
args = args + tuple([self])
return Observable.merge(*args, **kwargs)
max_concurrent = args[0]
sources = self
def subscribe(observer):
active_count = [0]
group = CompositeDisposable()
is_stopped = [False]
q = []
def subscribe(xs):
subscription = SingleAssignmentDisposable()
group.add(subscription)
def on_completed():
group.remove(subscription)
if len(q):
s = q.pop(0)
subscribe(s)
else:
active_count[0] -= 1
if is_stopped[0] and active_count[0] == 0:
observer.on_completed()
subscription.disposable = xs.subscribe(observer.on_next,
observer.on_error,
on_completed)
def on_next(inner_source):
if active_count[0] < max_concurrent:
active_count[0] += 1
subscribe(inner_source)
else:
q.append(inner_source)
def on_completed():
is_stopped[0] = True
if active_count[0] == 0:
observer.on_completed()
group.add(sources.subscribe(on_next, observer.on_error, on_completed))
return group
return AnonymousObservable(subscribe)