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Python ConcreteModel.t方法代码示例

本文整理汇总了Python中pyomo.core.ConcreteModel.t方法的典型用法代码示例。如果您正苦于以下问题:Python ConcreteModel.t方法的具体用法?Python ConcreteModel.t怎么用?Python ConcreteModel.t使用的例子?那么恭喜您, 这里精选的方法代码示例或许可以为您提供帮助。您也可以进一步了解该方法所在pyomo.core.ConcreteModel的用法示例。


在下文中一共展示了ConcreteModel.t方法的2个代码示例,这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞,您的评价将有助于系统推荐出更棒的Python代码示例。

示例1: makeTwoTermMultiIndexedDisjunction

# 需要导入模块: from pyomo.core import ConcreteModel [as 别名]
# 或者: from pyomo.core.ConcreteModel import t [as 别名]
def makeTwoTermMultiIndexedDisjunction():
    m = ConcreteModel()
    m.s = Set(initialize=[1, 2])
    m.t = Set(initialize=['A', 'B'])
    m.a = Var(m.s, m.t, bounds=(2, 7))

    def d_rule(disjunct, flag, s, t):
        m = disjunct.model()
        if flag:
            disjunct.c = Constraint(expr=m.a[s, t] == 0)
        else:
            disjunct.c = Constraint(expr=m.a[s, t] >= 5)
    m.disjunct = Disjunct([0, 1], m.s, m.t, rule=d_rule)

    def disj_rule(m, s, t):
        return [m.disjunct[0, s, t], m.disjunct[1, s, t]]
    m.disjunction = Disjunction(m.s, m.t, rule=disj_rule)
    return m
开发者ID:Pyomo,项目名称:pyomo,代码行数:20,代码来源:models.py

示例2: criticalityCheck

# 需要导入模块: from pyomo.core import ConcreteModel [as 别名]
# 或者: from pyomo.core.ConcreteModel import t [as 别名]
    def criticalityCheck(self, x, y, z, rom_params, worstcase=False, M=[0.0]):

        model = self.model

        self.setVarValue(x=x,y=y,z=z)
        self.setBound(x, y, z, 1e10)
        self.deactiveExtraConObj()
        self.activateRomCons(x, rom_params)

        optGJH = SolverFactory('contrib.gjh')
        optGJH.solve(model, tee=False, symbolic_solver_labels=True)
        g, J, varlist, conlist = model._gjh_info

        l = ConcreteModel()
        l.v = Var(varlist, domain=Reals)
        for i in varlist:
            #dummy = model.find_component(i)
            l.v[i] = 0.0
            l.v[i].setlb(-1.0)
            l.v[i].setub(1.0)
        if worstcase:
            if M.all() == 0.0:
                print('WARNING: worstcase criticality was requested but Jacobian error bound is zero')
            l.t = Var(range(0, self.ly), domain=Reals)
            for i in range(0, self.ly):
                l.t[i].setlb(-M[i])
                l.t[i].setub(M[i])

        def linConMaker(l, i):
            # i should be range(len(conlist) - 1)
            # because last element of conlist is the objective
            con_i = model.find_component(conlist[i])

            isEquality = con_i.equality

            isROM = False

            if conlist[i][:7] == '.' + self.TRF.name + '.rom':
                isROM = True
                romIndex = int(filter(str.isdigit, conlist[i]))

            # This is very inefficient
            # Fix this later if these problems get big
            # This is the ith row of J times v
            Jv = sum(x[2] * l.v[varlist[x[1]]] for x in J if x[0] == i)

            if isEquality:
                if worstcase and isROM:
                    return Jv + l.t[romIndex] == 0
                else:
                    return Jv == 0
            else:
                lo = con_i.lower
                up = con_i.upper
                if lo is not None:
                    level = lo.value - con_i.lslack()
                    if up is not None:
                        return (lo.value <= level + Jv <= up.value)
                    else:
                        return (lo.value <= level + Jv)
                elif up is not None:
                    level = up.value - con_i.uslack()
                    return (level + Jv <= up.value)
                else:
                    raise Exception(
                        "This constraint seems to be neither equality or inequality: " + conlist(i))


        l.lincons = Constraint(range(len(conlist)-1), rule=linConMaker)

        l.obj = Objective(expr=sum(x[1] * l.v[varlist[x[0]]] for x in g))

        # Calculate gradient norm for scaling purposes
        gfnorm = sqrt(sum(x[1]**2 for x in g))


        opt = SolverFactory(self.config.solver)
        opt.options.update(self.config.solver_options)
        #opt.options['halt_on_ampl_error'] = 'yes'
        #opt.options['max_iter'] = 5000
        results = opt.solve(
            l, keepfiles=self.keepfiles, tee=self.stream_solver)

        if ((results.solver.status == SolverStatus.ok)
                and (results.solver.termination_condition == TerminationCondition.optimal)):
            l.solutions.load_from(results)
            if gfnorm > 1:
                return True, abs(l.obj())/gfnorm
            else:
                return True, abs(l.obj())
        else:
            print("Waring: Crticality check fails with solver Status: " + str(results.solver.status))
            print("And Termination Conditions: " + str(results.solver.termination_condition))
            return False, infinity
开发者ID:Pyomo,项目名称:pyomo,代码行数:96,代码来源:PyomoInterface.py


注:本文中的pyomo.core.ConcreteModel.t方法示例由纯净天空整理自Github/MSDocs等开源代码及文档管理平台,相关代码片段筛选自各路编程大神贡献的开源项目,源码版权归原作者所有,传播和使用请参考对应项目的License;未经允许,请勿转载。