本文整理汇总了Python中privacyidea.lib.policy.PolicyClass.get_auth_challenge_response方法的典型用法代码示例。如果您正苦于以下问题：Python PolicyClass.get_auth_challenge_response方法的具体用法？Python PolicyClass.get_auth_challenge_response怎么用？Python PolicyClass.get_auth_challenge_response使用的例子？那么恭喜您, 这里精选的方法代码示例或许可以为您提供帮助。您也可以进一步了解该方法所在类privacyidea.lib.policy.PolicyClass的用法示例。
在下文中一共展示了PolicyClass.get_auth_challenge_response方法的1个代码示例，这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞，您的评价将有助于系统推荐出更棒的Python代码示例。
示例1: check_standard
# 需要导入模块: from privacyidea.lib.policy import PolicyClass [as 别名]
# 或者: from privacyidea.lib.policy.PolicyClass import get_auth_challenge_response [as 别名]
def check_standard(self, passw, user, options=None):
'''
do a standard verification, as we are not in a challengeResponse mode
the upper interfaces expect in the success the otp counter or at
least 0 if we have a success. A -1 identifies an error
:param passw: the password, which should be checked
:param options: dict with additional request parameters
:return: tuple of matching otpcounter and a potential reply
'''
otp_count = -1
pin_match = False
reply = None
ttype = self.token.getType()
## fallback eg. in case of check_s, which does not provide a user
if user is None:
user = privacyidea.lib.token.get_token_owner(self.token)
Policy = PolicyClass(request, config, c,
get_privacyIDEA_config())
support_challenge_response = Policy.get_auth_challenge_response(user, ttype)
## special handling for tokens, who support only challenge modes
## like the sms, email or ocra2 token
challenge_mode_only = False
mode = self.token.mode
if type(mode) == list and len(mode) == 1 and mode[0] == "challenge":
challenge_mode_only = True
## the support_challenge_response is overruled, if the token
## supports only challenge processing
if challenge_mode_only == True:
support_challenge_response = True
try:
## call the token authentication
(pin_match, otp_count, reply) = self.token.authenticate(passw, user,
options=options)
except Exception as exx:
if (support_challenge_response == True and
self.token.is_challenge_request(passw, user, options=options)):
LOG.info("Retry on base of a challenge request:")
pin_match = False
otp_count = -1
else:
LOG.error("%s" % (traceback.format_exc()))
raise Exception(exx)
if otp_count < 0 or pin_match == False:
if (support_challenge_response == True and
self.token.isActive() and
self.token.is_challenge_request(passw, user, options=options)):
# we are in createChallenge mode
# fix for #12413:
# - moved the create_challenge call to the checkTokenList!
## after all tokens are processed and only one is challengeing
# (_res, reply) = create_challenge(self.token, options=options)
self.challenge_token.append(self.token)
if len(self.challenge_token) == 0:
if otp_count >= 0:
self.valid_token.append(self.token)
elif pin_match is True:
self.pin_matching_token.append(self.token)
else:
self.invalid_token.append(self.token)
return (otp_count, reply)