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Python Query.count方法代码示例

本文整理汇总了Python中querybuilder.query.Query.count方法的典型用法代码示例。如果您正苦于以下问题:Python Query.count方法的具体用法?Python Query.count怎么用?Python Query.count使用的例子?那么恭喜您, 这里精选的方法代码示例或许可以为您提供帮助。您也可以进一步了解该方法所在querybuilder.query.Query的用法示例。


在下文中一共展示了Query.count方法的3个代码示例,这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞,您的评价将有助于系统推荐出更棒的Python代码示例。

示例1: test_count

# 需要导入模块: from querybuilder.query import Query [as 别名]
# 或者: from querybuilder.query.Query import count [as 别名]
 def test_count(self):
     query = Query().from_table(
         User
     )
     received = query.count()
     expected = len(User.objects.all())
     self.assertEqual(
         received,
         expected,
         'Expected {0} but received {1}'.format(
             expected,
             received
         )
     )
开发者ID:AlexandrPaveluc,项目名称:django-query-builder,代码行数:16,代码来源:aggregate_tests.py

示例2: freeTable

# 需要导入模块: from querybuilder.query import Query [as 别名]
# 或者: from querybuilder.query.Query import count [as 别名]
def freeTable(tableid) :
   # Get all client tokens associated to the table (id) and count them
   query = Query().from_table('client').where(tableid_id=tableid)
   # SELECT * FROM client WEHRE tableid_id = tableid
   client = query.select()
   clientCount = query.count()
   
   # Count when a payment has been done with the client token
   paymentCount = 0
   for token in client :
      query = Query().from_table('payment').where(token_id=token['id'])
      payment = query.select()
      if payment:
         paymentCount = paymentCount + 1
   return clientCount == paymentCount
开发者ID:JoPowell,项目名称:LINGI2172-Databases,代码行数:17,代码来源:step3.py

示例3: test_count

# 需要导入模块: from querybuilder.query import Query [as 别名]
# 或者: from querybuilder.query.Query import count [as 别名]
    def test_count(self):
        query = Query().from_table(
            User,
            ['one', 'two']
        ).order_by('id')
        received = query.count()
        expected = len(User.objects.all())
        self.assertEqual(
            received,
            expected,
            'Expected {0} but received {1}'.format(
                expected,
                received
            )
        )
        self.assertEqual(query.get_count_query().get_sql(), 'SELECT COUNT(tests_user.*) AS all_count FROM tests_user')

        # Make sure the copy didn't modify the original
        self.assertEqual(len(query.tables[0].fields), 2)
        self.assertEqual(len(query.sorters), 1)
开发者ID:isotoma,项目名称:django-query-builder,代码行数:22,代码来源:aggregate_tests.py


注:本文中的querybuilder.query.Query.count方法示例由纯净天空整理自Github/MSDocs等开源代码及文档管理平台,相关代码片段筛选自各路编程大神贡献的开源项目,源码版权归原作者所有,传播和使用请参考对应项目的License;未经允许,请勿转载。