本文整理汇总了Python中rdflib.Graph.ConjunctiveGraph.open方法的典型用法代码示例。如果您正苦于以下问题：Python ConjunctiveGraph.open方法的具体用法？Python ConjunctiveGraph.open怎么用？Python ConjunctiveGraph.open使用的例子？那么恭喜您, 这里精选的方法代码示例或许可以为您提供帮助。您也可以进一步了解该方法所在类rdflib.Graph.ConjunctiveGraph的用法示例。
在下文中一共展示了ConjunctiveGraph.open方法的2个代码示例，这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞，您的评价将有助于系统推荐出更棒的Python代码示例。
示例1: testN3Store
# 需要导入模块: from rdflib.Graph import ConjunctiveGraph [as 别名]
# 或者: from rdflib.Graph.ConjunctiveGraph import open [as 别名]
def testN3Store(store="default", configString=None):
g = ConjunctiveGraph(store=store)
if configString:
g.destroy(configString)
g.open(configString)
g.parse(StringInputSource(testN3), format="n3")
print g.store
try:
for s,p,o in g.triples((None,implies,None)):
formulaA = s
formulaB = o
assert type(formulaA)==QuotedGraph and type(formulaB)==QuotedGraph
a = URIRef('http://test/a')
b = URIRef('http://test/b')
c = URIRef('http://test/c')
d = URIRef('http://test/d')
v = Variable('y')
universe = ConjunctiveGraph(g.store)
#test formula as terms
assert len(list(universe.triples((formulaA,implies,formulaB))))==1
#test variable as term and variable roundtrip
assert len(list(formulaB.triples((None,None,v))))==1
for s,p,o in formulaB.triples((None,d,None)):
if o != c:
assert isinstance(o,Variable)
assert o == v
s = list(universe.subjects(RDF.type, RDFS.Class))[0]
assert isinstance(s,BNode)
assert len(list(universe.triples((None,implies,None)))) == 1
assert len(list(universe.triples((None,RDF.type,None)))) ==1
assert len(list(formulaA.triples((None,RDF.type,None))))==1
assert len(list(formulaA.triples((None,None,None))))==2
assert len(list(formulaB.triples((None,None,None))))==2
assert len(list(universe.triples((None,None,None))))==3
assert len(list(formulaB.triples((None,URIRef('http://test/d'),None))))==2
assert len(list(universe.triples((None,URIRef('http://test/d'),None))))==1
#context tests
#test contexts with triple argument
assert len(list(universe.contexts((a,d,c))))==1
#Remove test cases
universe.remove((None,implies,None))
assert len(list(universe.triples((None,implies,None))))==0
assert len(list(formulaA.triples((None,None,None))))==2
assert len(list(formulaB.triples((None,None,None))))==2
formulaA.remove((None,b,None))
assert len(list(formulaA.triples((None,None,None))))==1
formulaA.remove((None,RDF.type,None))
assert len(list(formulaA.triples((None,None,None))))==0
universe.remove((None,RDF.type,RDFS.Class))
#remove_context tests
universe.remove_context(formulaB)
assert len(list(universe.triples((None,RDF.type,None))))==0
assert len(universe)==1
assert len(formulaB)==0
universe.remove((None,None,None))
assert len(universe)==0
g.store.destroy(configString)
except:
g.store.destroy(configString)
raise示例2: Namespace
# 需要导入模块: from rdflib.Graph import ConjunctiveGraph [as 别名]
# 或者: from rdflib.Graph.ConjunctiveGraph import open [as 别名]
from __future__ import division
import sys, time
sys.path.append('pytc-0.7/build/lib.linux-x86_64-2.5')
sys.path.insert(0, 'rdflib/build/lib.linux-x86_64-2.5')
from rdflib.Graph import ConjunctiveGraph
from rdflib import Namespace, Literal
EX = Namespace("http://example.com/")
graph = ConjunctiveGraph('TokyoCabinet')
graph.open("tcgraph", create=True)
graph.add((EX['hello'], EX['world'], Literal("lit")))
print list(graph.triples((None, None, None)))
graph.close()