本文整理汇总了Python中qr_mumps.solver.QRMUMPSSolver.minimum_norm方法的典型用法代码示例。如果您正苦于以下问题：Python QRMUMPSSolver.minimum_norm方法的具体用法？Python QRMUMPSSolver.minimum_norm怎么用？Python QRMUMPSSolver.minimum_norm使用的例子？那么恭喜您, 这里精选的方法代码示例或许可以为您提供帮助。您也可以进一步了解该方法所在类qr_mumps.solver.QRMUMPSSolver的用法示例。
在下文中一共展示了QRMUMPSSolver.minimum_norm方法的4个代码示例，这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞，您的评价将有助于系统推荐出更棒的Python代码示例。
示例1: test_dense_minimum_norm_multiple_rhs
# 需要导入模块: from qr_mumps.solver import QRMUMPSSolver [as 别名]
# 或者: from qr_mumps.solver.QRMUMPSSolver import minimum_norm [as 别名]
def test_dense_minimum_norm_multiple_rhs(self):
solver = QRMUMPSSolver(self.A, verbose=False)
B = np.ones([self.m, 3], dtype=np.float64)
B[:, 1] = 2 * B[:, 1]
B[:, 2] = 3 * B[:, 2]
with pytest.raises(RuntimeError):
solver = solver.minimum_norm(B)示例2: test_dense_minimum_norm_multiple_rhs
# 需要导入模块: from qr_mumps.solver import QRMUMPSSolver [as 别名]
# 或者: from qr_mumps.solver.QRMUMPSSolver import minimum_norm [as 别名]
def test_dense_minimum_norm_multiple_rhs(self):
solver = QRMUMPSSolver((self.m, self.n, self.arow, self.acol, self.aval), verbose=False)
B = np.ones([self.n, 3], dtype=np.complex64)
B[: ,1] = 2 * B[:,1]
B[: ,2] = 3 * B[:,2]
rhs = np.dot(self.A, B)
with pytest.raises(RuntimeError):
x = solver.minimum_norm(rhs)示例3: test_dense_minimum_norm_wrong_size_rhs
# 需要导入模块: from qr_mumps.solver import QRMUMPSSolver [as 别名]
# 或者: from qr_mumps.solver.QRMUMPSSolver import minimum_norm [as 别名]
def test_dense_minimum_norm_wrong_size_rhs(self):
solver = QRMUMPSSolver(self.A, verbose=False)
rhs = np.ones([self.m + 1, 1], dtype=np.float64)
with pytest.raises(ValueError):
x = solver.minimum_norm(rhs)示例4: test_dense_minimum_norm_wrong_size_rhs
# 需要导入模块: from qr_mumps.solver import QRMUMPSSolver [as 别名]
# 或者: from qr_mumps.solver.QRMUMPSSolver import minimum_norm [as 别名]
def test_dense_minimum_norm_wrong_size_rhs(self):
solver = QRMUMPSSolver((self.m, self.n, self.arow, self.acol, self.aval), verbose=False)
rhs = np.ones([self.m+1, 1], dtype=np.float32)
with pytest.raises(ValueError):
x = solver.minimum_norm(rhs)