当前位置: 首页>>代码示例>>Python>>正文


Python PdfFileReader.fixIndirectObjectXref方法代码示例

本文整理汇总了Python中pyPdf.PdfFileReader.fixIndirectObjectXref方法的典型用法代码示例。如果您正苦于以下问题:Python PdfFileReader.fixIndirectObjectXref方法的具体用法?Python PdfFileReader.fixIndirectObjectXref怎么用?Python PdfFileReader.fixIndirectObjectXref使用的例子?那么恭喜您, 这里精选的方法代码示例或许可以为您提供帮助。您也可以进一步了解该方法所在pyPdf.PdfFileReader的用法示例。


在下文中一共展示了PdfFileReader.fixIndirectObjectXref方法的1个代码示例,这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞,您的评价将有助于系统推荐出更棒的Python代码示例。

示例1: extractAWAMIndicators

# 需要导入模块: from pyPdf import PdfFileReader [as 别名]
# 或者: from pyPdf.PdfFileReader import fixIndirectObjectXref [as 别名]
def extractAWAMIndicators(pdf, password=''):
    """ Check whether the given PDF document is accessible """

    # Takes an optional password which can be used to
    # unlock the document for encrypted documents.
    try:
        pdfobj = PdfFileReader(pdf, password)
        print 'Producer=>',pdfobj.producer
        print 'Creator=>',pdfobj.creator
    except DecryptionFailedException:
        # We are unable to decrypt document.
        # We have got no parsed pdfobj, and cannot do much more,
        # unfortunately... 
        # Tell that the document was not accessible due to encryption, at least
        print "Decryption failed"
        return {'EIAO.A.10.8.1.4.PDF.1.1':{(0, 1): 0}}
    except NotImplementedError:
        # pyPdf only supports algorithm version 1 and 2. 
        # Version 3 and 4 are not yet supported.
        print "Unsupported decryption algorithm."
        return {'EIAO.A.10.8.1.4.PDF.1.1':{(0, 1): 0}}


    try:
        # Fix indirect object references
        pdfobj.fixIndirectObjectXref()

        structTreeRoot=pdfobj.root['/StructTreeRoot'].getObject()
        roleMap=structTreeRoot['/RoleMap'].getObject()
    except (KeyError, ValueError), e:
        roleMap=None
开发者ID:diegofagundes,项目名称:codigoaberto,代码行数:33,代码来源:decrypt.py


注:本文中的pyPdf.PdfFileReader.fixIndirectObjectXref方法示例由纯净天空整理自Github/MSDocs等开源代码及文档管理平台,相关代码片段筛选自各路编程大神贡献的开源项目,源码版权归原作者所有,传播和使用请参考对应项目的License;未经允许,请勿转载。