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Python LBoard.plyCount方法代码示例

本文整理汇总了Python中pychess.Utils.lutils.LBoard.LBoard.plyCount方法的典型用法代码示例。如果您正苦于以下问题:Python LBoard.plyCount方法的具体用法?Python LBoard.plyCount怎么用?Python LBoard.plyCount使用的例子?那么恭喜您, 这里精选的方法代码示例或许可以为您提供帮助。您也可以进一步了解该方法所在pychess.Utils.lutils.LBoard.LBoard的用法示例。


在下文中一共展示了LBoard.plyCount方法的1个代码示例,这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞,您的评价将有助于系统推荐出更棒的Python代码示例。

示例1: add_variation

# 需要导入模块: from pychess.Utils.lutils.LBoard import LBoard [as 别名]
# 或者: from pychess.Utils.lutils.LBoard.LBoard import plyCount [as 别名]
    def add_variation(self, board, moves, comment="", score=""):
        board0 = board
        board = board0.clone()
        board.board.prev = None

        variation = [board]

        for move in moves:
            new = board.move(move)
            if len(variation) == 1:
                new.board.prev = board0.board
                variation[0].board.next = new.board
            else:
                new.board.prev = board.board
                board.board.next = new.board
            variation.append(new)
            board = new

        if board0.board.next is None:
            # If we are in the latest played board, and want to add a variation
            # we have to add a not played yet board first
            # which can hold the variation as his child
            from pychess.Utils.lutils.LBoard import LBoard

            null_board = LBoard()
            null_board.prev = board0.board
            null_board.plyCount = board0.board.plyCount + 1
            board0.board.next = null_board

        board0.board.next.children.append([board.board for board in variation])

        head = None
        for vari in self.variations:
            if board0 in vari:
                head = vari
                break

        variation[0] = board0
        self.variations.append(head[: board0.ply - self.lowply] + variation)
        self.needsSave = True
        self.emit("variation_added", board0.board.next.children[-1], board0.board.next, comment, score)
        return self.variations[-1]
开发者ID:jholland6843,项目名称:pychess,代码行数:44,代码来源:GameModel.py


注:本文中的pychess.Utils.lutils.LBoard.LBoard.plyCount方法示例由纯净天空整理自Github/MSDocs等开源代码及文档管理平台,相关代码片段筛选自各路编程大神贡献的开源项目,源码版权归原作者所有,传播和使用请参考对应项目的License;未经允许,请勿转载。